Calculus Examples

$y = \frac{x}{2 - \tan (x)}$

Step 1

Differentiate using the Quotient Rule which states that $\frac{d}{d x} [\frac{f (x)}{g (x)}]$ is $\frac{g (x) \frac{d}{d x} [f (x)] - f (x) \frac{d}{d x} [g (x)]}{{g (x)}^{2}}$ where $f (x) = x$ and $g (x) = 2 - \tan (x)$ .

$\frac{(2 - \tan (x)) \frac{d}{d x} [x] - x \frac{d}{d x} [2 - \tan (x)]}{{(2 - \tan (x))}^{2}}$

Step 2

Differentiate.

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Step 2.1

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$\frac{(2 - \tan (x)) \cdot 1 - x \frac{d}{d x} [2 - \tan (x)]}{{(2 - \tan (x))}^{2}}$

Step 2.2

Multiply $2 - \tan (x)$ by $1$ .

$\frac{2 - \tan (x) - x \frac{d}{d x} [2 - \tan (x)]}{{(2 - \tan (x))}^{2}}$

Step 2.3

By the Sum Rule, the derivative of $2 - \tan (x)$ with respect to $x$ is $\frac{d}{d x} [2] + \frac{d}{d x} [- \tan (x)]$ .

$\frac{2 - \tan (x) - x (\frac{d}{d x} [2] + \frac{d}{d x} [- \tan (x)])}{{(2 - \tan (x))}^{2}}$

Step 2.4

Since $2$ is constant with respect to $x$ , the derivative of $2$ with respect to $x$ is $0$ .

$\frac{2 - \tan (x) - x (0 + \frac{d}{d x} [- \tan (x)])}{{(2 - \tan (x))}^{2}}$

Step 2.5

Add $0$ and $\frac{d}{d x} [- \tan (x)]$ .

$\frac{2 - \tan (x) - x \frac{d}{d x} [- \tan (x)]}{{(2 - \tan (x))}^{2}}$

Step 2.6

Since $- 1$ is constant with respect to $x$ , the derivative of $- \tan (x)$ with respect to $x$ is $- \frac{d}{d x} [\tan (x)]$ .

$\frac{2 - \tan (x) - x (- \frac{d}{d x} [\tan (x)])}{{(2 - \tan (x))}^{2}}$

Step 2.7

Multiply.

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Step 2.7.1

Multiply $- 1$ by $- 1$ .

$\frac{2 - \tan (x) + 1 x \frac{d}{d x} [\tan (x)]}{{(2 - \tan (x))}^{2}}$

Step 2.7.2

Multiply $x$ by $1$ .

$\frac{2 - \tan (x) + x \frac{d}{d x} [\tan (x)]}{{(2 - \tan (x))}^{2}}$

Step 3

The derivative of $\tan (x)$ with respect to $x$ is $\sec^{2} (x)$ .

$\frac{2 - \tan (x) + x \sec^{2} (x)}{{(2 - \tan (x))}^{2}}$

Step 4

Reorder terms.

$\frac{x \sec^{2} (x) + 2 - \tan (x)}{{(2 - \tan (x))}^{2}}$