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Calculus Examples
limx→2x2+3x-10x2-4limx→2x2+3x−10x2−4
Step 1
Step 1.1
Evaluate the limit of the numerator and the limit of the denominator.
Step 1.1.1
Take the limit of the numerator and the limit of the denominator.
limx→2x2+3x-10limx→2x2-4
Step 1.1.2
Evaluate the limit of the numerator.
Step 1.1.2.1
Split the limit using the Sum of Limits Rule on the limit as x approaches 2.
limx→2x2+limx→23x-limx→210limx→2x2-4
Step 1.1.2.2
Move the exponent 2 from x2 outside the limit using the Limits Power Rule.
(limx→2x)2+limx→23x-limx→210limx→2x2-4
Step 1.1.2.3
Move the term 3 outside of the limit because it is constant with respect to x.
(limx→2x)2+3limx→2x-limx→210limx→2x2-4
Step 1.1.2.4
Evaluate the limit of 10 which is constant as x approaches 2.
(limx→2x)2+3limx→2x-1⋅10limx→2x2-4
Step 1.1.2.5
Evaluate the limits by plugging in 2 for all occurrences of x.
Step 1.1.2.5.1
Evaluate the limit of x by plugging in 2 for x.
22+3limx→2x-1⋅10limx→2x2-4
Step 1.1.2.5.2
Evaluate the limit of x by plugging in 2 for x.
22+3⋅2-1⋅10limx→2x2-4
22+3⋅2-1⋅10limx→2x2-4
Step 1.1.2.6
Simplify the answer.
Step 1.1.2.6.1
Simplify each term.
Step 1.1.2.6.1.1
Raise 2 to the power of 2.
4+3⋅2-1⋅10limx→2x2-4
Step 1.1.2.6.1.2
Multiply 3 by 2.
4+6-1⋅10limx→2x2-4
Step 1.1.2.6.1.3
Multiply -1 by 10.
4+6-10limx→2x2-4
4+6-10limx→2x2-4
Step 1.1.2.6.2
Add 4 and 6.
10-10limx→2x2-4
Step 1.1.2.6.3
Subtract 10 from 10.
0limx→2x2-4
0limx→2x2-4
0limx→2x2-4
Step 1.1.3
Evaluate the limit of the denominator.
Step 1.1.3.1
Evaluate the limit.
Step 1.1.3.1.1
Split the limit using the Sum of Limits Rule on the limit as x approaches 2.
0limx→2x2-limx→24
Step 1.1.3.1.2
Move the exponent 2 from x2 outside the limit using the Limits Power Rule.
0(limx→2x)2-limx→24
Step 1.1.3.1.3
Evaluate the limit of 4 which is constant as x approaches 2.
0(limx→2x)2-1⋅4
0(limx→2x)2-1⋅4
Step 1.1.3.2
Evaluate the limit of x by plugging in 2 for x.
022-1⋅4
Step 1.1.3.3
Simplify the answer.
Step 1.1.3.3.1
Simplify each term.
Step 1.1.3.3.1.1
Raise 2 to the power of 2.
04-1⋅4
Step 1.1.3.3.1.2
Multiply -1 by 4.
04-4
04-4
Step 1.1.3.3.2
Subtract 4 from 4.
00
Step 1.1.3.3.3
The expression contains a division by 0. The expression is undefined.
Undefined
00
Step 1.1.3.4
The expression contains a division by 0. The expression is undefined.
Undefined
00
Step 1.1.4
The expression contains a division by 0. The expression is undefined.
Undefined
00
Step 1.2
Since 00 is of indeterminate form, apply L'Hospital's Rule. L'Hospital's Rule states that the limit of a quotient of functions is equal to the limit of the quotient of their derivatives.
limx→2x2+3x-10x2-4=limx→2ddx[x2+3x-10]ddx[x2-4]
Step 1.3
Find the derivative of the numerator and denominator.
Step 1.3.1
Differentiate the numerator and denominator.
limx→2ddx[x2+3x-10]ddx[x2-4]
Step 1.3.2
By the Sum Rule, the derivative of x2+3x-10 with respect to x is ddx[x2]+ddx[3x]+ddx[-10].
limx→2ddx[x2]+ddx[3x]+ddx[-10]ddx[x2-4]
Step 1.3.3
Differentiate using the Power Rule which states that ddx[xn] is nxn-1 where n=2.
limx→22x+ddx[3x]+ddx[-10]ddx[x2-4]
Step 1.3.4
Evaluate ddx[3x].
Step 1.3.4.1
Since 3 is constant with respect to x, the derivative of 3x with respect to x is 3ddx[x].
limx→22x+3ddx[x]+ddx[-10]ddx[x2-4]
Step 1.3.4.2
Differentiate using the Power Rule which states that ddx[xn] is nxn-1 where n=1.
limx→22x+3⋅1+ddx[-10]ddx[x2-4]
Step 1.3.4.3
Multiply 3 by 1.
limx→22x+3+ddx[-10]ddx[x2-4]
limx→22x+3+ddx[-10]ddx[x2-4]
Step 1.3.5
Since -10 is constant with respect to x, the derivative of -10 with respect to x is 0.
limx→22x+3+0ddx[x2-4]
Step 1.3.6
Add 2x+3 and 0.
limx→22x+3ddx[x2-4]
Step 1.3.7
By the Sum Rule, the derivative of x2-4 with respect to x is ddx[x2]+ddx[-4].
limx→22x+3ddx[x2]+ddx[-4]
Step 1.3.8
Differentiate using the Power Rule which states that ddx[xn] is nxn-1 where n=2.
limx→22x+32x+ddx[-4]
Step 1.3.9
Since -4 is constant with respect to x, the derivative of -4 with respect to x is 0.
limx→22x+32x+0
Step 1.3.10
Add 2x and 0.
limx→22x+32x
limx→22x+32x
limx→22x+32x
Step 2
Step 2.1
Move the term 12 outside of the limit because it is constant with respect to x.
12limx→22x+3x
Step 2.2
Split the limit using the Limits Quotient Rule on the limit as x approaches 2.
12⋅limx→22x+3limx→2x
Step 2.3
Split the limit using the Sum of Limits Rule on the limit as x approaches 2.
12⋅limx→22x+limx→23limx→2x
Step 2.4
Move the term 2 outside of the limit because it is constant with respect to x.
12⋅2limx→2x+limx→23limx→2x
Step 2.5
Evaluate the limit of 3 which is constant as x approaches 2.
12⋅2limx→2x+3limx→2x
12⋅2limx→2x+3limx→2x
Step 3
Step 3.1
Evaluate the limit of x by plugging in 2 for x.
12⋅2⋅2+3limx→2x
Step 3.2
Evaluate the limit of x by plugging in 2 for x.
12⋅2⋅2+32
12⋅2⋅2+32
Step 4
Step 4.1
Simplify the numerator.
Step 4.1.1
Multiply 2 by 2.
12⋅4+32
Step 4.1.2
Add 4 and 3.
12⋅72
12⋅72
Step 4.2
Multiply 12⋅72.
Step 4.2.1
Multiply 12 by 72.
72⋅2
Step 4.2.2
Multiply 2 by 2.
74
74
74
Step 5
The result can be shown in multiple forms.
Exact Form:
74
Decimal Form:
1.75