Calculus Examples

Evaluate the Integral integral from 0 to 2 of 3x^2 with respect to x
203x2dx203x2dx
Step 1
Since 33 is constant with respect to xx, move 33 out of the integral.
320x2dx320x2dx
Step 2
By the Power Rule, the integral of x2x2 with respect to xx is 13x313x3.
3(13x3]20)3(13x3]20)
Step 3
Simplify the answer.
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Step 3.1
Combine 1313 and x3x3.
3(x33]20)3(x33]20)
Step 3.2
Substitute and simplify.
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Step 3.2.1
Evaluate x33x33 at 22 and at 00.
3((233)-033)3((233)033)
Step 3.2.2
Simplify.
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Step 3.2.2.1
Raise 22 to the power of 33.
3(83-033)3(83033)
Step 3.2.2.2
Raising 00 to any positive power yields 00.
3(83-03)3(8303)
Step 3.2.2.3
Cancel the common factor of 00 and 33.
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Step 3.2.2.3.1
Factor 33 out of 00.
3(83-3(0)3)3(833(0)3)
Step 3.2.2.3.2
Cancel the common factors.
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Step 3.2.2.3.2.1
Factor 33 out of 33.
3(83-3031)3(833031)
Step 3.2.2.3.2.2
Cancel the common factor.
3(83-3031)
Step 3.2.2.3.2.3
Rewrite the expression.
3(83-01)
Step 3.2.2.3.2.4
Divide 0 by 1.
3(83-0)
3(83-0)
3(83-0)
Step 3.2.2.4
Multiply -1 by 0.
3(83+0)
Step 3.2.2.5
Add 83 and 0.
3(83)
Step 3.2.2.6
Combine 3 and 83.
383
Step 3.2.2.7
Multiply 3 by 8.
243
Step 3.2.2.8
Cancel the common factor of 24 and 3.
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Step 3.2.2.8.1
Factor 3 out of 24.
383
Step 3.2.2.8.2
Cancel the common factors.
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Step 3.2.2.8.2.1
Factor 3 out of 3.
383(1)
Step 3.2.2.8.2.2
Cancel the common factor.
3831
Step 3.2.2.8.2.3
Rewrite the expression.
81
Step 3.2.2.8.2.4
Divide 8 by 1.
8
8
8
8
8
8
Step 4
 [x2  12  π  xdx ]