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Calculus Examples
∫8x2ln(x)dx∫8x2ln(x)dx
Step 1
Since 88 is constant with respect to xx, move 88 out of the integral.
8∫x2ln(x)dx8∫x2ln(x)dx
Step 2
Integrate by parts using the formula ∫udv=uv-∫vdu∫udv=uv−∫vdu, where u=ln(x)u=ln(x) and dv=x2dv=x2.
8(ln(x)(13x3)-∫13x31xdx)8(ln(x)(13x3)−∫13x31xdx)
Step 3
Step 3.1
Combine 1313 and x3x3.
8(ln(x)x33-∫13x31xdx)8(ln(x)x33−∫13x31xdx)
Step 3.2
Combine ln(x)ln(x) and x33x33.
8(ln(x)x33-∫13x31xdx)8(ln(x)x33−∫13x31xdx)
Step 3.3
Combine 1313 and x3x3.
8(ln(x)x33-∫x33⋅1xdx)8(ln(x)x33−∫x33⋅1xdx)
Step 3.4
Multiply x33x33 by 1x1x.
8(ln(x)x33-∫x33xdx)8(ln(x)x33−∫x33xdx)
Step 3.5
Cancel the common factor of x3x3 and xx.
Step 3.5.1
Factor xx out of x3x3.
8(ln(x)x33-∫x⋅x23xdx)8(ln(x)x33−∫x⋅x23xdx)
Step 3.5.2
Cancel the common factors.
Step 3.5.2.1
Factor xx out of 3x3x.
8(ln(x)x33-∫x⋅x2x⋅3dx)8(ln(x)x33−∫x⋅x2x⋅3dx)
Step 3.5.2.2
Cancel the common factor.
8(ln(x)x33-∫x⋅x2x⋅3dx)
Step 3.5.2.3
Rewrite the expression.
8(ln(x)x33-∫x23dx)
8(ln(x)x33-∫x23dx)
8(ln(x)x33-∫x23dx)
8(ln(x)x33-∫x23dx)
Step 4
Since 13 is constant with respect to x, move 13 out of the integral.
8(ln(x)x33-(13∫x2dx))
Step 5
By the Power Rule, the integral of x2 with respect to x is 13x3.
8(ln(x)x33-13(13x3+C))
Step 6
Step 6.1
Combine 13 and x3.
8(ln(x)x33-13(x33+C))
Step 6.2
Rewrite 8(ln(x)x33-13(x33+C)) as 8(ln(x)x33-x39)+C.
8(ln(x)x33-x39)+C
Step 6.3
Reorder terms.
8(13ln(x)x3-19x3)+C
8(13ln(x)x3-19x3)+C