Enter a problem...
Calculus Examples
∫sin(5x)dx
Step 1
Step 1.1
Let u=5x. Find dudx.
Step 1.1.1
Differentiate 5x.
ddx[5x]
Step 1.1.2
Since 5 is constant with respect to x, the derivative of 5x with respect to x is 5ddx[x].
5ddx[x]
Step 1.1.3
Differentiate using the Power Rule which states that ddx[xn] is nxn−1 where n=1.
5⋅1
Step 1.1.4
Multiply 5 by 1.
5
5
Step 1.2
Rewrite the problem using u and du.
∫sin(u)15du
∫sin(u)15du
Step 2
Combine sin(u) and 15.
∫sin(u)5du
Step 3
Since 15 is constant with respect to u, move 15 out of the integral.
15∫sin(u)du
Step 4
The integral of sin(u) with respect to u is −cos(u).
15(−cos(u)+C)
Step 5
Step 5.1
Simplify.
15(−cos(u))+C
Step 5.2
Combine 15 and cos(u).
−cos(u)5+C
−cos(u)5+C
Step 6
Replace all occurrences of u with 5x.
−cos(5x)5+C
Step 7
Reorder terms.
−15cos(5x)+C