Calculus Examples

$(4, - 3)$ , $- 3 x + 2 y = - 8$ , $6 x - y = 27$

Step 1

Simplify $- 3 \cdot 4 + 2 (- 3)$ .

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Step 1.1

Simplify each term.

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Step 1.1.1

Multiply $- 3$ by $4$ .

$- 12 + 2 (- 3) = - 8$

$6 (4) - (- 3) = 27$

Step 1.1.2

Multiply $2$ by $- 3$ .

$- 12 - 6 = - 8$

$6 (4) - (- 3) = 27$

$- 12 - 6 = - 8$

$6 (4) - (- 3) = 27$

Step 1.2

Subtract $6$ from $- 12$ .

$- 18 = - 8$

$6 (4) - (- 3) = 27$

$- 18 = - 8$

$6 (4) - (- 3) = 27$

Step 2

Since $- 18 \neq - 8$ , there are no solutions.

No solution

Step 3

Simplify $6 (4) - (- 3)$ .

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Step 3.1

Simplify each term.

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Step 3.1.1

Multiply $6$ by $4$ .

$24 - (- 3) = 27$

No solution

Step 3.1.2

Multiply $- 1$ by $- 3$ .

$24 + 3 = 27$

No solution

$24 + 3 = 27$

No solution

Step 3.2

Add $24$ and $3$ .

$27 = 27$

No solution

Step 4

Since $27 = 27$ , the equation will always be true.

No solution

Step 5

The ordered pair is not a solution to the system of equations.

$(4, - 3)$ is not a solution