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Calculus Examples
∫xe-x2dx∫xe−x2dx
Step 1
Step 1.1
Let u2=e-x2. Find du2dx.
Step 1.1.1
Differentiate e-x2.
ddx[e-x2]
Step 1.1.2
Differentiate using the chain rule, which states that ddx[f(g(x))] is f′(g(x))g′(x) where f(x)=ex and g(x)=-x2.
Step 1.1.2.1
To apply the Chain Rule, set u1 as -x2.
ddu1[eu1]ddx[-x2]
Step 1.1.2.2
Differentiate using the Exponential Rule which states that ddu1[au1] is au1ln(a) where a=e.
eu1ddx[-x2]
Step 1.1.2.3
Replace all occurrences of u1 with -x2.
e-x2ddx[-x2]
e-x2ddx[-x2]
Step 1.1.3
Differentiate.
Step 1.1.3.1
Since -1 is constant with respect to x, the derivative of -x2 with respect to x is -ddx[x2].
e-x2(-ddx[x2])
Step 1.1.3.2
Differentiate using the Power Rule which states that ddx[xn] is nxn-1 where n=2.
e-x2(-(2x))
Step 1.1.3.3
Multiply 2 by -1.
e-x2(-2x)
e-x2(-2x)
Step 1.1.4
Simplify.
Step 1.1.4.1
Reorder the factors of e-x2(-2x).
-2e-x2x
Step 1.1.4.2
Reorder factors in -2e-x2x.
-2xe-x2
-2xe-x2
-2xe-x2
Step 1.2
Rewrite the problem using u2 and du2.
∫1-2du2
∫1-2du2
Step 2
Move the negative in front of the fraction.
∫-12du2
Step 3
Apply the constant rule.
-12u2+C
Step 4
Replace all occurrences of u2 with e-x2.
-12e-x2+C