Calculus Examples

$x^{2} = {(4 x^{2} y^{3} + 1)}^{2}$

Step 1

Differentiate both sides of the equation.

$\frac{d}{d x} (x^{2}) = \frac{d}{d x} ({(4 x^{2} y^{3} + 1)}^{2})$

Step 2

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 2$ .

$2 x$

Step 3

Differentiate the right side of the equation.

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Step 3.1

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = x^{2}$ and $g (x) = 4 x^{2} y^{3} + 1$ .

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Step 3.1.1

To apply the Chain Rule, set $u_{1}$ as $4 x^{2} y^{3} + 1$ .

$\frac{d}{d u_{1}} [{u_{1}}^{2}] \frac{d}{d x} [4 x^{2} y^{3} + 1]$

Step 3.1.2

Differentiate using the Power Rule which states that $\frac{d}{d u_{1}} [{u_{1}}^{n}]$ is $n {u_{1}}^{n - 1}$ where $n = 2$ .

$2 u_{1} \frac{d}{d x} [4 x^{2} y^{3} + 1]$

Step 3.1.3

Replace all occurrences of $u_{1}$ with $4 x^{2} y^{3} + 1$ .

$2 (4 x^{2} y^{3} + 1) \frac{d}{d x} [4 x^{2} y^{3} + 1]$

Step 3.2

Differentiate.

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Step 3.2.1

By the Sum Rule, the derivative of $4 x^{2} y^{3} + 1$ with respect to $x$ is $\frac{d}{d x} [4 x^{2} y^{3}] + \frac{d}{d x} [1]$ .

$2 (4 x^{2} y^{3} + 1) (\frac{d}{d x} [4 x^{2} y^{3}] + \frac{d}{d x} [1])$

Step 3.2.2

Since $4$ is constant with respect to $x$ , the derivative of $4 x^{2} y^{3}$ with respect to $x$ is $4 \frac{d}{d x} [x^{2} y^{3}]$ .

$2 (4 x^{2} y^{3} + 1) (4 \frac{d}{d x} [x^{2} y^{3}] + \frac{d}{d x} [1])$

Step 3.3

Differentiate using the Product Rule which states that $\frac{d}{d x} [f (x) g (x)]$ is $f (x) \frac{d}{d x} [g (x)] + g (x) \frac{d}{d x} [f (x)]$ where $f (x) = x^{2}$ and $g (x) = y^{3}$ .

$2 (4 x^{2} y^{3} + 1) (4 (x^{2} \frac{d}{d x} [y^{3}] + y^{3} \frac{d}{d x} [x^{2}]) + \frac{d}{d x} [1])$

Step 3.4

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = x^{3}$ and $g (x) = y$ .

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Step 3.4.1

To apply the Chain Rule, set $u_{2}$ as $y$ .

$2 (4 x^{2} y^{3} + 1) (4 (x^{2} (\frac{d}{d u_{2}} [{u_{2}}^{3}] \frac{d}{d x} [y]) + y^{3} \frac{d}{d x} [x^{2}]) + \frac{d}{d x} [1])$

Step 3.4.2

Differentiate using the Power Rule which states that $\frac{d}{d u_{2}} [{u_{2}}^{n}]$ is $n {u_{2}}^{n - 1}$ where $n = 3$ .

$2 (4 x^{2} y^{3} + 1) (4 (x^{2} (3 {u_{2}}^{2} \frac{d}{d x} [y]) + y^{3} \frac{d}{d x} [x^{2}]) + \frac{d}{d x} [1])$

Step 3.4.3

Replace all occurrences of $u_{2}$ with $y$ .

$2 (4 x^{2} y^{3} + 1) (4 (x^{2} (3 y^{2} \frac{d}{d x} [y]) + y^{3} \frac{d}{d x} [x^{2}]) + \frac{d}{d x} [1])$

Step 3.5

Move $3$ to the left of $x^{2}$ .

