Calculus Examples

$x^{3} + y^{3} = 12 x y - 8$

Step 1

Differentiate both sides of the equation.

$\frac{d}{d x} (x^{3} + y^{3}) = \frac{d}{d x} (12 x y - 8)$

Step 2

Differentiate the left side of the equation.

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Step 2.1

Differentiate.

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Step 2.1.1

By the Sum Rule, the derivative of $x^{3} + y^{3}$ with respect to $x$ is $\frac{d}{d x} [x^{3}] + \frac{d}{d x} [y^{3}]$ .

$\frac{d}{d x} [x^{3}] + \frac{d}{d x} [y^{3}]$

Step 2.1.2

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 3$ .

$3 x^{2} + \frac{d}{d x} [y^{3}]$

Step 2.2

Evaluate $\frac{d}{d x} [y^{3}]$ .

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Step 2.2.1

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = x^{3}$ and $g (x) = y$ .

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Step 2.2.1.1

To apply the Chain Rule, set $u$ as $y$ .

$3 x^{2} + \frac{d}{d u} [u^{3}] \frac{d}{d x} [y]$

Step 2.2.1.2

Differentiate using the Power Rule which states that $\frac{d}{d u} [u^{n}]$ is $n u^{n - 1}$ where $n = 3$ .

$3 x^{2} + 3 u^{2} \frac{d}{d x} [y]$

Step 2.2.1.3

Replace all occurrences of $u$ with $y$ .

$3 x^{2} + 3 y^{2} \frac{d}{d x} [y]$

Step 2.2.2

Rewrite $\frac{d}{d x} [y]$ as $y'$ .

$3 x^{2} + 3 y^{2} y'$

Step 3

Differentiate the right side of the equation.

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Step 3.1

By the Sum Rule, the derivative of $12 x y - 8$ with respect to $x$ is $\frac{d}{d x} [12 x y] + \frac{d}{d x} [- 8]$ .

$\frac{d}{d x} [12 x y] + \frac{d}{d x} [- 8]$

Step 3.2

Evaluate $\frac{d}{d x} [12 x y]$ .

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Step 3.2.1

Since $12$ is constant with respect to $x$ , the derivative of $12 x y$ with respect to $x$ is $12 \frac{d}{d x} [x y]$ .

$12 \frac{d}{d x} [x y] + \frac{d}{d x} [- 8]$

Step 3.2.2

Differentiate using the Product Rule which states that $\frac{d}{d x} [f (x) g (x)]$ is $f (x) \frac{d}{d x} [g (x)] + g (x) \frac{d}{d x} [f (x)]$ where $f (x) = x$ and $g (x) = y$ .

$12 (x \frac{d}{d x} [y] + y \frac{d}{d x} [x]) + \frac{d}{d x} [- 8]$

Step 3.2.3

Rewrite $\frac{d}{d x} [y]$ as $y'$ .

$12 (x y' + y \frac{d}{d x} [x]) + \frac{d}{d x} [- 8]$

Step 3.2.4

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$12 (x y' + y \cdot 1) + \frac{d}{d x} [- 8]$

Step 3.2.5

Multiply $y$ by $1$ .

$12 (x y' + y) + \frac{d}{d x} [- 8]$

Step 3.3

Since $- 8$ is constant with respect to $x$ , the derivative of $- 8$ with respect to $x$ is $0$ .

$12 (x y' + y) + 0$

Step 3.4

Simplify.

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Step 3.4.1

Apply the distributive property.

$12 (x y') + 12 y + 0$

Step 3.4.2

Add $12 x y' + 12 y$ and $0$ .

$12 x y' + 12 y$

Step 4

Reform the equation by setting the left side equal to the right side.

$3 x^{2} + 3 y^{2} y' = 12 x y' + 12 y$

Step 5

Solve for $y'$ .

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Step 5.1

Subtract $12 x y'$ from both sides of the equation.

$3 x^{2} + 3 y^{2} y' - 12 x y' = 12 y$

Step 5.2

Subtract $3 x^{2}$ from both sides of the equation.

$3 y^{2} y' - 12 x y' = 12 y - 3 x^{2}$

Step 5.3

Factor $3 y'$ out of $3 y^{2} y' - 12 x y'$ .

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Step 5.3.1

Factor $3 y'$ out of $3 y^{2} y'$ .

$3 y' y^{2} - 12 x y' = 12 y - 3 x^{2}$

Step 5.3.2

Factor $3 y'$ out of $- 12 x y'$ .

