Calculus Examples

Graph ( natural log of x)/x
ln(x)x
Step 1
Find the asymptotes.
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Step 1.1
Find where the expression ln(x)x is undefined.
x0
Step 1.2
Since ln(x)x as x0 from the left and ln(x)x- as x0 from the right, then x=0 is a vertical asymptote.
x=0
Step 1.3
Ignoring the logarithm, consider the rational function R(x)=axnbxm where n is the degree of the numerator and m is the degree of the denominator.
1. If n<m, then the x-axis, y=0, is the horizontal asymptote.
2. If n=m, then the horizontal asymptote is the line y=ab.
3. If n>m, then there is no horizontal asymptote (there is an oblique asymptote).
Step 1.4
Find n and m.
n=0
m=1
Step 1.5
Since n<m, the x-axis, y=0, is the horizontal asymptote.
y=0
Step 1.6
No oblique asymptotes are present for logarithmic and trigonometric functions.
No Oblique Asymptotes
Step 1.7
This is the set of all asymptotes.
Vertical Asymptotes: x=0
Horizontal Asymptotes: y=0
Vertical Asymptotes: x=0
Horizontal Asymptotes: y=0
Step 2
Find the point at x=1.
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Step 2.1
Replace the variable x with 1 in the expression.
f(1)=ln(1)1
Step 2.2
Simplify the result.
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Step 2.2.1
Divide ln(1) by 1.
f(1)=ln(1)
Step 2.2.2
The natural logarithm of 1 is 0.
f(1)=0
Step 2.2.3
The final answer is 0.
0
0
Step 2.3
Convert 0 to decimal.
y=0
y=0
Step 3
Find the point at x=2.
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Step 3.1
Replace the variable x with 2 in the expression.
f(2)=ln(2)2
Step 3.2
Simplify the result.
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Step 3.2.1
Rewrite ln(2)2 as 12ln(2).
f(2)=12ln(2)
Step 3.2.2
Simplify 12ln(2) by moving 12 inside the logarithm.
f(2)=ln(212)
Step 3.2.3
The final answer is ln(212).
ln(212)
ln(212)
Step 3.3
Convert ln(212) to decimal.
y=0.34657359
y=0.34657359
Step 4
Find the point at x=3.
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Step 4.1
Replace the variable x with 3 in the expression.
f(3)=ln(3)3
Step 4.2
Simplify the result.
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Step 4.2.1
Rewrite ln(3)3 as 13ln(3).
f(3)=13ln(3)
Step 4.2.2
Simplify 13ln(3) by moving 13 inside the logarithm.
f(3)=ln(313)
Step 4.2.3
The final answer is ln(313).
ln(313)
ln(313)
Step 4.3
Convert ln(313) to decimal.
y=0.36620409
y=0.36620409
Step 5
The log function can be graphed using the vertical asymptote at x=0 and the points (1,0),(2,0.34657359),(3,0.36620409).
Vertical Asymptote: x=0
xy1020.34730.366
Step 6
 [x2  12  π  xdx ]