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Calculus Examples
Step 1
Write as a function.
Step 2
Step 2.1
Find the first derivative.
Step 2.1.1
Differentiate using the Quotient Rule which states that is where and .
Step 2.1.2
Differentiate.
Step 2.1.2.1
Differentiate using the Power Rule which states that is where .
Step 2.1.2.2
Move to the left of .
Step 2.1.2.3
By the Sum Rule, the derivative of with respect to is .
Step 2.1.2.4
Differentiate using the Power Rule which states that is where .
Step 2.1.2.5
Since is constant with respect to , the derivative of with respect to is .
Step 2.1.2.6
Simplify the expression.
Step 2.1.2.6.1
Add and .
Step 2.1.2.6.2
Multiply by .
Step 2.1.3
Raise to the power of .
Step 2.1.4
Use the power rule to combine exponents.
Step 2.1.5
Add and .
Step 2.1.6
Simplify.
Step 2.1.6.1
Apply the distributive property.
Step 2.1.6.2
Apply the distributive property.
Step 2.1.6.3
Simplify the numerator.
Step 2.1.6.3.1
Simplify each term.
Step 2.1.6.3.1.1
Multiply by by adding the exponents.
Step 2.1.6.3.1.1.1
Move .
Step 2.1.6.3.1.1.2
Multiply by .
Step 2.1.6.3.1.1.2.1
Raise to the power of .
Step 2.1.6.3.1.1.2.2
Use the power rule to combine exponents.
Step 2.1.6.3.1.1.3
Add and .
Step 2.1.6.3.1.2
Multiply by .
Step 2.1.6.3.2
Combine the opposite terms in .
Step 2.1.6.3.2.1
Subtract from .
Step 2.1.6.3.2.2
Add and .
Step 2.2
Find the second derivative.
Step 2.2.1
Since is constant with respect to , the derivative of with respect to is .
Step 2.2.2
Differentiate using the Quotient Rule which states that is where and .
Step 2.2.3
Differentiate using the Power Rule.
Step 2.2.3.1
Multiply the exponents in .
Step 2.2.3.1.1
Apply the power rule and multiply exponents, .
Step 2.2.3.1.2
Multiply by .
Step 2.2.3.2
Differentiate using the Power Rule which states that is where .
Step 2.2.3.3
Multiply by .
Step 2.2.4
Differentiate using the chain rule, which states that is where and .
Step 2.2.4.1
To apply the Chain Rule, set as .
Step 2.2.4.2
Differentiate using the Power Rule which states that is where .
Step 2.2.4.3
Replace all occurrences of with .
Step 2.2.5
Simplify with factoring out.
Step 2.2.5.1
Multiply by .
Step 2.2.5.2
Factor out of .
Step 2.2.5.2.1
Factor out of .
Step 2.2.5.2.2
Factor out of .
Step 2.2.5.2.3
Factor out of .
Step 2.2.6
Cancel the common factors.
Step 2.2.6.1
Factor out of .
Step 2.2.6.2
Cancel the common factor.
Step 2.2.6.3
Rewrite the expression.
Step 2.2.7
By the Sum Rule, the derivative of with respect to is .
Step 2.2.8
Differentiate using the Power Rule which states that is where .
Step 2.2.9
Since is constant with respect to , the derivative of with respect to is .
Step 2.2.10
Simplify the expression.
Step 2.2.10.1
Add and .
Step 2.2.10.2
Multiply by .
Step 2.2.11
Raise to the power of .
Step 2.2.12
Raise to the power of .
Step 2.2.13
Use the power rule to combine exponents.
Step 2.2.14
Add and .
Step 2.2.15
Subtract from .
Step 2.2.16
Combine and .
Step 2.2.17
Simplify.
Step 2.2.17.1
Apply the distributive property.
Step 2.2.17.2
Simplify each term.
Step 2.2.17.2.1
Multiply by .
Step 2.2.17.2.2
Multiply by .
Step 2.3
The second derivative of with respect to is .
Step 3
Step 3.1
Set the second derivative equal to .
Step 3.2
Set the numerator equal to zero.
Step 3.3
Solve the equation for .
Step 3.3.1
Subtract from both sides of the equation.
Step 3.3.2
Divide each term in by and simplify.
Step 3.3.2.1
Divide each term in by .
