Calculus Examples

f (x) = x e^{\frac{x}{2}}

$f (x) = x e^{\frac{x}{2}}$ ,

[- 3, 1]

$[- 3, 1]$

Step 1

Find the critical points.

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Step 1.1

Find the first derivative.

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Step 1.1.1

Find the first derivative.

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Step 1.1.1.1

Differentiate using the Product Rule which states that

\frac{d}{d x} [f (x) g (x)]

$\frac{d}{d x} [f (x) g (x)]$ is

f (x) \frac{d}{d x} [g (x)] + g (x) \frac{d}{d x} [f (x)]

$f (x) \frac{d}{d x} [g (x)] + g (x) \frac{d}{d x} [f (x)]$ where

f (x) = x

$f (x) = x$ and

g (x) = e^{\frac{x}{2}}

$g (x) = e^{\frac{x}{2}}$ .

x \frac{d}{d x} [e^{\frac{x}{2}}] + e^{\frac{x}{2}} \frac{d}{d x} [x]

$x \frac{d}{d x} [e^{\frac{x}{2}}] + e^{\frac{x}{2}} \frac{d}{d x} [x]$

Step 1.1.1.2

Differentiate using the chain rule, which states that

\frac{d}{d x} [f (g (x))]

$\frac{d}{d x} [f (g (x))]$ is

f' (g (x)) g' (x)

$f' (g (x)) g' (x)$ where

f (x) = e^{x}

$f (x) = e^{x}$ and

g (x) = \frac{x}{2}

$g (x) = \frac{x}{2}$ .

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Step 1.1.1.2.1

To apply the Chain Rule, set

u

$u$ as

\frac{x}{2}

$\frac{x}{2}$ .

x (\frac{d}{d u} [e^{u}] \frac{d}{d x} [\frac{x}{2}]) + e^{\frac{x}{2}} \frac{d}{d x} [x]

$x (\frac{d}{d u} [e^{u}] \frac{d}{d x} [\frac{x}{2}]) + e^{\frac{x}{2}} \frac{d}{d x} [x]$

Step 1.1.1.2.2

Differentiate using the Exponential Rule which states that

\frac{d}{d u} [a^{u}]

$\frac{d}{d u} [a^{u}]$ is

a^{u} ln (a)

$a^{u} \ln (a)$ where

a

$a$ =

e

$e$ .

x (e^{u} \frac{d}{d x} [\frac{x}{2}]) + e^{\frac{x}{2}} \frac{d}{d x} [x]

$x (e^{u} \frac{d}{d x} [\frac{x}{2}]) + e^{\frac{x}{2}} \frac{d}{d x} [x]$

Step 1.1.1.2.3

Replace all occurrences of

u

$u$ with

\frac{x}{2}

$\frac{x}{2}$ .

x (e^{\frac{x}{2}} \frac{d}{d x} [\frac{x}{2}]) + e^{\frac{x}{2}} \frac{d}{d x} [x]

$x (e^{\frac{x}{2}} \frac{d}{d x} [\frac{x}{2}]) + e^{\frac{x}{2}} \frac{d}{d x} [x]$

x (e^{\frac{x}{2}} \frac{d}{d x} [\frac{x}{2}]) + e^{\frac{x}{2}} \frac{d}{d x} [x]

$x (e^{\frac{x}{2}} \frac{d}{d x} [\frac{x}{2}]) + e^{\frac{x}{2}} \frac{d}{d x} [x]$

Step 1.1.1.3

Differentiate.

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Step 1.1.1.3.1

Since

\frac{1}{2}

$\frac{1}{2}$ is constant with respect to

x

$x$ , the derivative of

\frac{x}{2}

$\frac{x}{2}$ with respect to

x

$x$ is

\frac{1}{2} \frac{d}{d x} [x]

$\frac{1}{2} \frac{d}{d x} [x]$ .

x (e^{\frac{x}{2}} (\frac{1}{2} \frac{d}{d x} [x])) + e^{\frac{x}{2}} \frac{d}{d x} [x]

$x (e^{\frac{x}{2}} (\frac{1}{2} \frac{d}{d x} [x])) + e^{\frac{x}{2}} \frac{d}{d x} [x]$

Step 1.1.1.3.2

Combine fractions.

