Calculus Examples

g (x) = \frac{1}{12} x^{2} - 9 \sqrt{x}

$g (x) = \frac{1}{12} x^{2} - 9 \sqrt{x}$ on

0

$0$ ,

16

$16$

Step 1

Find the critical points.

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Step 1.1

Find the first derivative.

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Step 1.1.1

Find the first derivative.

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Step 1.1.1.1

By the Sum Rule, the derivative of

\frac{1}{12} x^{2} - 9 \sqrt{x}

$\frac{1}{12} x^{2} - 9 \sqrt{x}$ with respect to

x

$x$ is

\frac{d}{d x} [\frac{1}{12} x^{2}] + \frac{d}{d x} [- 9 \sqrt{x}]

$\frac{d}{d x} [\frac{1}{12} x^{2}] + \frac{d}{d x} [- 9 \sqrt{x}]$ .

\frac{d}{d x} [\frac{1}{12} x^{2}] + \frac{d}{d x} [- 9 \sqrt{x}]

$\frac{d}{d x} [\frac{1}{12} x^{2}] + \frac{d}{d x} [- 9 \sqrt{x}]$

Step 1.1.1.2

Evaluate

\frac{d}{d x} [\frac{1}{12} x^{2}]

$\frac{d}{d x} [\frac{1}{12} x^{2}]$ .

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Step 1.1.1.2.1

Since

\frac{1}{12}

$\frac{1}{12}$ is constant with respect to

x

$x$ , the derivative of

\frac{1}{12} x^{2}

$\frac{1}{12} x^{2}$ with respect to

x

$x$ is

\frac{1}{12} \frac{d}{d x} [x^{2}]

$\frac{1}{12} \frac{d}{d x} [x^{2}]$ .

\frac{1}{12} \frac{d}{d x} [x^{2}] + \frac{d}{d x} [- 9 \sqrt{x}]

$\frac{1}{12} \frac{d}{d x} [x^{2}] + \frac{d}{d x} [- 9 \sqrt{x}]$

Step 1.1.1.2.2

Differentiate using the Power Rule which states that

\frac{d}{d x} [x^{n}]

$\frac{d}{d x} [x^{n}]$ is

n x^{n - 1}

$n x^{n - 1}$ where

n = 2

$n = 2$ .

\frac{1}{12} (2 x) + \frac{d}{d x} [- 9 \sqrt{x}]

$\frac{1}{12} (2 x) + \frac{d}{d x} [- 9 \sqrt{x}]$

Step 1.1.1.2.3

Combine

2

$2$ and

\frac{1}{12}

$\frac{1}{12}$ .

\frac{2}{12} x + \frac{d}{d x} [- 9 \sqrt{x}]

$\frac{2}{12} x + \frac{d}{d x} [- 9 \sqrt{x}]$

Step 1.1.1.2.4

Combine

\frac{2}{12}

$\frac{2}{12}$ and

x

$x$ .

\frac{2 x}{12} + \frac{d}{d x} [- 9 \sqrt{x}]

$\frac{2 x}{12} + \frac{d}{d x} [- 9 \sqrt{x}]$

Step 1.1.1.2.5

Cancel the common factor of

2

$2$ and

12

$12$ .

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Step 1.1.1.2.5.1

Factor

2

$2$ out of

2 x

$2 x$ .

\frac{2 (x)}{12} + \frac{d}{d x} [- 9 \sqrt{x}]

$\frac{2 (x)}{12} + \frac{d}{d x} [- 9 \sqrt{x}]$

Step 1.1.1.2.5.2

Cancel the common factors.

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Step 1.1.1.2.5.2.1

Factor

2

$2$ out of

12

$12$ .

\frac{2 x}{2 \cdot 6} + \frac{d}{d x} [- 9 \sqrt{x}]

$\frac{2 x}{2 \cdot 6} + \frac{d}{d x} [- 9 \sqrt{x}]$

Step 1.1.1.2.5.2.2

Cancel the common factor.

$\frac{2 x}{2 \cdot 6} + \frac{d}{d x} [- 9 \sqrt{x}]$

Step 1.1.1.2.5.2.3

Rewrite the expression.

$\frac{x}{6} + \frac{d}{d x} [- 9 \sqrt{x}]$

Step 1.1.1.3

Evaluate

$\frac{d}{d x} [- 9 \sqrt{x}]$ .

