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Calculus Examples
∫203x2dx∫203x2dx
Step 1
Since 33 is constant with respect to xx, move 33 out of the integral.
3∫20x2dx3∫20x2dx
Step 2
By the Power Rule, the integral of x2x2 with respect to xx is 13x313x3.
3(13x3]20)3(13x3]20)
Step 3
Step 3.1
Combine 1313 and x3x3.
3(x33]20)3(x33]20)
Step 3.2
Substitute and simplify.
Step 3.2.1
Evaluate x33x33 at 22 and at 00.
3((233)-033)3((233)−033)
Step 3.2.2
Simplify.
Step 3.2.2.1
Raise 22 to the power of 33.
3(83-033)3(83−033)
Step 3.2.2.2
Raising 00 to any positive power yields 00.
3(83-03)3(83−03)
Step 3.2.2.3
Cancel the common factor of 00 and 33.
Step 3.2.2.3.1
Factor 33 out of 00.
3(83-3(0)3)3(83−3(0)3)
Step 3.2.2.3.2
Cancel the common factors.
Step 3.2.2.3.2.1
Factor 33 out of 33.
3(83-3⋅03⋅1)3(83−3⋅03⋅1)
Step 3.2.2.3.2.2
Cancel the common factor.
3(83-3⋅03⋅1)
Step 3.2.2.3.2.3
Rewrite the expression.
3(83-01)
Step 3.2.2.3.2.4
Divide 0 by 1.
3(83-0)
3(83-0)
3(83-0)
Step 3.2.2.4
Multiply -1 by 0.
3(83+0)
Step 3.2.2.5
Add 83 and 0.
3(83)
Step 3.2.2.6
Combine 3 and 83.
3⋅83
Step 3.2.2.7
Multiply 3 by 8.
243
Step 3.2.2.8
Cancel the common factor of 24 and 3.
Step 3.2.2.8.1
Factor 3 out of 24.
3⋅83
Step 3.2.2.8.2
Cancel the common factors.
Step 3.2.2.8.2.1
Factor 3 out of 3.
3⋅83(1)
Step 3.2.2.8.2.2
Cancel the common factor.
3⋅83⋅1
Step 3.2.2.8.2.3
Rewrite the expression.
81
Step 3.2.2.8.2.4
Divide 8 by 1.
8
8
8
8
8
8
Step 4