$2 (4 x^{2} y^{3} + 1) (4 (3 \cdot x^{2} y^{2} \frac{d}{d x} [y] + y^{3} \frac{d}{d x} [x^{2}]) + \frac{d}{d x} [1])$

Step 3.6

Rewrite $\frac{d}{d x} [y]$ as $y'$ .

$2 (4 x^{2} y^{3} + 1) (4 (3 x^{2} y^{2} y' + y^{3} \frac{d}{d x} [x^{2}]) + \frac{d}{d x} [1])$

Step 3.7

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 2$ .

$2 (4 x^{2} y^{3} + 1) (4 (3 x^{2} y^{2} y' + y^{3} (2 x)) + \frac{d}{d x} [1])$

Step 3.8

Move $2$ to the left of $y^{3}$ .

$2 (4 x^{2} y^{3} + 1) (4 (3 x^{2} y^{2} y' + 2 \cdot y^{3} x) + \frac{d}{d x} [1])$

Step 3.9

Since $1$ is constant with respect to $x$ , the derivative of $1$ with respect to $x$ is $0$ .

$2 (4 x^{2} y^{3} + 1) (4 (3 x^{2} y^{2} y' + 2 y^{3} x) + 0)$

Step 3.10

Simplify the expression.

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Step 3.10.1

Add $4 (3 x^{2} y^{2} y' + 2 y^{3} x)$ and $0$ .

$2 (4 x^{2} y^{3} + 1) (4 (3 x^{2} y^{2} y' + 2 y^{3} x))$

Step 3.10.2

Multiply $4$ by $2$ .

$8 (4 x^{2} y^{3} + 1) (3 x^{2} y^{2} y' + 2 y^{3} x)$

Step 3.11

Simplify.

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Step 3.11.1

Apply the distributive property.

$(8 (4 x^{2} y^{3}) + 8 \cdot 1) (3 x^{2} y^{2} y' + 2 y^{3} x)$

Step 3.11.2

Combine terms.

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Step 3.11.2.1

Multiply $4$ by $8$ .

$(32 (x^{2} y^{3}) + 8 \cdot 1) (3 x^{2} y^{2} y' + 2 y^{3} x)$

Step 3.11.2.2

Multiply $8$ by $1$ .

$(32 x^{2} y^{3} + 8) (3 x^{2} y^{2} y' + 2 y^{3} x)$

Step 4

Reform the equation by setting the left side equal to the right side.

$2 x = (32 x^{2} y^{3} + 8) (3 x^{2} y^{2} y' + 2 y^{3} x)$

Step 5

Solve for $y'$ .

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Step 5.1

Rewrite the equation as $(32 x^{2} y^{3} + 8) (3 x^{2} y^{2} y' + 2 y^{3} x) = 2 x$ .

$(32 x^{2} y^{3} + 8) (3 x^{2} y^{2} y' + 2 y^{3} x) = 2 x$

Step 5.2

Divide each term in $(32 x^{2} y^{3} + 8) (3 x^{2} y^{2} y' + 2 y^{3} x) = 2 x$ by $32 x^{2} y^{3} + 8$ and simplify.

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Step 5.2.1

Divide each term in $(32 x^{2} y^{3} + 8) (3 x^{2} y^{2} y' + 2 y^{3} x) = 2 x$ by $32 x^{2} y^{3} + 8$ .

$\frac{(32 x^{2} y^{3} + 8) (3 x^{2} y^{2} y' + 2 y^{3} x)}{32 x^{2} y^{3} + 8} = \frac{2 x}{32 x^{2} y^{3} + 8}$

Step 5.2.2

Simplify the left side.

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Step 5.2.2.1

Cancel the common factor of $32 x^{2} y^{3} + 8$ .

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Step 5.2.2.1.1

Cancel the common factor.

$\frac{(32 x^{2} y^{3} + 8) (3 x^{2} y^{2} y' + 2 y^{3} x)}{32 x^{2} y^{3} + 8} = \frac{2 x}{32 x^{2} y^{3} + 8}$

Step 5.2.2.1.2

Divide $3 x^{2} y^{2} y' + 2 y^{3} x$ by $1$ .

