Calculus Examples

Evaluate the Integral integral from 0 to 2pi of sin(x) with respect to x
02πsin(x)dx
Step 1
The integral of sin(x) with respect to x is -cos(x).
-cos(x)]02π
Step 2
Simplify the answer.
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Step 2.1
Evaluate -cos(x) at 2π and at 0.
-cos(2π)+cos(0)
Step 2.2
The exact value of cos(0) is 1.
-cos(2π)+1
Step 2.3
Simplify.
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Step 2.3.1
Subtract full rotations of 2π until the angle is greater than or equal to 0 and less than 2π.
-cos(0)+1
Step 2.3.2
The exact value of cos(0) is 1.
-11+1
Step 2.3.3
Multiply -1 by 1.
-1+1
Step 2.3.4
Add -1 and 1.
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02πsinxdx
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 [x2  12  π  xdx ]