$3 y' y^{2} + 3 y' (- 4 x) = 12 y - 3 x^{2}$

Step 5.3.3

Factor $3 y'$ out of $3 y' y^{2} + 3 y' (- 4 x)$ .

$3 y' (y^{2} - 4 x) = 12 y - 3 x^{2}$

Step 5.4

Divide each term in $3 y' (y^{2} - 4 x) = 12 y - 3 x^{2}$ by $3 (y^{2} - 4 x)$ and simplify.

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Step 5.4.1

Divide each term in $3 y' (y^{2} - 4 x) = 12 y - 3 x^{2}$ by $3 (y^{2} - 4 x)$ .

$\frac{3 y' (y^{2} - 4 x)}{3 (y^{2} - 4 x)} = \frac{12 y}{3 (y^{2} - 4 x)} + \frac{- 3 x^{2}}{3 (y^{2} - 4 x)}$

Step 5.4.2

Simplify the left side.

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Step 5.4.2.1

Cancel the common factor of $3$ .

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Step 5.4.2.1.1

Cancel the common factor.

$\frac{3 y' (y^{2} - 4 x)}{3 (y^{2} - 4 x)} = \frac{12 y}{3 (y^{2} - 4 x)} + \frac{- 3 x^{2}}{3 (y^{2} - 4 x)}$

Step 5.4.2.1.2

Rewrite the expression.

$\frac{y' (y^{2} - 4 x)}{y^{2} - 4 x} = \frac{12 y}{3 (y^{2} - 4 x)} + \frac{- 3 x^{2}}{3 (y^{2} - 4 x)}$

Step 5.4.2.2

Cancel the common factor of $y^{2} - 4 x$ .

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Step 5.4.2.2.1

Cancel the common factor.

$\frac{y' (y^{2} - 4 x)}{y^{2} - 4 x} = \frac{12 y}{3 (y^{2} - 4 x)} + \frac{- 3 x^{2}}{3 (y^{2} - 4 x)}$

Step 5.4.2.2.2

Divide $y'$ by $1$ .

$y' = \frac{12 y}{3 (y^{2} - 4 x)} + \frac{- 3 x^{2}}{3 (y^{2} - 4 x)}$

Step 5.4.3

Simplify the right side.

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Step 5.4.3.1

Simplify each term.

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Step 5.4.3.1.1

Cancel the common factor of $12$ and $3$ .

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Step 5.4.3.1.1.1

Factor $3$ out of $12 y$ .

$y' = \frac{3 (4 y)}{3 (y^{2} - 4 x)} + \frac{- 3 x^{2}}{3 (y^{2} - 4 x)}$

Step 5.4.3.1.1.2

Cancel the common factors.

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Step 5.4.3.1.1.2.1

Cancel the common factor.

$y' = \frac{3 (4 y)}{3 (y^{2} - 4 x)} + \frac{- 3 x^{2}}{3 (y^{2} - 4 x)}$

Step 5.4.3.1.1.2.2

Rewrite the expression.

$y' = \frac{4 y}{y^{2} - 4 x} + \frac{- 3 x^{2}}{3 (y^{2} - 4 x)}$

Step 5.4.3.1.2

Cancel the common factor of $- 3$ and $3$ .

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Step 5.4.3.1.2.1

Factor $3$ out of $- 3 x^{2}$ .

$y' = \frac{4 y}{y^{2} - 4 x} + \frac{3 (- x^{2})}{3 (y^{2} - 4 x)}$

Step 5.4.3.1.2.2

Cancel the common factors.

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Step 5.4.3.1.2.2.1

Cancel the common factor.

$y' = \frac{4 y}{y^{2} - 4 x} + \frac{3 (- x^{2})}{3 (y^{2} - 4 x)}$

Step 5.4.3.1.2.2.2

Rewrite the expression.

$y' = \frac{4 y}{y^{2} - 4 x} + \frac{- x^{2}}{y^{2} - 4 x}$

Step 5.4.3.1.3

Move the negative in front of the fraction.

$y' = \frac{4 y}{y^{2} - 4 x} - \frac{x^{2}}{y^{2} - 4 x}$

Step 5.4.3.2

Combine the numerators over the common denominator.

$y' = \frac{4 y - x^{2}}{y^{2} - 4 x}$

Step 6

Replace $y'$ with $\frac{d y}{d x}$ .

$\frac{d y}{d x} = \frac{4 y - x^{2}}{y^{2} - 4 x}$