$3 x^{2} y^{2} y' + 2 y^{3} x = \frac{2 x}{32 x^{2} y^{3} + 8}$

Step 5.2.3

Simplify the right side.

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Step 5.2.3.1

Cancel the common factor of $2$ and $32 x^{2} y^{3} + 8$ .

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Step 5.2.3.1.1

Factor $2$ out of $2 x$ .

$3 x^{2} y^{2} y' + 2 y^{3} x = \frac{2 (x)}{32 x^{2} y^{3} + 8}$

Step 5.2.3.1.2

Cancel the common factors.

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Step 5.2.3.1.2.1

Factor $2$ out of $32 x^{2} y^{3}$ .

$3 x^{2} y^{2} y' + 2 y^{3} x = \frac{2 (x)}{2 (16 x^{2} y^{3}) + 8}$

Step 5.2.3.1.2.2

Factor $2$ out of $8$ .

$3 x^{2} y^{2} y' + 2 y^{3} x = \frac{2 x}{2 (16 x^{2} y^{3}) + 2 \cdot 4}$

Step 5.2.3.1.2.3

Factor $2$ out of $2 (16 x^{2} y^{3}) + 2 (4)$ .

$3 x^{2} y^{2} y' + 2 y^{3} x = \frac{2 (x)}{2 (16 x^{2} y^{3} + 4)}$

Step 5.2.3.1.2.4

Cancel the common factor.

$3 x^{2} y^{2} y' + 2 y^{3} x = \frac{2 x}{2 (16 x^{2} y^{3} + 4)}$

Step 5.2.3.1.2.5

Rewrite the expression.

$3 x^{2} y^{2} y' + 2 y^{3} x = \frac{x}{16 x^{2} y^{3} + 4}$

Step 5.2.3.2

Factor $4$ out of $16 x^{2} y^{3} + 4$ .

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Step 5.2.3.2.1

Factor $4$ out of $16 x^{2} y^{3}$ .

$3 x^{2} y^{2} y' + 2 y^{3} x = \frac{x}{4 (4 x^{2} y^{3}) + 4}$

Step 5.2.3.2.2

Factor $4$ out of $4$ .

$3 x^{2} y^{2} y' + 2 y^{3} x = \frac{x}{4 (4 x^{2} y^{3}) + 4 (1)}$

Step 5.2.3.2.3

Factor $4$ out of $4 (4 x^{2} y^{3}) + 4 (1)$ .

$3 x^{2} y^{2} y' + 2 y^{3} x = \frac{x}{4 (4 x^{2} y^{3} + 1)}$

Step 5.3

Subtract $2 y^{3} x$ from both sides of the equation.

$3 x^{2} y^{2} y' = \frac{x}{4 (4 x^{2} y^{3} + 1)} - 2 y^{3} x$

Step 5.4

Divide each term in $3 x^{2} y^{2} y' = \frac{x}{4 (4 x^{2} y^{3} + 1)} - 2 y^{3} x$ by $3 x^{2} y^{2}$ and simplify.

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Step 5.4.1

Divide each term in $3 x^{2} y^{2} y' = \frac{x}{4 (4 x^{2} y^{3} + 1)} - 2 y^{3} x$ by $3 x^{2} y^{2}$ .

$\frac{3 x^{2} y^{2} y'}{3 x^{2} y^{2}} = \frac{\frac{x}{4 (4 x^{2} y^{3} + 1)}}{3 x^{2} y^{2}} + \frac{- 2 y^{3} x}{3 x^{2} y^{2}}$

Step 5.4.2

Simplify the left side.

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Step 5.4.2.1

Cancel the common factor of $3$ .

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Step 5.4.2.1.1

Cancel the common factor.

$\frac{3 x^{2} y^{2} y'}{3 x^{2} y^{2}} = \frac{\frac{x}{4 (4 x^{2} y^{3} + 1)}}{3 x^{2} y^{2}} + \frac{- 2 y^{3} x}{3 x^{2} y^{2}}$

Step 5.4.2.1.2

Rewrite the expression.