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Step 1.1.1.3.2.1

Combine

\frac{1}{2}

$\frac{1}{2}$ and

e^{\frac{x}{2}}

$e^{\frac{x}{2}}$ .

x (\frac{e^{\frac{x}{2}}}{2} \frac{d}{d x} [x]) + e^{\frac{x}{2}} \frac{d}{d x} [x]

$x (\frac{e^{\frac{x}{2}}}{2} \frac{d}{d x} [x]) + e^{\frac{x}{2}} \frac{d}{d x} [x]$

Step 1.1.1.3.2.2

Combine

\frac{e^{\frac{x}{2}}}{2}

$\frac{e^{\frac{x}{2}}}{2}$ and

x

$x$ .

\frac{e^{\frac{x}{2}} x}{2} \frac{d}{d x} [x] + e^{\frac{x}{2}} \frac{d}{d x} [x]

$\frac{e^{\frac{x}{2}} x}{2} \frac{d}{d x} [x] + e^{\frac{x}{2}} \frac{d}{d x} [x]$

\frac{e^{\frac{x}{2}} x}{2} \frac{d}{d x} [x] + e^{\frac{x}{2}} \frac{d}{d x} [x]

$\frac{e^{\frac{x}{2}} x}{2} \frac{d}{d x} [x] + e^{\frac{x}{2}} \frac{d}{d x} [x]$

Step 1.1.1.3.3

Differentiate using the Power Rule which states that

\frac{d}{d x} [x^{n}]

$\frac{d}{d x} [x^{n}]$ is

n x^{n - 1}

$n x^{n - 1}$ where

n = 1

$n = 1$ .

\frac{e^{\frac{x}{2}} x}{2} \cdot 1 + e^{\frac{x}{2}} \frac{d}{d x} [x]

$\frac{e^{\frac{x}{2}} x}{2} \cdot 1 + e^{\frac{x}{2}} \frac{d}{d x} [x]$

Step 1.1.1.3.4

Multiply

\frac{e^{\frac{x}{2}} x}{2}

$\frac{e^{\frac{x}{2}} x}{2}$ by

1

$1$ .

\frac{e^{\frac{x}{2}} x}{2} + e^{\frac{x}{2}} \frac{d}{d x} [x]

$\frac{e^{\frac{x}{2}} x}{2} + e^{\frac{x}{2}} \frac{d}{d x} [x]$

Step 1.1.1.3.5

Differentiate using the Power Rule which states that

\frac{d}{d x} [x^{n}]

$\frac{d}{d x} [x^{n}]$ is

n x^{n - 1}

$n x^{n - 1}$ where

n = 1

$n = 1$ .

\frac{e^{\frac{x}{2}} x}{2} + e^{\frac{x}{2}} \cdot 1

$\frac{e^{\frac{x}{2}} x}{2} + e^{\frac{x}{2}} \cdot 1$

Step 1.1.1.3.6

Simplify the expression.

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Step 1.1.1.3.6.1

Multiply

e^{\frac{x}{2}}

$e^{\frac{x}{2}}$ by

1

$1$ .

\frac{e^{\frac{x}{2}} x}{2} + e^{\frac{x}{2}}

$\frac{e^{\frac{x}{2}} x}{2} + e^{\frac{x}{2}}$

Step 1.1.1.3.6.2

Reorder factors in

\frac{e^{\frac{x}{2}} x}{2} + e^{\frac{x}{2}}

$\frac{e^{\frac{x}{2}} x}{2} + e^{\frac{x}{2}}$ .

f' (x) = \frac{x e^{\frac{x}{2}}}{2} + e^{\frac{x}{2}}

$f' (x) = \frac{x e^{\frac{x}{2}}}{2} + e^{\frac{x}{2}}$

f' (x) = \frac{x e^{\frac{x}{2}}}{2} + e^{\frac{x}{2}}

$f' (x) = \frac{x e^{\frac{x}{2}}}{2} + e^{\frac{x}{2}}$

f' (x) = \frac{x e^{\frac{x}{2}}}{2} + e^{\frac{x}{2}}

$f' (x) = \frac{x e^{\frac{x}{2}}}{2} + e^{\frac{x}{2}}$

f' (x) = \frac{x e^{\frac{x}{2}}}{2} + e^{\frac{x}{2}}

$f' (x) = \frac{x e^{\frac{x}{2}}}{2} + e^{\frac{x}{2}}$

Step 1.1.2

The first derivative of

f (x)

$f (x)$ with respect to

x

$x$ is

\frac{x e^{\frac{x}{2}}}{2} + e^{\frac{x}{2}}

$\frac{x e^{\frac{x}{2}}}{2} + e^{\frac{x}{2}}$ .

