Calculus Examples

$\sin (\sqrt{1 + x^{2}})$

Step 1

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{1 + x^{2}}$ as ${(1 + x^{2})}^{\frac{1}{2}}$ .

$\frac{d}{d x} [\sin ({(1 + x^{2})}^{\frac{1}{2}})]$

Step 2

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = \sin (x)$ and $g (x) = {(1 + x^{2})}^{\frac{1}{2}}$ .

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Step 2.1

To apply the Chain Rule, set $u_{1}$ as ${(1 + x^{2})}^{\frac{1}{2}}$ .

$\frac{d}{d u_{1}} [\sin (u_{1})] \frac{d}{d x} [{(1 + x^{2})}^{\frac{1}{2}}]$

Step 2.2

The derivative of $\sin (u_{1})$ with respect to $u_{1}$ is $\cos (u_{1})$ .

$\cos (u_{1}) \frac{d}{d x} [{(1 + x^{2})}^{\frac{1}{2}}]$

Step 2.3

Replace all occurrences of $u_{1}$ with ${(1 + x^{2})}^{\frac{1}{2}}$ .

$\cos ({(1 + x^{2})}^{\frac{1}{2}}) \frac{d}{d x} [{(1 + x^{2})}^{\frac{1}{2}}]$

Step 3

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = x^{\frac{1}{2}}$ and $g (x) = 1 + x^{2}$ .

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Step 3.1

To apply the Chain Rule, set $u_{2}$ as $1 + x^{2}$ .

$\cos ({(1 + x^{2})}^{\frac{1}{2}}) (\frac{d}{d u_{2}} [{u_{2}}^{\frac{1}{2}}] \frac{d}{d x} [1 + x^{2}])$

Step 3.2

Differentiate using the Power Rule which states that $\frac{d}{d u_{2}} [{u_{2}}^{n}]$ is $n {u_{2}}^{n - 1}$ where $n = \frac{1}{2}$ .

$\cos ({(1 + x^{2})}^{\frac{1}{2}}) (\frac{1}{2} {u_{2}}^{\frac{1}{2} - 1} \frac{d}{d x} [1 + x^{2}])$

Step 3.3

Replace all occurrences of $u_{2}$ with $1 + x^{2}$ .

$\cos ({(1 + x^{2})}^{\frac{1}{2}}) (\frac{1}{2} {(1 + x^{2})}^{\frac{1}{2} - 1} \frac{d}{d x} [1 + x^{2}])$

Step 4

To write $- 1$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$\cos ({(1 + x^{2})}^{\frac{1}{2}}) (\frac{1}{2} {(1 + x^{2})}^{\frac{1}{2} - 1 \cdot \frac{2}{2}} \frac{d}{d x} [1 + x^{2}])$

Step 5

Combine $- 1$ and $\frac{2}{2}$ .

$\cos ({(1 + x^{2})}^{\frac{1}{2}}) (\frac{1}{2} {(1 + x^{2})}^{\frac{1}{2} + \frac{- 1 \cdot 2}{2}} \frac{d}{d x} [1 + x^{2}])$

Step 6

Combine the numerators over the common denominator.

$\cos ({(1 + x^{2})}^{\frac{1}{2}}) (\frac{1}{2} {(1 + x^{2})}^{\frac{1 - 1 \cdot 2}{2}} \frac{d}{d x} [1 + x^{2}])$

Step 7

Simplify the numerator.

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Step 7.1

Multiply $- 1$ by $2$ .

$\cos ({(1 + x^{2})}^{\frac{1}{2}}) (\frac{1}{2} {(1 + x^{2})}^{\frac{1 - 2}{2}} \frac{d}{d x} [1 + x^{2}])$

Step 7.2

Subtract $2$ from $1$ .

$\cos ({(1 + x^{2})}^{\frac{1}{2}}) (\frac{1}{2} {(1 + x^{2})}^{\frac{- 1}{2}} \frac{d}{d x} [1 + x^{2}])$

Step 8

Combine fractions.

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Step 8.1

Move the negative in front of the fraction.

