Calculus Examples

$f (x) = \frac{9}{\sqrt{x}}$

Step 1

The function $F (x)$ can be found by finding the indefinite integral of the derivative $f (x)$ .

$F (x) = \int f (x) d x$

Step 2

Set up the integral to solve.

$F (x) = \int \frac{9}{\sqrt{x}} d x$

Step 3

Since $9$ is constant with respect to $x$ , move $9$ out of the integral.

$9 \int \frac{1}{\sqrt{x}} d x$

Step 4

Apply basic rules of exponents.

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Step 4.1

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{x}$ as $x^{\frac{1}{2}}$ .

$9 \int \frac{1}{x^{\frac{1}{2}}} d x$

Step 4.2

Move $x^{\frac{1}{2}}$ out of the denominator by raising it to the $- 1$ power.

$9 \int {(x^{\frac{1}{2}})}^{- 1} d x$

Step 4.3

Multiply the exponents in ${(x^{\frac{1}{2}})}^{- 1}$ .

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Step 4.3.1

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$9 \int x^{\frac{1}{2} \cdot - 1} d x$

Step 4.3.2

Combine $\frac{1}{2}$ and $- 1$ .

$9 \int x^{\frac{- 1}{2}} d x$

Step 4.3.3

Move the negative in front of the fraction.

$9 \int x^{- \frac{1}{2}} d x$

Step 5

By the Power Rule, the integral of $x^{- \frac{1}{2}}$ with respect to $x$ is $2 x^{\frac{1}{2}}$ .

$9 (2 x^{\frac{1}{2}} + C)$

Step 6

Simplify the answer.

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Step 6.1

Rewrite $9 (2 x^{\frac{1}{2}} + C)$ as $9 \cdot 2 x^{\frac{1}{2}} + C$ .

$9 \cdot 2 x^{\frac{1}{2}} + C$

Step 6.2

Multiply $9$ by $2$ .

$18 x^{\frac{1}{2}} + C$

Step 7

The answer is the antiderivative of the function $f (x) = \frac{9}{\sqrt{x}}$ .

$F (x) =$ $18 x^{\frac{1}{2}} + C$