Calculus Examples

Find the Absolute Max and Min over the Interval f(x)=1/x , x>=1
f(x)=1xf(x)=1x , x1x1
Step 1
Find the critical points.
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Step 1.1
Find the first derivative.
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Step 1.1.1
Find the first derivative.
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Step 1.1.1.1
Rewrite 1x1x as x-1x1.
ddx[x-1]ddx[x1]
Step 1.1.1.2
Differentiate using the Power Rule which states that ddx[xn]ddx[xn] is nxn-1nxn1 where n=-1n=1.
-x-2x2
Step 1.1.1.3
Rewrite the expression using the negative exponent rule b-n=1bnbn=1bn.
f(x)=-1x2
f(x)=-1x2
Step 1.1.2
The first derivative of f(x) with respect to x is -1x2.
-1x2
-1x2
Step 1.2
Set the first derivative equal to 0 then solve the equation -1x2=0.
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Step 1.2.1
Set the first derivative equal to 0.
-1x2=0
Step 1.2.2
Set the numerator equal to zero.
1=0
Step 1.2.3
Since 10, there are no solutions.
No solution
No solution
Step 1.3
Find the values where the derivative is undefined.
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Step 1.3.1
Set the denominator in 1x2 equal to 0 to find where the expression is undefined.
x2=0
Step 1.3.2
Solve for x.
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Step 1.3.2.1
Take the specified root of both sides of the equation to eliminate the exponent on the left side.
x=±0
Step 1.3.2.2
Simplify ±0.
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Step 1.3.2.2.1
Rewrite 0 as 02.
x=±02
Step 1.3.2.2.2
Pull terms out from under the radical, assuming positive real numbers.
x=±0
Step 1.3.2.2.3
Plus or minus 0 is 0.
x=0
x=0
x=0
x=0
Step 1.4
Evaluate 1x at each x value where the derivative is 0 or undefined.
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Step 1.4.1
Evaluate at x=0.
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Step 1.4.1.1
Substitute 0 for x.
10
Step 1.4.1.2
The expression contains a division by 0. The expression is undefined.
Undefined
Undefined
Undefined
Step 1.5
There are no values of x in the domain of the original problem where the derivative is 0 or undefined.
No critical points found
No critical points found
Step 2
Evaluate at the included endpoints.
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Step 2.1
Evaluate at x=1.
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Step 2.1.1
Substitute 1 for x.
11
Step 2.1.2
Divide 1 by 1.
1
1
Step 2.2
List all of the points.
(1,1)
(1,1)
Step 3
Since there is no value of x that makes the first derivative equal to 0, there are no local extrema.
No Local Extrema
Step 4
Compare the f(x) values found for each value of x in order to determine the absolute maximum and minimum over the given interval. The maximum will occur at the highest f(x) value and the minimum will occur at the lowest f(x) value.
Absolute Maximum: (1,1)
No absolute minimum
Step 5
 [x2  12  π  xdx ]