\frac{x e^{\frac{x}{2}}}{2} + e^{\frac{x}{2}}

$\frac{x e^{\frac{x}{2}}}{2} + e^{\frac{x}{2}}$

\frac{x e^{\frac{x}{2}}}{2} + e^{\frac{x}{2}}

$\frac{x e^{\frac{x}{2}}}{2} + e^{\frac{x}{2}}$

Step 1.2

Set the first derivative equal to

0

$0$ then solve the equation

\frac{x e^{\frac{x}{2}}}{2} + e^{\frac{x}{2}} = 0

$\frac{x e^{\frac{x}{2}}}{2} + e^{\frac{x}{2}} = 0$ .

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Step 1.2.1

Set the first derivative equal to

0

$0$ .

\frac{x e^{\frac{x}{2}}}{2} + e^{\frac{x}{2}} = 0

$\frac{x e^{\frac{x}{2}}}{2} + e^{\frac{x}{2}} = 0$

Step 1.2.2

Factor

e^{\frac{x}{2}}

$e^{\frac{x}{2}}$ out of

\frac{x e^{\frac{x}{2}}}{2} + e^{\frac{x}{2}}

$\frac{x e^{\frac{x}{2}}}{2} + e^{\frac{x}{2}}$ .

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Step 1.2.2.1

Factor

e^{\frac{x}{2}}

$e^{\frac{x}{2}}$ out of

\frac{x e^{\frac{x}{2}}}{2}

$\frac{x e^{\frac{x}{2}}}{2}$ .

e^{\frac{x}{2}} (\frac{x}{2}) + e^{\frac{x}{2}} = 0

$e^{\frac{x}{2}} (\frac{x}{2}) + e^{\frac{x}{2}} = 0$

Step 1.2.2.2

Multiply by

1

$1$ .

e^{\frac{x}{2}} (\frac{x}{2}) + e^{\frac{x}{2}} \cdot 1 = 0

$e^{\frac{x}{2}} (\frac{x}{2}) + e^{\frac{x}{2}} \cdot 1 = 0$

Step 1.2.2.3

Factor

e^{\frac{x}{2}}

$e^{\frac{x}{2}}$ out of

e^{\frac{x}{2}} \frac{x}{2} + e^{\frac{x}{2}} \cdot 1

$e^{\frac{x}{2}} \frac{x}{2} + e^{\frac{x}{2}} \cdot 1$ .

e^{\frac{x}{2}} (\frac{x}{2} + 1) = 0

$e^{\frac{x}{2}} (\frac{x}{2} + 1) = 0$

e^{\frac{x}{2}} (\frac{x}{2} + 1) = 0

$e^{\frac{x}{2}} (\frac{x}{2} + 1) = 0$

Step 1.2.3

If any individual factor on the left side of the equation is equal to

0

$0$ , the entire expression will be equal to

0

$0$ .

e^{\frac{x}{2}} = 0

$e^{\frac{x}{2}} = 0$

\frac{x}{2} + 1 = 0

$\frac{x}{2} + 1 = 0$

Step 1.2.4

Set

e^{\frac{x}{2}}

$e^{\frac{x}{2}}$ equal to

0

$0$ and solve for

x

$x$ .

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Step 1.2.4.1

Set

$e^{\frac{x}{2}}$ equal to

$0$ .

$e^{\frac{x}{2}} = 0$

Step 1.2.4.2

Solve

$e^{\frac{x}{2}} = 0$ for

$x$ .

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Step 1.2.4.2.1

Take the natural logarithm of both sides of the equation to remove the variable from the exponent.

$\ln (e^{\frac{x}{2}}) = \ln (0)$

Step 1.2.4.2.2

The equation cannot be solved because

$\ln (0)$ is undefined.

Undefined

Step 1.2.4.2.3

There is no solution for

$e^{\frac{x}{2}} = 0$

No solution

Step 1.2.5

Set

$\frac{x}{2} + 1$ equal to

$0$ and solve for

$x$ .