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Step 1.1.1.3.1

Use

$\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite

$\sqrt{x}$ as

$x^{\frac{1}{2}}$ .

$\frac{x}{6} + \frac{d}{d x} [- 9 x^{\frac{1}{2}}]$

Step 1.1.1.3.2

Since

$- 9$ is constant with respect to

$x$ , the derivative of

$- 9 x^{\frac{1}{2}}$ with respect to

$x$ is

$- 9 \frac{d}{d x} [x^{\frac{1}{2}}]$ .

$\frac{x}{6} - 9 \frac{d}{d x} [x^{\frac{1}{2}}]$

Step 1.1.1.3.3

Differentiate using the Power Rule which states that

$\frac{d}{d x} [x^{n}]$ is

$n x^{n - 1}$ where

$n = \frac{1}{2}$ .

$\frac{x}{6} - 9 (\frac{1}{2} x^{\frac{1}{2} - 1})$

Step 1.1.1.3.4

To write

$- 1$ as a fraction with a common denominator, multiply by

$\frac{2}{2}$ .

$\frac{x}{6} - 9 (\frac{1}{2} x^{\frac{1}{2} - 1 \cdot \frac{2}{2}})$

Step 1.1.1.3.5

Combine

$- 1$ and

$\frac{2}{2}$ .

$\frac{x}{6} - 9 (\frac{1}{2} x^{\frac{1}{2} + \frac{- 1 \cdot 2}{2}})$

Step 1.1.1.3.6

Combine the numerators over the common denominator.

$\frac{x}{6} - 9 (\frac{1}{2} x^{\frac{1 - 1 \cdot 2}{2}})$

Step 1.1.1.3.7

Simplify the numerator.

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Step 1.1.1.3.7.1

Multiply

$- 1$ by

$2$ .

$\frac{x}{6} - 9 (\frac{1}{2} x^{\frac{1 - 2}{2}})$

Step 1.1.1.3.7.2

Subtract

$2$ from

$1$ .

$\frac{x}{6} - 9 (\frac{1}{2} x^{\frac{- 1}{2}})$

Step 1.1.1.3.8

Move the negative in front of the fraction.

$\frac{x}{6} - 9 (\frac{1}{2} x^{- \frac{1}{2}})$

Step 1.1.1.3.9

Combine

$\frac{1}{2}$ and

$x^{- \frac{1}{2}}$ .

$\frac{x}{6} - 9 \frac{x^{- \frac{1}{2}}}{2}$

Step 1.1.1.3.10

Combine

$- 9$ and

$\frac{x^{- \frac{1}{2}}}{2}$ .

$\frac{x}{6} + \frac{- 9 x^{- \frac{1}{2}}}{2}$

Step 1.1.1.3.11

Move

$x^{- \frac{1}{2}}$ to the denominator using the negative exponent rule

$b^{- n} = \frac{1}{b^{n}}$ .

$\frac{x}{6} + \frac{- 9}{2 x^{\frac{1}{2}}}$

Step 1.1.1.3.12

Move the negative in front of the fraction.

$f' (x) = \frac{x}{6} - \frac{9}{2 x^{\frac{1}{2}}}$

Step 1.1.2

The first derivative of

$g (x)$ with respect to

$x$ is

$\frac{x}{6} - \frac{9}{2 x^{\frac{1}{2}}}$ .

$\frac{x}{6} - \frac{9}{2 x^{\frac{1}{2}}}$

Step 1.2

Set the first derivative equal to

$0$ then solve the equation

$\frac{x}{6} - \frac{9}{2 x^{\frac{1}{2}}} = 0$ .

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Step 1.2.1

Set the first derivative equal to

$0$ .

$\frac{x}{6} - \frac{9}{2 x^{\frac{1}{2}}} = 0$

Step 1.2.2

Find the LCD of the terms in the equation.

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Step 1.2.2.1

Finding the LCD of a list of values is the same as finding the LCM of the denominators of those values.

$6, 2 x^{\frac{1}{2}}, 1$

Step 1.2.2.2

Since

$6, 2 x^{\frac{1}{2}}, 1$ contains both numbers and variables, there are two steps to find the LCM. Find LCM for the numeric part

$6, 2, 1$ then find LCM for the variable part

$x^{\frac{1}{2}}$ .

Step 1.2.2.3

The LCM is the smallest positive number that all of the numbers divide into evenly.

