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Calculus Examples
Step 1
Step 1.1
Differentiate using the chain rule, which states that is where and .
Step 1.1.1
To apply the Chain Rule, set as .
Step 1.1.2
The derivative of with respect to is .
Step 1.1.3
Replace all occurrences of with .
Step 1.2
Differentiate.
Step 1.2.1
Since is constant with respect to , the derivative of with respect to is .
Step 1.2.2
Differentiate using the Power Rule which states that is where .
Step 1.2.3
Simplify the expression.
Step 1.2.3.1
Multiply by .
Step 1.2.3.2
Reorder the factors of .
Step 2
Step 2.1
Since is constant with respect to , the derivative of with respect to is .
Step 2.2
Differentiate using the chain rule, which states that is where and .
Step 2.2.1
To apply the Chain Rule, set as .
Step 2.2.2
The derivative of with respect to is .
Step 2.2.3
Replace all occurrences of with .
Step 2.3
Since is constant with respect to , the derivative of with respect to is .
Step 2.4
Raise to the power of .
Step 2.5
Raise to the power of .
Step 2.6
Use the power rule to combine exponents.
Step 2.7
Add and .
Step 2.8
Differentiate using the Power Rule which states that is where .
Step 2.9
Multiply by .
Step 3
To find the local maximum and minimum values of the function, set the derivative equal to and solve.
Step 4
Step 4.1
Divide each term in by .
Step 4.2
Simplify the left side.
Step 4.2.1
Dividing two negative values results in a positive value.
Step 4.2.2
Cancel the common factor of .
Step 4.2.2.1
Cancel the common factor.
Step 4.2.2.2
Divide by .
Step 4.3
Simplify the right side.
Step 4.3.1
Divide by .
Step 5
Take the inverse sine of both sides of the equation to extract from inside the sine.
Step 6
Step 6.1
The exact value of is .
Step 7
Step 7.1
Divide each term in by .
Step 7.2
Simplify the left side.
Step 7.2.1
Cancel the common factor of .
Step 7.2.1.1
Cancel the common factor.
Step 7.2.1.2
Divide by .
Step 7.3
Simplify the right side.
Step 7.3.1
Divide by .
Step 8
The sine function is positive in the first and second quadrants. To find the second solution, subtract the reference angle from to find the solution in the second quadrant.
Step 9
Step 9.1
Simplify.
Step 9.1.1
Multiply by .
Step 9.1.2
Add and .
Step 9.2
Divide each term in by and simplify.
Step 9.2.1
Divide each term in by .
Step 9.2.2
Simplify the left side.
Step 9.2.2.1
Cancel the common factor of .
Step 9.2.2.1.1
Cancel the common factor.
Step 9.2.2.1.2
Divide by .
Step 9.2.3
Simplify the right side.
Step 9.2.3.1
Cancel the common factor of .
Step 9.2.3.1.1
Cancel the common factor.
Step 9.2.3.1.2
Rewrite the expression.
Step 10
The solution to the equation .
Step 11
Evaluate the second derivative at . If the second derivative is positive, then this is a local minimum. If it is negative, then this is a local maximum.
Step 12
Step 12.1
Multiply by .
Step 12.2
The exact value of is .
Step 12.3
Multiply by .
Step 13
is a local maximum because the value of the second derivative is negative. This is referred to as the second derivative test.
is a local maximum
Step 14
Step 14.1
Replace the variable with in the expression.
Step 14.2
Simplify the result.
Step 14.2.1
Multiply by .
Step 14.2.2
The exact value of is .
Step 14.2.3
The final answer is .
Step 15
Evaluate the second derivative at . If the second derivative is positive, then this is a local minimum. If it is negative, then this is a local maximum.
Step 16
Step 16.1
Multiply by .
Step 16.2
Apply the reference angle by finding the angle with equivalent trig values in the first quadrant. Make the expression negative because cosine is negative in the second quadrant.
Step 16.3
The exact value of is .
Step 16.4
Multiply by .
Step 16.5
Multiply .
Step 16.5.1
Multiply by .
Step 16.5.2
Multiply by .
Step 17
is a local minimum because the value of the second derivative is positive. This is referred to as the second derivative test.
is a local minimum
Step 18
Step 18.1
Replace the variable with in the expression.
Step 18.2
Simplify the result.
Step 18.2.1
Multiply by .
Step 18.2.2
Apply the reference angle by finding the angle with equivalent trig values in the first quadrant. Make the expression negative because cosine is negative in the second quadrant.
Step 18.2.3
The exact value of is .
Step 18.2.4
Multiply by .
Step 18.2.5
The final answer is .
Step 19
These are the local extrema for .
is a local maxima
is a local minima
Step 20