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Step 1.2.5.1

Set

$\frac{x}{2} + 1$ equal to

$0$ .

$\frac{x}{2} + 1 = 0$

Step 1.2.5.2

Solve

$\frac{x}{2} + 1 = 0$ for

$x$ .

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Step 1.2.5.2.1

Subtract

$1$ from both sides of the equation.

$\frac{x}{2} = - 1$

Step 1.2.5.2.2

Multiply both sides of the equation by

$2$ .

$2 \frac{x}{2} = 2 \cdot - 1$

Step 1.2.5.2.3

Simplify both sides of the equation.

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Step 1.2.5.2.3.1

Simplify the left side.

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Step 1.2.5.2.3.1.1

Cancel the common factor of

$2$ .

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Step 1.2.5.2.3.1.1.1

Cancel the common factor.

$2 \frac{x}{2} = 2 \cdot - 1$

Step 1.2.5.2.3.1.1.2

Rewrite the expression.

$x = 2 \cdot - 1$

Step 1.2.5.2.3.2

Simplify the right side.

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Step 1.2.5.2.3.2.1

Multiply

$2$ by

$- 1$ .

$x = - 2$

Step 1.2.6

The final solution is all the values that make

$e^{\frac{x}{2}} (\frac{x}{2} + 1) = 0$ true.

$x = - 2$

Step 1.3

Find the values where the derivative is undefined.

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Step 1.3.1

The domain of the expression is all real numbers except where the expression is undefined. In this case, there is no real number that makes the expression undefined.

Step 1.4

Evaluate

$x e^{\frac{x}{2}}$ at each

$x$ value where the derivative is

$0$ or undefined.

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Step 1.4.1

Evaluate at

$x = - 2$ .

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Step 1.4.1.1

Substitute

$- 2$ for

$x$ .

$(- 2) \cdot e^{\frac{- 2}{2}}$

Step 1.4.1.2

Simplify.

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Step 1.4.1.2.1

Divide

$- 2$ by

$2$ .

$- 2 \cdot e^{- 1}$

Step 1.4.1.2.2

Rewrite the expression using the negative exponent rule

$b^{- n} = \frac{1}{b^{n}}$ .

$- 2 \cdot \frac{1}{e}$

Step 1.4.1.2.3

Combine

$- 2$ and

$\frac{1}{e}$ .

$\frac{- 2}{e}$

Step 1.4.1.2.4

Move the negative in front of the fraction.

$- \frac{2}{e}$

Step 1.4.2

List all of the points.

$(- 2, - \frac{2}{e})$

Step 2

Evaluate at the included endpoints.

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Step 2.1

Evaluate at

$x = - 3$ .

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Step 2.1.1

Substitute

$- 3$ for

$x$ .

$(- 3) \cdot e^{\frac{- 3}{2}}$

Step 2.1.2

Simplify.

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Step 2.1.2.1

Move the negative in front of the fraction.

$- 3 \cdot e^{- \frac{3}{2}}$

Step 2.1.2.2

Rewrite the expression using the negative exponent rule

$b^{- n} = \frac{1}{b^{n}}$ .

$- 3 \cdot \frac{1}{e^{\frac{3}{2}}}$

Step 2.1.2.3

Combine

$- 3$ and

$\frac{1}{e^{\frac{3}{2}}}$ .

$\frac{- 3}{e^{\frac{3}{2}}}$

Step 2.1.2.4

Move the negative in front of the fraction.

$- \frac{3}{e^{\frac{3}{2}}}$

Step 2.2

Evaluate at

$x = 1$ .

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Step 2.2.1

Substitute

$1$ for

$x$ .

$(1) \cdot e^{\frac{1}{2}}$

Step 2.2.2

Multiply

$e^{\frac{1}{2}}$ by

$1$ .

$e^{\frac{1}{2}}$

Step 2.3

List all of the points.

$(- 3, - \frac{3}{e^{\frac{3}{2}}}), (1, e^{\frac{1}{2}})$

Step 3

Compare the

$f (x)$ values found for each value of

$x$ in order to determine the absolute maximum and minimum over the given interval. The maximum will occur at the highest

$f (x)$ value and the minimum will occur at the lowest

$f (x)$ value.

Absolute Maximum:

$(1, e^{\frac{1}{2}})$

Absolute Minimum:

$(- 2, - \frac{2}{e})$

Step 4