Calculus Examples

$y = \ln (\sqrt{x + 6})$

Step 1

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{x + 6}$ as ${(x + 6)}^{\frac{1}{2}}$ .

$\frac{d}{d x} [\ln ({(x + 6)}^{\frac{1}{2}})]$

Step 2

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = \ln (x)$ and $g (x) = {(x + 6)}^{\frac{1}{2}}$ .

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Step 2.1

To apply the Chain Rule, set $u_{1}$ as ${(x + 6)}^{\frac{1}{2}}$ .

$\frac{d}{d u_{1}} [\ln (u_{1})] \frac{d}{d x} [{(x + 6)}^{\frac{1}{2}}]$

Step 2.2

The derivative of $\ln (u_{1})$ with respect to $u_{1}$ is $\frac{1}{u_{1}}$ .

$\frac{1}{u_{1}} \frac{d}{d x} [{(x + 6)}^{\frac{1}{2}}]$

Step 2.3

Replace all occurrences of $u_{1}$ with ${(x + 6)}^{\frac{1}{2}}$ .

$\frac{1}{{(x + 6)}^{\frac{1}{2}}} \frac{d}{d x} [{(x + 6)}^{\frac{1}{2}}]$

Step 3

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = x^{\frac{1}{2}}$ and $g (x) = x + 6$ .

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Step 3.1

To apply the Chain Rule, set $u_{2}$ as $x + 6$ .

$\frac{1}{{(x + 6)}^{\frac{1}{2}}} (\frac{d}{d u_{2}} [{u_{2}}^{\frac{1}{2}}] \frac{d}{d x} [x + 6])$

Step 3.2

Differentiate using the Power Rule which states that $\frac{d}{d u_{2}} [{u_{2}}^{n}]$ is $n {u_{2}}^{n - 1}$ where $n = \frac{1}{2}$ .

$\frac{1}{{(x + 6)}^{\frac{1}{2}}} (\frac{1}{2} {u_{2}}^{\frac{1}{2} - 1} \frac{d}{d x} [x + 6])$

Step 3.3

Replace all occurrences of $u_{2}$ with $x + 6$ .

$\frac{1}{{(x + 6)}^{\frac{1}{2}}} (\frac{1}{2} {(x + 6)}^{\frac{1}{2} - 1} \frac{d}{d x} [x + 6])$

Step 4

To write $- 1$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$\frac{1}{{(x + 6)}^{\frac{1}{2}}} (\frac{1}{2} {(x + 6)}^{\frac{1}{2} - 1 \cdot \frac{2}{2}} \frac{d}{d x} [x + 6])$

Step 5

Combine $- 1$ and $\frac{2}{2}$ .

$\frac{1}{{(x + 6)}^{\frac{1}{2}}} (\frac{1}{2} {(x + 6)}^{\frac{1}{2} + \frac{- 1 \cdot 2}{2}} \frac{d}{d x} [x + 6])$

Step 6

Combine the numerators over the common denominator.

$\frac{1}{{(x + 6)}^{\frac{1}{2}}} (\frac{1}{2} {(x + 6)}^{\frac{1 - 1 \cdot 2}{2}} \frac{d}{d x} [x + 6])$

Step 7

Simplify the numerator.

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Step 7.1

Multiply $- 1$ by $2$ .

$\frac{1}{{(x + 6)}^{\frac{1}{2}}} (\frac{1}{2} {(x + 6)}^{\frac{1 - 2}{2}} \frac{d}{d x} [x + 6])$

Step 7.2

Subtract $2$ from $1$ .

$\frac{1}{{(x + 6)}^{\frac{1}{2}}} (\frac{1}{2} {(x + 6)}^{\frac{- 1}{2}} \frac{d}{d x} [x + 6])$

Step 8

Move the negative in front of the fraction.

$\frac{1}{{(x + 6)}^{\frac{1}{2}}} (\frac{1}{2} {(x + 6)}^{- \frac{1}{2}} \frac{d}{d x} [x + 6])$

Step 9

Combine $\frac{1}{2}$ and ${(x + 6)}^{- \frac{1}{2}}$ .

$\frac{1}{{(x + 6)}^{\frac{1}{2}}} (\frac{{(x + 6)}^{- \frac{1}{2}}}{2} \frac{d}{d x} [x + 6])$

Step 10

Move ${(x + 6)}^{- \frac{1}{2}}$ to the denominator using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$\frac{1}{{(x + 6)}^{\frac{1}{2}}} (\frac{1}{2 {(x + 6)}^{\frac{1}{2}}} \frac{d}{d x} [x + 6])$

Step 11

Multiply $\frac{1}{2 {(x + 6)}^{\frac{1}{2}}}$ by $\frac{1}{{(x + 6)}^{\frac{1}{2}}}$ .

$\frac{1}{2 {(x + 6)}^{\frac{1}{2}} {(x + 6)}^{\frac{1}{2}}} \frac{d}{d x} [x + 6]$

Step 12

Multiply ${(x + 6)}^{\frac{1}{2}}$ by ${(x + 6)}^{\frac{1}{2}}$ by adding the exponents.

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Step 12.1

Move ${(x + 6)}^{\frac{1}{2}}$ .

$\frac{1}{2 ({(x + 6)}^{\frac{1}{2}} {(x + 6)}^{\frac{1}{2}})} \frac{d}{d x} [x + 6]$

Step 12.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{1}{2 {(x + 6)}^{\frac{1}{2} + \frac{1}{2}}} \frac{d}{d x} [x + 6]$

Step 12.3

Combine the numerators over the common denominator.

$\frac{1}{2 {(x + 6)}^{\frac{1 + 1}{2}}} \frac{d}{d x} [x + 6]$

Step 12.4

Add $1$ and $1$ .

$\frac{1}{2 {(x + 6)}^{\frac{2}{2}}} \frac{d}{d x} [x + 6]$

Step 12.5

Divide $2$ by $2$ .

$\frac{1}{2 {(x + 6)}^{1}} \frac{d}{d x} [x + 6]$

Step 13

Simplify $2 {(x + 6)}^{1}$ .

$\frac{1}{2 (x + 6)} \frac{d}{d x} [x + 6]$

Step 14

By the Sum Rule, the derivative of $x + 6$ with respect to $x$ is $\frac{d}{d x} [x] + \frac{d}{d x} [6]$ .

$\frac{1}{2 (x + 6)} (\frac{d}{d x} [x] + \frac{d}{d x} [6])$

Step 15

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$\frac{1}{2 (x + 6)} (1 + \frac{d}{d x} [6])$

Step 16

Since $6$ is constant with respect to $x$ , the derivative of $6$ with respect to $x$ is $0$ .

$\frac{1}{2 (x + 6)} (1 + 0)$

Step 17

Simplify the expression.

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Step 17.1

Add $1$ and $0$ .

$\frac{1}{2 (x + 6)} \cdot 1$

Step 17.2

Multiply $\frac{1}{2 (x + 6)}$ by $1$ .

$\frac{1}{2 (x + 6)}$