$\frac{x^{2} y^{2} y'}{x^{2} y^{2}} = \frac{\frac{x}{4 (4 x^{2} y^{3} + 1)}}{3 x^{2} y^{2}} + \frac{- 2 y^{3} x}{3 x^{2} y^{2}}$

Step 5.4.2.2

Cancel the common factor of $x^{2}$ .

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Step 5.4.2.2.1

Cancel the common factor.

$\frac{x^{2} y^{2} y'}{x^{2} y^{2}} = \frac{\frac{x}{4 (4 x^{2} y^{3} + 1)}}{3 x^{2} y^{2}} + \frac{- 2 y^{3} x}{3 x^{2} y^{2}}$

Step 5.4.2.2.2

Rewrite the expression.

$\frac{y^{2} y'}{y^{2}} = \frac{\frac{x}{4 (4 x^{2} y^{3} + 1)}}{3 x^{2} y^{2}} + \frac{- 2 y^{3} x}{3 x^{2} y^{2}}$

Step 5.4.2.3

Cancel the common factor of $y^{2}$ .

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Step 5.4.2.3.1

Cancel the common factor.

$\frac{y^{2} y'}{y^{2}} = \frac{\frac{x}{4 (4 x^{2} y^{3} + 1)}}{3 x^{2} y^{2}} + \frac{- 2 y^{3} x}{3 x^{2} y^{2}}$

Step 5.4.2.3.2

Divide $y'$ by $1$ .

$y' = \frac{\frac{x}{4 (4 x^{2} y^{3} + 1)}}{3 x^{2} y^{2}} + \frac{- 2 y^{3} x}{3 x^{2} y^{2}}$

Step 5.4.3

Simplify the right side.

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Step 5.4.3.1

Combine the numerators over the common denominator.

$y' = \frac{\frac{x}{4 (4 x^{2} y^{3} + 1)} - 2 y^{3} x}{3 x^{2} y^{2}}$

Step 5.4.3.2

Simplify the numerator.

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Step 5.4.3.2.1

Factor $x$ out of $\frac{x}{4 (4 x^{2} y^{3} + 1)} - 2 y^{3} x$ .

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Step 5.4.3.2.1.1

Factor $x$ out of $\frac{x}{4 (4 x^{2} y^{3} + 1)}$ .

$y' = \frac{x \frac{1}{4 (4 x^{2} y^{3} + 1)} - 2 y^{3} x}{3 x^{2} y^{2}}$

Step 5.4.3.2.1.2

Factor $x$ out of $- 2 y^{3} x$ .

$y' = \frac{x \frac{1}{4 (4 x^{2} y^{3} + 1)} + x (- 2 y^{3})}{3 x^{2} y^{2}}$

Step 5.4.3.2.1.3

Factor $x$ out of $x \frac{1}{4 (4 x^{2} y^{3} + 1)} + x (- 2 y^{3})$ .

$y' = \frac{x (\frac{1}{4 (4 x^{2} y^{3} + 1)} - 2 y^{3})}{3 x^{2} y^{2}}$

Step 5.4.3.2.2

To write $- 2 y^{3}$ as a fraction with a common denominator, multiply by $\frac{4 (4 x^{2} y^{3} + 1)}{4 (4 x^{2} y^{3} + 1)}$ .

$y' = \frac{x (\frac{1}{4 (4 x^{2} y^{3} + 1)} - 2 y^{3} \cdot \frac{4 (4 x^{2} y^{3} + 1)}{4 (4 x^{2} y^{3} + 1)})}{3 x^{2} y^{2}}$

Step 5.4.3.2.3

Combine $- 2 y^{3}$ and $\frac{4 (4 x^{2} y^{3} + 1)}{4 (4 x^{2} y^{3} + 1)}$ .

$y' = \frac{x (\frac{1}{4 (4 x^{2} y^{3} + 1)} + \frac{- 2 y^{3} (4 (4 x^{2} y^{3} + 1))}{4 (4 x^{2} y^{3} + 1)})}{3 x^{2} y^{2}}$

Step 5.4.3.2.4

Combine the numerators over the common denominator.