1. List the prime factors of each number.

2. Multiply each factor the greatest number of times it occurs in either number.

Step 1.2.2.4

$6$ has factors of

$2$ and

$3$ .

$2 \cdot 3$

Step 1.2.2.5

Since

$2$ has no factors besides

$1$ and

$2$ .

$2$ is a prime number

Step 1.2.2.6

The number

$1$ is not a prime number because it only has one positive factor, which is itself.

Not prime

Step 1.2.2.7

The LCM of

$6, 2, 1$ is the result of multiplying all prime factors the greatest number of times they occur in either number.

$2 \cdot 3$

Step 1.2.2.8

Multiply

$2$ by

$3$ .

$6$

Step 1.2.2.9

The LCM of

$x^{\frac{1}{2}}$ is the result of multiplying all prime factors the greatest number of times they occur in either term.

$x^{\frac{1}{2}}$

Step 1.2.2.10

The LCM for

$6, 2 x^{\frac{1}{2}}, 1$ is the numeric part

$6$ multiplied by the variable part.

$6 x^{\frac{1}{2}}$

Step 1.2.3

Multiply each term in

$\frac{x}{6} - \frac{9}{2 x^{\frac{1}{2}}} = 0$ by

$6 x^{\frac{1}{2}}$ to eliminate the fractions.

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Step 1.2.3.1

Multiply each term in

$\frac{x}{6} - \frac{9}{2 x^{\frac{1}{2}}} = 0$ by

$6 x^{\frac{1}{2}}$ .

$\frac{x}{6} (6 x^{\frac{1}{2}}) - \frac{9}{2 x^{\frac{1}{2}}} (6 x^{\frac{1}{2}}) = 0 (6 x^{\frac{1}{2}})$

Step 1.2.3.2

Simplify the left side.

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Step 1.2.3.2.1

Simplify each term.

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Step 1.2.3.2.1.1

Rewrite using the commutative property of multiplication.

$6 \frac{x}{6} x^{\frac{1}{2}} - \frac{9}{2 x^{\frac{1}{2}}} (6 x^{\frac{1}{2}}) = 0 (6 x^{\frac{1}{2}})$

Step 1.2.3.2.1.2

Cancel the common factor of

$6$ .

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Step 1.2.3.2.1.2.1

Cancel the common factor.

$6 \frac{x}{6} x^{\frac{1}{2}} - \frac{9}{2 x^{\frac{1}{2}}} (6 x^{\frac{1}{2}}) = 0 (6 x^{\frac{1}{2}})$

Step 1.2.3.2.1.2.2

Rewrite the expression.

$x \cdot x^{\frac{1}{2}} - \frac{9}{2 x^{\frac{1}{2}}} (6 x^{\frac{1}{2}}) = 0 (6 x^{\frac{1}{2}})$

Step 1.2.3.2.1.3

Multiply

$x$ by

$x^{\frac{1}{2}}$ by adding the exponents.

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Step 1.2.3.2.1.3.1

Multiply

$x$ by

$x^{\frac{1}{2}}$ .

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Step 1.2.3.2.1.3.1.1

Raise

$x$ to the power of

$1$ .

$x^{1} x^{\frac{1}{2}} - \frac{9}{2 x^{\frac{1}{2}}} (6 x^{\frac{1}{2}}) = 0 (6 x^{\frac{1}{2}})$

Step 1.2.3.2.1.3.1.2

Use the power rule

$a^{m} a^{n} = a^{m + n}$ to combine exponents.

$x^{1 + \frac{1}{2}} - \frac{9}{2 x^{\frac{1}{2}}} (6 x^{\frac{1}{2}}) = 0 (6 x^{\frac{1}{2}})$

Step 1.2.3.2.1.3.2

Write

$1$ as a fraction with a common denominator.

$x^{\frac{2}{2} + \frac{1}{2}} - \frac{9}{2 x^{\frac{1}{2}}} (6 x^{\frac{1}{2}}) = 0 (6 x^{\frac{1}{2}})$

Step 1.2.3.2.1.3.3

Combine the numerators over the common denominator.

$x^{\frac{2 + 1}{2}} - \frac{9}{2 x^{\frac{1}{2}}} (6 x^{\frac{1}{2}}) = 0 (6 x^{\frac{1}{2}})$

Step 1.2.3.2.1.3.4

Add

$2$ and

$1$ .

