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Calculus Examples
∫x4ln(x)dx∫x4ln(x)dx
Step 1
Integrate by parts using the formula ∫udv=uv-∫vdu∫udv=uv−∫vdu, where u=ln(x)u=ln(x) and dv=x4dv=x4.
ln(x)(15x5)-∫15x51xdxln(x)(15x5)−∫15x51xdx
Step 2
Step 2.1
Combine 1515 and x5x5.
ln(x)x55-∫15x51xdxln(x)x55−∫15x51xdx
Step 2.2
Combine ln(x)ln(x) and x55x55.
ln(x)x55-∫15x51xdxln(x)x55−∫15x51xdx
ln(x)x55-∫15x51xdxln(x)x55−∫15x51xdx
Step 3
Since 1515 is constant with respect to xx, move 1515 out of the integral.
ln(x)x55-(15∫x51xdx)ln(x)x55−(15∫x51xdx)
Step 4
Step 4.1
Combine x5x5 and 1x1x.
ln(x)x55-(15∫x5xdx)ln(x)x55−(15∫x5xdx)
Step 4.2
Cancel the common factor of x5x5 and xx.
Step 4.2.1
Factor xx out of x5x5.
ln(x)x55-(15∫x⋅x4xdx)ln(x)x55−(15∫x⋅x4xdx)
Step 4.2.2
Cancel the common factors.
Step 4.2.2.1
Raise xx to the power of 11.
ln(x)x55-(15∫x⋅x4x1dx)ln(x)x55−(15∫x⋅x4x1dx)
Step 4.2.2.2
Factor xx out of x1x1.
ln(x)x55-(15∫x⋅x4x⋅1dx)ln(x)x55−(15∫x⋅x4x⋅1dx)
Step 4.2.2.3
Cancel the common factor.
ln(x)x55-(15∫x⋅x4x⋅1dx)
Step 4.2.2.4
Rewrite the expression.
ln(x)x55-(15∫x41dx)
Step 4.2.2.5
Divide x4 by 1.
ln(x)x55-(15∫x4dx)
ln(x)x55-(15∫x4dx)
ln(x)x55-15∫x4dx
ln(x)x55-15∫x4dx
Step 5
By the Power Rule, the integral of x4 with respect to x is 15x5.
ln(x)x55-15(15x5+C)
Step 6
Step 6.1
Rewrite ln(x)x55-15(15x5+C) as 15ln(x)x5-15⋅15x5+C.
15ln(x)x5-15⋅15x5+C
Step 6.2
Simplify.
Step 6.2.1
Combine 15 and ln(x).
ln(x)5x5-15⋅15x5+C
Step 6.2.2
Combine ln(x)5 and x5.
ln(x)x55-15⋅15x5+C
Step 6.2.3
Multiply 15 by 15.
ln(x)x55-15⋅5x5+C
Step 6.2.4
Multiply 5 by 5.
ln(x)x55-125x5+C
15ln(x)x5-125x5+C
15ln(x)x5-125x5+C