Calculus Examples

$f (x) = x^{2} + 4 x - 5$

Step 1

Consider the difference quotient formula.

$\frac{f (x + h) - f (x)}{h}$

Step 2

Find the components of the definition.

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Step 2.1

Evaluate the function at $x = x + h$ .

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Step 2.1.1

Replace the variable $x$ with $x + h$ in the expression.

$f (x + h) = {(x + h)}^{2} + 4 (x + h) - 5$

Step 2.1.2

Simplify the result.

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Step 2.1.2.1

Simplify each term.

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Step 2.1.2.1.1

Rewrite ${(x + h)}^{2}$ as $(x + h) (x + h)$ .

$f (x + h) = (x + h) (x + h) + 4 (x + h) - 5$

Step 2.1.2.1.2

Expand $(x + h) (x + h)$ using the FOIL Method.

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Step 2.1.2.1.2.1

Apply the distributive property.

$f (x + h) = x (x + h) + h (x + h) + 4 (x + h) - 5$

Step 2.1.2.1.2.2

Apply the distributive property.

$f (x + h) = x \cdot x + x h + h (x + h) + 4 (x + h) - 5$

Step 2.1.2.1.2.3

Apply the distributive property.

$f (x + h) = x \cdot x + x h + h x + h \cdot h + 4 (x + h) - 5$

Step 2.1.2.1.3

Simplify and combine like terms.

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Step 2.1.2.1.3.1

Simplify each term.

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Step 2.1.2.1.3.1.1

Multiply $x$ by $x$ .

$f (x + h) = x^{2} + x h + h x + h \cdot h + 4 (x + h) - 5$

Step 2.1.2.1.3.1.2

Multiply $h$ by $h$ .

$f (x + h) = x^{2} + x h + h x + h^{2} + 4 (x + h) - 5$

Step 2.1.2.1.3.2

Add $x h$ and $h x$ .

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Step 2.1.2.1.3.2.1

Reorder $x$ and $h$ .

$f (x + h) = x^{2} + h x + h x + h^{2} + 4 (x + h) - 5$

Step 2.1.2.1.3.2.2

Add $h x$ and $h x$ .

$f (x + h) = x^{2} + 2 h x + h^{2} + 4 (x + h) - 5$

Step 2.1.2.1.4

Apply the distributive property.

$f (x + h) = x^{2} + 2 h x + h^{2} + 4 x + 4 h - 5$

Step 2.1.2.2

The final answer is $x^{2} + 2 h x + h^{2} + 4 x + 4 h - 5$ .

$x^{2} + 2 h x + h^{2} + 4 x + 4 h - 5$

Step 2.2

Reorder.

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Step 2.2.1

Move $4 x$ .

$x^{2} + 2 h x + h^{2} + 4 h + 4 x - 5$

Step 2.2.2

Move $x^{2}$ .

$2 h x + h^{2} + x^{2} + 4 h + 4 x - 5$

Step 2.2.3

Reorder $2 h x$ and $h^{2}$ .

$h^{2} + 2 h x + x^{2} + 4 h + 4 x - 5$

Step 2.3

Find the components of the definition.

$f (x + h) = h^{2} + 2 h x + x^{2} + 4 h + 4 x - 5$

$f (x) = x^{2} + 4 x - 5$

$f (x + h) = h^{2} + 2 h x + x^{2} + 4 h + 4 x - 5$

$f (x) = x^{2} + 4 x - 5$

Step 3

Plug in the components.

$\frac{f (x + h) - f (x)}{h} = \frac{h^{2} + 2 h x + x^{2} + 4 h + 4 x - 5 - (x^{2} + 4 x - 5)}{h}$

Step 4

Simplify.

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Step 4.1

Simplify the numerator.

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Step 4.1.1

Apply the distributive property.

$\frac{h^{2} + 2 h x + x^{2} + 4 h + 4 x - 5 - x^{2} - (4 x) - - 5}{h}$

Step 4.1.2

Simplify.

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Step 4.1.2.1

Multiply $4$ by $- 1$ .

$\frac{h^{2} + 2 h x + x^{2} + 4 h + 4 x - 5 - x^{2} - 4 x - - 5}{h}$

Step 4.1.2.2

Multiply $- 1$ by $- 5$ .

$\frac{h^{2} + 2 h x + x^{2} + 4 h + 4 x - 5 - x^{2} - 4 x + 5}{h}$

Step 4.1.3

Subtract $x^{2}$ from $x^{2}$ .

$\frac{h^{2} + 2 h x + 4 h + 4 x - 5 + 0 - 4 x + 5}{h}$

Step 4.1.4

Add $h^{2}$ and $0$ .

$\frac{h^{2} + 2 h x + 4 h + 4 x - 5 - 4 x + 5}{h}$

Step 4.1.5

Subtract $4 x$ from $4 x$ .

$\frac{h^{2} + 2 h x + 4 h + 0 - 5 + 5}{h}$

Step 4.1.6

Add $h^{2}$ and $0$ .

$\frac{h^{2} + 2 h x + 4 h - 5 + 5}{h}$

Step 4.1.7

Add $- 5$ and $5$ .

$\frac{h^{2} + 2 h x + 4 h + 0}{h}$

Step 4.1.8

Add $h^{2} + 2 h x + 4 h$ and $0$ .

$\frac{h^{2} + 2 h x + 4 h}{h}$

Step 4.1.9

Factor $h$ out of $h^{2} + 2 h x + 4 h$ .

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Step 4.1.9.1

Factor $h$ out of $h^{2}$ .

$\frac{h \cdot h + 2 h x + 4 h}{h}$

Step 4.1.9.2

Factor $h$ out of $2 h x$ .

$\frac{h (h) + h (2 x) + 4 h}{h}$

Step 4.1.9.3

Factor $h$ out of $4 h$ .

$\frac{h (h) + h (2 x) + h \cdot 4}{h}$

Step 4.1.9.4

Factor $h$ out of $h (h) + h (2 x)$ .

$\frac{h (h + 2 x) + h \cdot 4}{h}$

Step 4.1.9.5

Factor $h$ out of $h (h + 2 x) + h \cdot 4$ .

$\frac{h (h + 2 x + 4)}{h}$

Step 4.2

Reduce the expression by cancelling the common factors.

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Step 4.2.1

Cancel the common factor of $h$ .

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Step 4.2.1.1

Cancel the common factor.

$\frac{h (h + 2 x + 4)}{h}$

Step 4.2.1.2

Divide $h + 2 x + 4$ by $1$ .

$h + 2 x + 4$

Step 4.2.2

Reorder $h$ and $2 x$ .

$2 x + h + 4$

Step 5