$x^{\frac{3}{2}} - \frac{9}{2 x^{\frac{1}{2}}} (6 x^{\frac{1}{2}}) = 0 (6 x^{\frac{1}{2}})$

Step 1.2.3.2.1.4

Cancel the common factor of

$2 x^{\frac{1}{2}}$ .

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Step 1.2.3.2.1.4.1

Move the leading negative in

$- \frac{9}{2 x^{\frac{1}{2}}}$ into the numerator.

$x^{\frac{3}{2}} + \frac{- 9}{2 x^{\frac{1}{2}}} (6 x^{\frac{1}{2}}) = 0 (6 x^{\frac{1}{2}})$

Step 1.2.3.2.1.4.2

Factor

$2 x^{\frac{1}{2}}$ out of

$6 x^{\frac{1}{2}}$ .

$x^{\frac{3}{2}} + \frac{- 9}{2 x^{\frac{1}{2}}} (2 x^{\frac{1}{2}} (3)) = 0 (6 x^{\frac{1}{2}})$

Step 1.2.3.2.1.4.3

Cancel the common factor.

$x^{\frac{3}{2}} + \frac{- 9}{2 x^{\frac{1}{2}}} (2 x^{\frac{1}{2}} \cdot 3) = 0 (6 x^{\frac{1}{2}})$

Step 1.2.3.2.1.4.4

Rewrite the expression.

$x^{\frac{3}{2}} - 9 \cdot 3 = 0 (6 x^{\frac{1}{2}})$

Step 1.2.3.2.1.5

Multiply

$- 9$ by

$3$ .

$x^{\frac{3}{2}} - 27 = 0 (6 x^{\frac{1}{2}})$

Step 1.2.3.3

Simplify the right side.

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Step 1.2.3.3.1

Multiply

$0 (6 x^{\frac{1}{2}})$ .

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Step 1.2.3.3.1.1

Multiply

$6$ by

$0$ .

$x^{\frac{3}{2}} - 27 = 0 x^{\frac{1}{2}}$

Step 1.2.3.3.1.2

Multiply

$0$ by

$x^{\frac{1}{2}}$ .

$x^{\frac{3}{2}} - 27 = 0$

Step 1.2.4

Solve the equation.

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Step 1.2.4.1

Add

$27$ to both sides of the equation.

$x^{\frac{3}{2}} = 27$

Step 1.2.4.2

Raise each side of the equation to the power of

$\frac{2}{3}$ to eliminate the fractional exponent on the left side.

${(x^{\frac{3}{2}})}^{\frac{2}{3}} = 27^{\frac{2}{3}}$

Step 1.2.4.3

Simplify the exponent.

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Step 1.2.4.3.1

Simplify the left side.

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Step 1.2.4.3.1.1

Simplify

${(x^{\frac{3}{2}})}^{\frac{2}{3}}$ .

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Step 1.2.4.3.1.1.1

Multiply the exponents in

${(x^{\frac{3}{2}})}^{\frac{2}{3}}$ .

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Step 1.2.4.3.1.1.1.1

Apply the power rule and multiply exponents,

${(a^{m})}^{n} = a^{m n}$ .

$x^{\frac{3}{2} \cdot \frac{2}{3}} = 27^{\frac{2}{3}}$

Step 1.2.4.3.1.1.1.2

Cancel the common factor of

$3$ .

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Step 1.2.4.3.1.1.1.2.1

Cancel the common factor.

$x^{\frac{3}{2} \cdot \frac{2}{3}} = 27^{\frac{2}{3}}$

Step 1.2.4.3.1.1.1.2.2

Rewrite the expression.

$x^{\frac{1}{2} \cdot 2} = 27^{\frac{2}{3}}$

Step 1.2.4.3.1.1.1.3

Cancel the common factor of

$2$ .

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Step 1.2.4.3.1.1.1.3.1

Cancel the common factor.

$x^{\frac{1}{2} \cdot 2} = 27^{\frac{2}{3}}$

Step 1.2.4.3.1.1.1.3.2

Rewrite the expression.

$x^{1} = 27^{\frac{2}{3}}$

Step 1.2.4.3.1.1.2

Simplify.

$x = 27^{\frac{2}{3}}$

Step 1.2.4.3.2

Simplify the right side.

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Step 1.2.4.3.2.1

Simplify

$27^{\frac{2}{3}}$ .

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Step 1.2.4.3.2.1.1

Simplify the expression.