$\cos ({(1 + x^{2})}^{\frac{1}{2}}) (\frac{1}{2} {(1 + x^{2})}^{- \frac{1}{2}} \frac{d}{d x} [1 + x^{2}])$

Step 8.2

Combine $\frac{1}{2}$ and ${(1 + x^{2})}^{- \frac{1}{2}}$ .

$\cos ({(1 + x^{2})}^{\frac{1}{2}}) (\frac{{(1 + x^{2})}^{- \frac{1}{2}}}{2} \frac{d}{d x} [1 + x^{2}])$

Step 8.3

Move ${(1 + x^{2})}^{- \frac{1}{2}}$ to the denominator using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$\cos ({(1 + x^{2})}^{\frac{1}{2}}) (\frac{1}{2 {(1 + x^{2})}^{\frac{1}{2}}} \frac{d}{d x} [1 + x^{2}])$

Step 8.4

Combine $\frac{1}{2 {(1 + x^{2})}^{\frac{1}{2}}}$ and $\cos ({(1 + x^{2})}^{\frac{1}{2}})$ .

$\frac{\cos ({(1 + x^{2})}^{\frac{1}{2}})}{2 {(1 + x^{2})}^{\frac{1}{2}}} \frac{d}{d x} [1 + x^{2}]$

Step 9

By the Sum Rule, the derivative of $1 + x^{2}$ with respect to $x$ is $\frac{d}{d x} [1] + \frac{d}{d x} [x^{2}]$ .

$\frac{\cos ({(1 + x^{2})}^{\frac{1}{2}})}{2 {(1 + x^{2})}^{\frac{1}{2}}} (\frac{d}{d x} [1] + \frac{d}{d x} [x^{2}])$

Step 10

Since $1$ is constant with respect to $x$ , the derivative of $1$ with respect to $x$ is $0$ .

$\frac{\cos ({(1 + x^{2})}^{\frac{1}{2}})}{2 {(1 + x^{2})}^{\frac{1}{2}}} (0 + \frac{d}{d x} [x^{2}])$

Step 11

Add $0$ and $\frac{d}{d x} [x^{2}]$ .

$\frac{\cos ({(1 + x^{2})}^{\frac{1}{2}})}{2 {(1 + x^{2})}^{\frac{1}{2}}} \frac{d}{d x} [x^{2}]$

Step 12

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 2$ .

$\frac{\cos ({(1 + x^{2})}^{\frac{1}{2}})}{2 {(1 + x^{2})}^{\frac{1}{2}}} (2 x)$

Step 13

Simplify terms.

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Step 13.1

Combine $2$ and $\frac{\cos ({(1 + x^{2})}^{\frac{1}{2}})}{2 {(1 + x^{2})}^{\frac{1}{2}}}$ .

$\frac{2 \cos ({(1 + x^{2})}^{\frac{1}{2}})}{2 {(1 + x^{2})}^{\frac{1}{2}}} x$

Step 13.2

Combine $\frac{2 \cos ({(1 + x^{2})}^{\frac{1}{2}})}{2 {(1 + x^{2})}^{\frac{1}{2}}}$ and $x$ .

$\frac{2 \cos ({(1 + x^{2})}^{\frac{1}{2}}) x}{2 {(1 + x^{2})}^{\frac{1}{2}}}$

Step 13.3

Cancel the common factor.

$\frac{2 \cos ({(1 + x^{2})}^{\frac{1}{2}}) x}{2 {(1 + x^{2})}^{\frac{1}{2}}}$

Step 13.4

Rewrite the expression.

$\frac{\cos ({(1 + x^{2})}^{\frac{1}{2}}) x}{{(1 + x^{2})}^{\frac{1}{2}}}$

Step 14

Simplify.

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Step 14.1

Reorder factors in $\cos ({(1 + x^{2})}^{\frac{1}{2}}) x$ .

$\frac{x \cos ({(1 + x^{2})}^{\frac{1}{2}})}{{(1 + x^{2})}^{\frac{1}{2}}}$

Step 14.2

Reorder terms.

$\frac{x \cos ({(1 + x^{2})}^{\frac{1}{2}})}{{(x^{2} + 1)}^{\frac{1}{2}}}$