$y' = \frac{x \frac{1 - 2 y^{3} (4 (4 x^{2} y^{3} + 1))}{4 (4 x^{2} y^{3} + 1)}}{3 x^{2} y^{2}}$

Step 5.4.3.2.5

Simplify the numerator.

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Step 5.4.3.2.5.1

Apply the distributive property.

$y' = \frac{x \frac{1 - 2 y^{3} (4 (4 x^{2} y^{3}) + 4 \cdot 1)}{4 (4 x^{2} y^{3} + 1)}}{3 x^{2} y^{2}}$

Step 5.4.3.2.5.2

Multiply $4$ by $4$ .

$y' = \frac{x \frac{1 - 2 y^{3} (16 (x^{2} y^{3}) + 4 \cdot 1)}{4 (4 x^{2} y^{3} + 1)}}{3 x^{2} y^{2}}$

Step 5.4.3.2.5.3

Multiply $4$ by $1$ .

$y' = \frac{x \frac{1 - 2 y^{3} (16 (x^{2} y^{3}) + 4)}{4 (4 x^{2} y^{3} + 1)}}{3 x^{2} y^{2}}$

Step 5.4.3.2.5.4

Apply the distributive property.

$y' = \frac{x \frac{1 - 2 y^{3} (16 x^{2} y^{3}) - 2 y^{3} \cdot 4}{4 (4 x^{2} y^{3} + 1)}}{3 x^{2} y^{2}}$

Step 5.4.3.2.5.5

Multiply $y^{3}$ by $y^{3}$ by adding the exponents.

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Step 5.4.3.2.5.5.1

Move $y^{3}$ .

$y' = \frac{x \frac{1 - 2 (y^{3} y^{3}) (16 x^{2}) - 2 y^{3} \cdot 4}{4 (4 x^{2} y^{3} + 1)}}{3 x^{2} y^{2}}$

Step 5.4.3.2.5.5.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$y' = \frac{x \frac{1 - 2 y^{3 + 3} (16 x^{2}) - 2 y^{3} \cdot 4}{4 (4 x^{2} y^{3} + 1)}}{3 x^{2} y^{2}}$

Step 5.4.3.2.5.5.3

Add $3$ and $3$ .

$y' = \frac{x \frac{1 - 2 y^{6} (16 x^{2}) - 2 y^{3} \cdot 4}{4 (4 x^{2} y^{3} + 1)}}{3 x^{2} y^{2}}$

Step 5.4.3.2.5.6

Multiply $4$ by $- 2$ .

$y' = \frac{x \frac{1 - 2 y^{6} (16 x^{2}) - 8 y^{3}}{4 (4 x^{2} y^{3} + 1)}}{3 x^{2} y^{2}}$

Step 5.4.3.2.5.7

Simplify each term.

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Step 5.4.3.2.5.7.1

Rewrite using the commutative property of multiplication.

$y' = \frac{x \frac{1 - 2 \cdot 16 y^{6} x^{2} - 8 y^{3}}{4 (4 x^{2} y^{3} + 1)}}{3 x^{2} y^{2}}$

Step 5.4.3.2.5.7.2

Multiply $- 2$ by $16$ .

$y' = \frac{x \frac{1 - 32 y^{6} x^{2} - 8 y^{3}}{4 (4 x^{2} y^{3} + 1)}}{3 x^{2} y^{2}}$

Step 5.4.3.3

Combine $x$ and $\frac{1 - 32 y^{6} x^{2} - 8 y^{3}}{4 (4 x^{2} y^{3} + 1)}$ .

$y' = \frac{\frac{x (1 - 32 y^{6} x^{2} - 8 y^{3})}{4 (4 x^{2} y^{3} + 1)}}{3 x^{2} y^{2}}$

Step 5.4.3.4

Multiply the numerator by the reciprocal of the denominator.

$y' = \frac{x (1 - 32 y^{6} x^{2} - 8 y^{3})}{4 (4 x^{2} y^{3} + 1)} \cdot \frac{1}{3 x^{2} y^{2}}$

Step 5.4.3.5

Simplify terms.