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Step 1.2.4.3.2.1.1.1

Rewrite

$27$ as

$3^{3}$ .

$x = {(3^{3})}^{\frac{2}{3}}$

Step 1.2.4.3.2.1.1.2

Apply the power rule and multiply exponents,

${(a^{m})}^{n} = a^{m n}$ .

$x = 3^{3 (\frac{2}{3})}$

Step 1.2.4.3.2.1.2

Cancel the common factor of

$3$ .

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Step 1.2.4.3.2.1.2.1

Cancel the common factor.

$x = 3^{3 (\frac{2}{3})}$

Step 1.2.4.3.2.1.2.2

Rewrite the expression.

$x = 3^{2}$

Step 1.2.4.3.2.1.3

Raise

$3$ to the power of

$2$ .

$x = 9$

Step 1.3

Find the values where the derivative is undefined.

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Step 1.3.1

Convert expressions with fractional exponents to radicals.

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Step 1.3.1.1

Apply the rule

$x^{\frac{m}{n}} = \sqrt[n]{x^{m}}$ to rewrite the exponentiation as a radical.

$\frac{x}{6} - \frac{9}{2 \sqrt{x^{1}}}$

Step 1.3.1.2

Anything raised to

$1$ is the base itself.

$\frac{x}{6} - \frac{9}{2 \sqrt{x}}$

Step 1.3.2

Set the denominator in

$\frac{9}{2 \sqrt{x}}$ equal to

$0$ to find where the expression is undefined.

$2 \sqrt{x} = 0$

Step 1.3.3

Solve for

$x$ .

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Step 1.3.3.1

To remove the radical on the left side of the equation, square both sides of the equation.

${(2 \sqrt{x})}^{2} = 0^{2}$

Step 1.3.3.2

Simplify each side of the equation.

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Step 1.3.3.2.1

Use

$\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite

$\sqrt{x}$ as

$x^{\frac{1}{2}}$ .

${(2 x^{\frac{1}{2}})}^{2} = 0^{2}$

Step 1.3.3.2.2

Simplify the left side.

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Step 1.3.3.2.2.1

Simplify

${(2 x^{\frac{1}{2}})}^{2}$ .

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Step 1.3.3.2.2.1.1

Apply the product rule to

$2 x^{\frac{1}{2}}$ .

$2^{2} {(x^{\frac{1}{2}})}^{2} = 0^{2}$

Step 1.3.3.2.2.1.2

Raise

$2$ to the power of

$2$ .

$4 {(x^{\frac{1}{2}})}^{2} = 0^{2}$

Step 1.3.3.2.2.1.3

Multiply the exponents in

${(x^{\frac{1}{2}})}^{2}$ .

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Step 1.3.3.2.2.1.3.1

Apply the power rule and multiply exponents,

${(a^{m})}^{n} = a^{m n}$ .

$4 x^{\frac{1}{2} \cdot 2} = 0^{2}$

Step 1.3.3.2.2.1.3.2

Cancel the common factor of

$2$ .

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Step 1.3.3.2.2.1.3.2.1

Cancel the common factor.

$4 x^{\frac{1}{2} \cdot 2} = 0^{2}$

Step 1.3.3.2.2.1.3.2.2

Rewrite the expression.

$4 x^{1} = 0^{2}$

Step 1.3.3.2.2.1.4

Simplify.

$4 x = 0^{2}$

Step 1.3.3.2.3

Simplify the right side.

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Step 1.3.3.2.3.1

Raising

$0$ to any positive power yields

$0$ .

$4 x = 0$

Step 1.3.3.3

Divide each term in

$4 x = 0$ by

$4$ and simplify.

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Step 1.3.3.3.1

Divide each term in

$4 x = 0$ by

$4$ .

$\frac{4 x}{4} = \frac{0}{4}$

Step 1.3.3.3.2

Simplify the left side.

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Step 1.3.3.3.2.1

Cancel the common factor of

$4$ .

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Step 1.3.3.3.2.1.1

Cancel the common factor.

$\frac{4 x}{4} = \frac{0}{4}$

Step 1.3.3.3.2.1.2

Divide

$x$ by

$1$ .

$x = \frac{0}{4}$

Step 1.3.3.3.3

Simplify the right side.

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Step 1.3.3.3.3.1

Divide

$0$ by

$4$ .

$x = 0$

Step 1.3.4

Set the radicand in

$\sqrt{x}$ less than

$0$ to find where the expression is undefined.

