Calculus Examples

$\frac{lim_{t \to 0} \tan (6 t)}{\sin (2 t)}$

Step 1

Evaluate the limit.

Tap for more steps...

Step 1.1

Move the limit inside the trig function because tangent is continuous.

$\frac{\tan (lim_{t \to 0} 6 t)}{\sin (2 t)}$

Step 1.2

Move the term $6$ outside of the limit because it is constant with respect to $t$ .

$\frac{\tan (6 lim_{t \to 0} t)}{\sin (2 t)}$

Step 2

Evaluate the limit of $t$ by plugging in $0$ for $t$ .

$\frac{\tan (6 \cdot 0)}{\sin (2 t)}$

Step 3

Simplify the answer.

Tap for more steps...

Step 3.1

Rewrite $\tan (6 \cdot 0)$ in terms of sines and cosines.

$\frac{\frac{\sin (6 \cdot 0)}{\cos (6 \cdot 0)}}{\sin (2 t)}$

Step 3.2

Rewrite $\frac{\frac{\sin (6 \cdot 0)}{\cos (6 \cdot 0)}}{\sin (2 t)}$ as a product.

$\frac{\sin (6 \cdot 0)}{\cos (6 \cdot 0)} \cdot \frac{1}{\sin (2 t)}$

Step 3.3

Multiply $\frac{\sin (6 \cdot 0)}{\cos (6 \cdot 0)}$ by $\frac{1}{\sin (2 t)}$ .

$\frac{\sin (6 \cdot 0)}{\cos (6 \cdot 0) \sin (2 t)}$

Step 3.4

Multiply $6$ by $0$ .

$\frac{\sin (0)}{\cos (6 \cdot 0) \sin (2 t)}$

Step 3.5

Multiply $6$ by $0$ .

$\frac{\sin (0)}{\cos (0) \sin (2 t)}$

Step 3.6

The exact value of $\sin (0)$ is $0$ .

$\frac{0}{\cos (0) \sin (2 t)}$

Step 3.7

Simplify the denominator.

Tap for more steps...

Step 3.7.1

The exact value of $\cos (0)$ is $1$ .

$\frac{0}{1 \sin (2 t)}$

Step 3.7.2

Multiply $\sin (2 t)$ by $1$ .

$\frac{0}{\sin (2 t)}$

Step 3.8

Divide $0$ by $\sin (2 t)$ .

$0$