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Step 5.4.3.5.1

Combine.

$y' = \frac{x (1 - 32 y^{6} x^{2} - 8 y^{3}) \cdot 1}{4 (4 x^{2} y^{3} + 1) (3 x^{2} y^{2})}$

Step 5.4.3.5.2

Cancel the common factor of $x$ and $x^{2}$ .

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Step 5.4.3.5.2.1

Factor $x$ out of $x (1 - 32 y^{6} x^{2} - 8 y^{3}) \cdot 1$ .

$y' = \frac{x ((1 - 32 y^{6} x^{2} - 8 y^{3}) \cdot 1)}{4 (4 x^{2} y^{3} + 1) (3 x^{2} y^{2})}$

Step 5.4.3.5.2.2

Cancel the common factors.

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Step 5.4.3.5.2.2.1

Factor $x$ out of $4 (4 x^{2} y^{3} + 1) (3 x^{2} y^{2})$ .

$y' = \frac{x ((1 - 32 y^{6} x^{2} - 8 y^{3}) \cdot 1)}{x (4 (4 x^{2} y^{3} + 1) (3 x y^{2}))}$

Step 5.4.3.5.2.2.2

Cancel the common factor.

$y' = \frac{x ((1 - 32 y^{6} x^{2} - 8 y^{3}) \cdot 1)}{x (4 (4 x^{2} y^{3} + 1) (3 x y^{2}))}$

Step 5.4.3.5.2.2.3

Rewrite the expression.

$y' = \frac{(1 - 32 y^{6} x^{2} - 8 y^{3}) \cdot 1}{4 (4 x^{2} y^{3} + 1) (3 x y^{2})}$

Step 5.4.3.5.3

Multiply.

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Step 5.4.3.5.3.1

Multiply $1 - 32 y^{6} x^{2} - 8 y^{3}$ by $1$ .

$y' = \frac{1 - 32 y^{6} x^{2} - 8 y^{3}}{4 (4 x^{2} y^{3} + 1) (3 x y^{2})}$

Step 5.4.3.5.3.2

Multiply $3$ by $4$ .

$y' = \frac{1 - 32 y^{6} x^{2} - 8 y^{3}}{12 (4 x^{2} y^{3} + 1) (x y^{2})}$

Step 5.4.3.6

Simplify the denominator.

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Step 5.4.3.6.1

Rewrite.

$y' = \frac{1 - 32 y^{6} x^{2} - 8 y^{3}}{4 (4 x^{2} y^{3} + 1) (3 x^{2} y^{2})}$

Step 5.4.3.6.2

Factor $x$ out of $x^{2}$ .

$y' = \frac{1 - 32 y^{6} x^{2} - 8 y^{3}}{4 (4 x^{2} y^{3} + 1) (3 (x \cdot x) y^{2})}$

Step 5.4.3.6.3

Rewrite.

$y' = \frac{1 - 32 y^{6} x^{2} - 8 y^{3}}{4 (4 x^{2} y^{3} + 1) (3 x^{1} y^{2})}$

Step 5.4.3.6.4

Simplify.

$y' = \frac{1 - 32 y^{6} x^{2} - 8 y^{3}}{4 (4 x^{2} y^{3} + 1) (3 x y^{2})}$

Step 5.4.3.6.5

Remove unnecessary parentheses.

$y' = \frac{1 - 32 y^{6} x^{2} - 8 y^{3}}{12 (4 x^{2} y^{3} + 1) x y^{2}}$

Step 5.4.3.7

Reorder factors in $\frac{1 - 32 y^{6} x^{2} - 8 y^{3}}{12 (4 x^{2} y^{3} + 1) x y^{2}}$ .

$y' = \frac{1 - 32 y^{6} x^{2} - 8 y^{3}}{12 x y^{2} (4 x^{2} y^{3} + 1)}$

Step 6

Replace $y'$ with $\frac{d y}{d x}$ .

$\frac{d y}{d x} = \frac{1 - 32 y^{6} x^{2} - 8 y^{3}}{12 x y^{2} (4 x^{2} y^{3} + 1)}$