$x < 0$

Step 1.3.5

The equation is undefined where the denominator equals

$0$ , the argument of a square root is less than

$0$ , or the argument of a logarithm is less than or equal to

$0$ .

$x \leq 0$

$(- \infty, 0]$

$x \leq 0$

$(- \infty, 0]$

Step 1.4

Evaluate

$\frac{1}{12} x^{2} - 9 \sqrt{x}$ at each

$x$ value where the derivative is

$0$ or undefined.

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Step 1.4.1

Evaluate at

$x = 9$ .

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Step 1.4.1.1

Substitute

$9$ for

$x$ .

$\frac{1}{12} \cdot {(9)}^{2} - 9 \sqrt{9}$

Step 1.4.1.2

Simplify.

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Step 1.4.1.2.1

Simplify each term.

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Step 1.4.1.2.1.1

Raise

$9$ to the power of

$2$ .

$\frac{1}{12} \cdot 81 - 9 \sqrt{9}$

Step 1.4.1.2.1.2

Cancel the common factor of

$3$ .

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Step 1.4.1.2.1.2.1

Factor

$3$ out of

$12$ .

$\frac{1}{3 (4)} \cdot 81 - 9 \sqrt{9}$

Step 1.4.1.2.1.2.2

Factor

$3$ out of

$81$ .

$\frac{1}{3 \cdot 4} \cdot (3 \cdot 27) - 9 \sqrt{9}$

Step 1.4.1.2.1.2.3

Cancel the common factor.

$\frac{1}{3 \cdot 4} \cdot (3 \cdot 27) - 9 \sqrt{9}$

Step 1.4.1.2.1.2.4

Rewrite the expression.

$\frac{1}{4} \cdot 27 - 9 \sqrt{9}$

Step 1.4.1.2.1.3

Combine

$\frac{1}{4}$ and

$27$ .

$\frac{27}{4} - 9 \sqrt{9}$

Step 1.4.1.2.1.4

Rewrite

$9$ as

$3^{2}$ .

$\frac{27}{4} - 9 \sqrt{3^{2}}$

Step 1.4.1.2.1.5

Pull terms out from under the radical, assuming positive real numbers.

$\frac{27}{4} - 9 \cdot 3$

Step 1.4.1.2.1.6

Multiply

$- 9$ by

$3$ .

$\frac{27}{4} - 27$

Step 1.4.1.2.2

To write

$- 27$ as a fraction with a common denominator, multiply by

$\frac{4}{4}$ .

$\frac{27}{4} - 27 \cdot \frac{4}{4}$

Step 1.4.1.2.3

Combine

$- 27$ and

$\frac{4}{4}$ .

$\frac{27}{4} + \frac{- 27 \cdot 4}{4}$

Step 1.4.1.2.4

Combine the numerators over the common denominator.

$\frac{27 - 27 \cdot 4}{4}$

Step 1.4.1.2.5

Simplify the numerator.

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Step 1.4.1.2.5.1

Multiply

$- 27$ by

$4$ .

$\frac{27 - 108}{4}$

Step 1.4.1.2.5.2

Subtract

$108$ from

$27$ .

$\frac{- 81}{4}$

Step 1.4.1.2.6

Move the negative in front of the fraction.

$- \frac{81}{4}$

Step 1.4.2

Evaluate at

$x = 0$ .

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Step 1.4.2.1

Substitute

$0$ for

$x$ .

$\frac{1}{12} \cdot {(0)}^{2} - 9 \sqrt{0}$

Step 1.4.2.2

Simplify.

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Step 1.4.2.2.1

Simplify each term.

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Step 1.4.2.2.1.1

Raising

$0$ to any positive power yields

$0$ .

$\frac{1}{12} \cdot 0 - 9 \sqrt{0}$

Step 1.4.2.2.1.2

Multiply

$\frac{1}{12}$ by

$0$ .

$0 - 9 \sqrt{0}$

Step 1.4.2.2.1.3

Rewrite

$0$ as

$0^{2}$ .

$0 - 9 \sqrt{0^{2}}$

Step 1.4.2.2.1.4

Pull terms out from under the radical, assuming positive real numbers.

$0 - 9 \cdot 0$

Step 1.4.2.2.1.5

Multiply

$- 9$ by

$0$ .

$0 + 0$

Step 1.4.2.2.2

Add

$0$ and

$0$ .

