Calculus Examples

$g (x) = \sqrt[3]{2 t}$

Step 1

Simplify with factoring out.

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Step 1.1

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt[3]{2 t}$ as ${(2 t)}^{\frac{1}{3}}$ .

$\frac{d}{d t} [{(2 t)}^{\frac{1}{3}}]$

Step 1.2

Factor $2$ out of $2 t$ .

$\frac{d}{d t} [{(2 (t))}^{\frac{1}{3}}]$

Step 1.3

Apply the product rule to $2 (t)$ .

$\frac{d}{d t} [2^{\frac{1}{3}} t^{\frac{1}{3}}]$

Step 2

Since $2^{\frac{1}{3}}$ is constant with respect to $t$ , the derivative of $2^{\frac{1}{3}} t^{\frac{1}{3}}$ with respect to $t$ is $2^{\frac{1}{3}} \frac{d}{d t} [t^{\frac{1}{3}}]$ .

$2^{\frac{1}{3}} \frac{d}{d t} [t^{\frac{1}{3}}]$

Step 3

Differentiate using the Power Rule which states that $\frac{d}{d t} [t^{n}]$ is $n t^{n - 1}$ where $n = \frac{1}{3}$ .

$2^{\frac{1}{3}} (\frac{1}{3} t^{\frac{1}{3} - 1})$

Step 4

To write $- 1$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$2^{\frac{1}{3}} (\frac{1}{3} t^{\frac{1}{3} - 1 \cdot \frac{3}{3}})$

Step 5

Combine $- 1$ and $\frac{3}{3}$ .

$2^{\frac{1}{3}} (\frac{1}{3} t^{\frac{1}{3} + \frac{- 1 \cdot 3}{3}})$

Step 6

Combine the numerators over the common denominator.

$2^{\frac{1}{3}} (\frac{1}{3} t^{\frac{1 - 1 \cdot 3}{3}})$

Step 7

Simplify the numerator.

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Step 7.1

Multiply $- 1$ by $3$ .

$2^{\frac{1}{3}} (\frac{1}{3} t^{\frac{1 - 3}{3}})$

Step 7.2

Subtract $3$ from $1$ .

$2^{\frac{1}{3}} (\frac{1}{3} t^{\frac{- 2}{3}})$

Step 8

Move the negative in front of the fraction.

$2^{\frac{1}{3}} (\frac{1}{3} t^{- \frac{2}{3}})$

Step 9

Combine $\frac{1}{3}$ and $t^{- \frac{2}{3}}$ .

$2^{\frac{1}{3}} \frac{t^{- \frac{2}{3}}}{3}$

Step 10

Combine $2^{\frac{1}{3}}$ and $\frac{t^{- \frac{2}{3}}}{3}$ .

$\frac{2^{\frac{1}{3}} t^{- \frac{2}{3}}}{3}$

Step 11

Move $t^{- \frac{2}{3}}$ to the denominator using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$\frac{2^{\frac{1}{3}}}{3 t^{\frac{2}{3}}}$