Calculus Examples

Find the Derivative - d/dx x/(x^2+1)
xx2+1
Step 1
Differentiate using the Quotient Rule which states that ddx[f(x)g(x)] is g(x)ddx[f(x)]-f(x)ddx[g(x)]g(x)2 where f(x)=x and g(x)=x2+1.
(x2+1)ddx[x]-xddx[x2+1](x2+1)2
Step 2
Differentiate.
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Step 2.1
Differentiate using the Power Rule which states that ddx[xn] is nxn-1 where n=1.
(x2+1)1-xddx[x2+1](x2+1)2
Step 2.2
Multiply x2+1 by 1.
x2+1-xddx[x2+1](x2+1)2
Step 2.3
By the Sum Rule, the derivative of x2+1 with respect to x is ddx[x2]+ddx[1].
x2+1-x(ddx[x2]+ddx[1])(x2+1)2
Step 2.4
Differentiate using the Power Rule which states that ddx[xn] is nxn-1 where n=2.
x2+1-x(2x+ddx[1])(x2+1)2
Step 2.5
Since 1 is constant with respect to x, the derivative of 1 with respect to x is 0.
x2+1-x(2x+0)(x2+1)2
Step 2.6
Simplify the expression.
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Step 2.6.1
Add 2x and 0.
x2+1-x(2x)(x2+1)2
Step 2.6.2
Multiply 2 by -1.
x2+1-2xx(x2+1)2
x2+1-2xx(x2+1)2
x2+1-2xx(x2+1)2
Step 3
Raise x to the power of 1.
x2+1-2(x1x)(x2+1)2
Step 4
Raise x to the power of 1.
x2+1-2(x1x1)(x2+1)2
Step 5
Use the power rule aman=am+n to combine exponents.
x2+1-2x1+1(x2+1)2
Step 6
Add 1 and 1.
x2+1-2x2(x2+1)2
Step 7
Subtract 2x2 from x2.
-x2+1(x2+1)2
xx2+1
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