Calculus Examples

$f (x) = x^{4} + 2 x^{2}$ , $a = 1$

Step 1

Consider the function used to find the linearization at $a$ .

$L (x) = f (a) + f' (a) (x - a)$

Step 2

Substitute the value of $a = 1$ into the linearization function.

$L (x) = f (1) + f' (1) (x - 1)$

Step 3

Evaluate $f (1)$ .

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Step 3.1

Replace the variable $x$ with $1$ in the expression.

$f (1) = {(1)}^{4} + 2 {(1)}^{2}$

Step 3.2

Simplify ${(1)}^{4} + 2 {(1)}^{2}$ .

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Step 3.2.1

Remove parentheses.

${(1)}^{4} + 2 {(1)}^{2}$

Step 3.2.2

Simplify each term.

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Step 3.2.2.1

One to any power is one.

$1 + 2 {(1)}^{2}$

Step 3.2.2.2

One to any power is one.

$1 + 2 \cdot 1$

Step 3.2.2.3

Multiply $2$ by $1$ .

$1 + 2$

Step 3.2.3

Add $1$ and $2$ .

$3$

Step 4

Find the derivative and evaluate it at $1$ .

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Step 4.1

Find the derivative of $f (x) = x^{4} + 2 x^{2}$ .

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Step 4.1.1

Differentiate.

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Step 4.1.1.1

By the Sum Rule, the derivative of $x^{4} + 2 x^{2}$ with respect to $x$ is $\frac{d}{d x} [x^{4}] + \frac{d}{d x} [2 x^{2}]$ .

$\frac{d}{d x} [x^{4}] + \frac{d}{d x} [2 x^{2}]$

Step 4.1.1.2

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 4$ .

$4 x^{3} + \frac{d}{d x} [2 x^{2}]$

Step 4.1.2

Evaluate $\frac{d}{d x} [2 x^{2}]$ .

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Step 4.1.2.1

Since $2$ is constant with respect to $x$ , the derivative of $2 x^{2}$ with respect to $x$ is $2 \frac{d}{d x} [x^{2}]$ .

$4 x^{3} + 2 \frac{d}{d x} [x^{2}]$

Step 4.1.2.2

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 2$ .

$4 x^{3} + 2 (2 x)$

Step 4.1.2.3

Multiply $2$ by $2$ .

$4 x^{3} + 4 x$

Step 4.2

Replace the variable $x$ with $1$ in the expression.

$4 {(1)}^{3} + 4 (1)$

Step 4.3

Simplify.

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Step 4.3.1

Simplify each term.

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Step 4.3.1.1

One to any power is one.

$4 \cdot 1 + 4 (1)$

Step 4.3.1.2

Multiply $4$ by $1$ .

$4 + 4 (1)$

Step 4.3.1.3

Multiply $4$ by $1$ .

$4 + 4$

Step 4.3.2

Add $4$ and $4$ .

$8$

Step 5

Substitute the components into the linearization function in order to find the linearization at $a$ .

$L (x) = 3 + 8 (x - 1)$

Step 6

Simplify.

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Step 6.1

Simplify each term.

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Step 6.1.1

Apply the distributive property.

$L (x) = 3 + 8 x + 8 \cdot - 1$

Step 6.1.2

Multiply $8$ by $- 1$ .

$L (x) = 3 + 8 x - 8$

Step 6.2

Subtract $8$ from $3$ .

$L (x) = 8 x - 5$

Step 7