Step 3.3.2.2
Simplify the left side.
Step 3.3.2.2.1
Cancel the common factor of .
Step 3.3.2.2.1.1
Cancel the common factor.
Step 3.3.2.2.1.2
Divide by .
Step 3.3.2.3
Simplify the right side.
Step 3.3.2.3.1
Divide by .
Step 3.3.3
Take the specified root of both sides of the equation to eliminate the exponent on the left side.
Step 3.3.4
Any root of is .
Step 3.3.5
The complete solution is the result of both the positive and negative portions of the solution.
Step 3.3.5.1
First, use the positive value of the to find the first solution.
Step 3.3.5.2
Next, use the negative value of the to find the second solution.
Step 3.3.5.3
The complete solution is the result of both the positive and negative portions of the solution.
Step 4
Step 4.1
Substitute in to find the value of .
Step 4.1.1
Replace the variable with in the expression.
Step 4.1.2
Simplify the result.
Step 4.1.2.1
One to any power is one.
Step 4.1.2.2
Simplify the denominator.
Step 4.1.2.2.1
One to any power is one.
Step 4.1.2.2.2
Add and .
Step 4.1.2.3
The final answer is .
Step 4.2
The point found by substituting in is . This point can be an inflection point.
Step 4.3
Substitute in to find the value of .
Step 4.3.1
Replace the variable with in the expression.
Step 4.3.2
Simplify the result.
Step 4.3.2.1
Raise to the power of .
Step 4.3.2.2
Simplify the denominator.
Step 4.3.2.2.1
Raise to the power of .
Step 4.3.2.2.2
Add and .
Step 4.3.2.3
The final answer is .
Step 4.4
The point found by substituting in is . This point can be an inflection point.
Step 4.5
Determine the points that could be inflection points.
Step 5
Split into intervals around the points that could potentially be inflection points.
Step 6
Step 6.1
Replace the variable with in the expression.
Step 6.2
Simplify the result.
Step 6.2.1
Simplify the numerator.
Step 6.2.1.1
Raise to the power of .
Step 6.2.1.2
Multiply by .
Step 6.2.1.3
Add and .
Step 6.2.2
Simplify the denominator.
Step 6.2.2.1
Raise to the power of .
Step 6.2.2.2
Add and .
Step 6.2.2.3
Raise to the power of .
Step 6.2.3
Divide by .
Step 6.2.4
The final answer is .
Step 6.3
At , the second derivative is . Since this is negative, the second derivative is decreasing on the interval
Decreasing on since
Decreasing on since
Step 7
Step 7.1
Replace the variable with in the expression.
Step 7.2
Simplify the result.
Step 7.2.1
Simplify the numerator.
Step 7.2.1.1
Raising to any positive power yields .
Step 7.2.1.2
Multiply by .
Step 7.2.1.3
Add and .
Step 7.2.2
Simplify the denominator.
Step 7.2.2.1
Raising to any positive power yields .
Step 7.2.2.2
Add and .
Step 7.2.2.3
Raise to the power of .
Step 7.2.3
Cancel the common factor of and .
Step 7.2.3.1
Factor out of .
Step 7.2.3.2
Cancel the common factors.
Step 7.2.3.2.1
Factor out of .
Step 7.2.3.2.2
Cancel the common factor.
Step 7.2.3.2.3
Rewrite the expression.
Step 7.2.4
The final answer is .
Step 7.3
At , the second derivative is . Since this is positive, the second derivative is increasing on the interval .
Increasing on since
Increasing on since
Step 8
Step 8.1
Replace the variable with in the expression.
Step 8.2
Simplify the result.
Step 8.2.1
Simplify the numerator.
Step 8.2.1.1
Raise to the power of .
Step 8.2.1.2
Multiply by .
Step 8.2.1.3
Add and .
Step 8.2.2
Simplify the denominator.
Step 8.2.2.1
Raise to the power of .
Step 8.2.2.2
Add and .
Step 8.2.2.3
Raise to the power of .
Step 8.2.3
Divide by .
Step 8.2.4
The final answer is .
Step 8.3
At , the second derivative is . Since this is negative, the second derivative is decreasing on the interval
Decreasing on since
Decreasing on since
Step 9
An inflection point is a point on a curve at which the concavity changes sign from plus to minus or from minus to plus. The inflection points in this case are .
Step 10