$0$

Step 1.4.3

List all of the points.

$(9, - \frac{81}{4}), (0, 0)$

Step 2

Evaluate at the included endpoints.

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Step 2.1

Evaluate at

$x = 0$ .

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Step 2.1.1

Substitute

$0$ for

$x$ .

$\frac{1}{12} \cdot {(0)}^{2} - 9 \sqrt{0}$

Step 2.1.2

Simplify.

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Step 2.1.2.1

Simplify each term.

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Step 2.1.2.1.1

Raising

$0$ to any positive power yields

$0$ .

$\frac{1}{12} \cdot 0 - 9 \sqrt{0}$

Step 2.1.2.1.2

Multiply

$\frac{1}{12}$ by

$0$ .

$0 - 9 \sqrt{0}$

Step 2.1.2.1.3

Rewrite

$0$ as

$0^{2}$ .

$0 - 9 \sqrt{0^{2}}$

Step 2.1.2.1.4

Pull terms out from under the radical, assuming positive real numbers.

$0 - 9 \cdot 0$

Step 2.1.2.1.5

Multiply

$- 9$ by

$0$ .

$0 + 0$

Step 2.1.2.2

Add

$0$ and

$0$ .

$0$

Step 2.2

Evaluate at

$x = 16$ .

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Step 2.2.1

Substitute

$16$ for

$x$ .

$\frac{1}{12} \cdot {(16)}^{2} - 9 \sqrt{16}$

Step 2.2.2

Simplify.

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Step 2.2.2.1

Simplify each term.

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Step 2.2.2.1.1

Raise

$16$ to the power of

$2$ .

$\frac{1}{12} \cdot 256 - 9 \sqrt{16}$

Step 2.2.2.1.2

Cancel the common factor of

$4$ .

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Step 2.2.2.1.2.1

Factor

$4$ out of

$12$ .

$\frac{1}{4 (3)} \cdot 256 - 9 \sqrt{16}$

Step 2.2.2.1.2.2

Factor

$4$ out of

$256$ .

$\frac{1}{4 \cdot 3} \cdot (4 \cdot 64) - 9 \sqrt{16}$

Step 2.2.2.1.2.3

Cancel the common factor.

$\frac{1}{4 \cdot 3} \cdot (4 \cdot 64) - 9 \sqrt{16}$

Step 2.2.2.1.2.4

Rewrite the expression.

$\frac{1}{3} \cdot 64 - 9 \sqrt{16}$

Step 2.2.2.1.3

Combine

$\frac{1}{3}$ and

$64$ .

$\frac{64}{3} - 9 \sqrt{16}$

Step 2.2.2.1.4

Rewrite

$16$ as

$4^{2}$ .

$\frac{64}{3} - 9 \sqrt{4^{2}}$

Step 2.2.2.1.5

Pull terms out from under the radical, assuming positive real numbers.

$\frac{64}{3} - 9 \cdot 4$

Step 2.2.2.1.6

Multiply

$- 9$ by

$4$ .

$\frac{64}{3} - 36$

Step 2.2.2.2

To write

$- 36$ as a fraction with a common denominator, multiply by

$\frac{3}{3}$ .

$\frac{64}{3} - 36 \cdot \frac{3}{3}$

Step 2.2.2.3

Combine

$- 36$ and

$\frac{3}{3}$ .

$\frac{64}{3} + \frac{- 36 \cdot 3}{3}$

Step 2.2.2.4

Combine the numerators over the common denominator.

$\frac{64 - 36 \cdot 3}{3}$

Step 2.2.2.5

Simplify the numerator.

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Step 2.2.2.5.1

Multiply

$- 36$ by

$3$ .

$\frac{64 - 108}{3}$

Step 2.2.2.5.2

Subtract

$108$ from

$64$ .

$\frac{- 44}{3}$

Step 2.2.2.6

Move the negative in front of the fraction.

$- \frac{44}{3}$

Step 2.3

List all of the points.

$(0, 0), (16, - \frac{44}{3})$

Step 3

Compare the

$g (x)$ values found for each value of

$x$ in order to determine the absolute maximum and minimum over the given interval. The maximum will occur at the highest

$g (x)$ value and the minimum will occur at the lowest

$g (x)$ value.

Absolute Maximum:

$(0, 0)$

Absolute Minimum:

$(9, - \frac{81}{4})$

Step 4