Calculus Examples

f (x) = sin (x) + cos (x)

$f (x) = \sin (x) + \cos (x)$ ,

0 \leq x \leq 2 π

$0 \leq x \leq 2 π$

Step 1

Find the critical points.

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Step 1.1

Find the first derivative.

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Step 1.1.1

Find the first derivative.

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Step 1.1.1.1

By the Sum Rule, the derivative of

sin (x) + cos (x)

$\sin (x) + \cos (x)$ with respect to

x

$x$ is

\frac{d}{d x} [sin (x)] + \frac{d}{d x} [cos (x)]

$\frac{d}{d x} [\sin (x)] + \frac{d}{d x} [\cos (x)]$ .

\frac{d}{d x} [sin (x)] + \frac{d}{d x} [cos (x)]

$\frac{d}{d x} [\sin (x)] + \frac{d}{d x} [\cos (x)]$

Step 1.1.1.2

The derivative of

sin (x)

$\sin (x)$ with respect to

x

$x$ is

cos (x)

$\cos (x)$ .

cos (x) + \frac{d}{d x} [cos (x)]

$\cos (x) + \frac{d}{d x} [\cos (x)]$

Step 1.1.1.3

The derivative of

cos (x)

$\cos (x)$ with respect to

x

$x$ is

- sin (x)

$- \sin (x)$ .

$f' (x) = \cos (x) - \sin (x)$

Step 1.1.2

The first derivative of

$f (x)$ with respect to

$x$ is

$\cos (x) - \sin (x)$ .

$\cos (x) - \sin (x)$

Step 1.2

Set the first derivative equal to

$0$ then solve the equation

$\cos (x) - \sin (x) = 0$ .

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Step 1.2.1

Set the first derivative equal to

$0$ .

$\cos (x) - \sin (x) = 0$

Step 1.2.2

Divide each term in the equation by

$\cos (x)$ .

$\frac{\cos (x)}{\cos (x)} + \frac{- \sin (x)}{\cos (x)} = \frac{0}{\cos (x)}$

Step 1.2.3

Cancel the common factor of

$\cos (x)$ .

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Step 1.2.3.1

Cancel the common factor.

$\frac{\cos (x)}{\cos (x)} + \frac{- \sin (x)}{\cos (x)} = \frac{0}{\cos (x)}$

Step 1.2.3.2

Rewrite the expression.

$1 + \frac{- \sin (x)}{\cos (x)} = \frac{0}{\cos (x)}$

Step 1.2.4

Separate fractions.

$1 + \frac{- 1}{1} \cdot \frac{\sin (x)}{\cos (x)} = \frac{0}{\cos (x)}$

Step 1.2.5

Convert from

$\frac{\sin (x)}{\cos (x)}$ to

$\tan (x)$ .

$1 + \frac{- 1}{1} \cdot \tan (x) = \frac{0}{\cos (x)}$

Step 1.2.6

Divide

$- 1$ by

$1$ .

$1 - \tan (x) = \frac{0}{\cos (x)}$

Step 1.2.7

Separate fractions.

$1 - \tan (x) = \frac{0}{1} \cdot \frac{1}{\cos (x)}$

Step 1.2.8

Convert from

$\frac{1}{\cos (x)}$ to

$\sec (x)$ .

$1 - \tan (x) = \frac{0}{1} \cdot \sec (x)$

Step 1.2.9

Divide

$0$ by

$1$ .

$1 - \tan (x) = 0 \sec (x)$

Step 1.2.10

Multiply

$0$ by

$\sec (x)$ .

$1 - \tan (x) = 0$

Step 1.2.11

Subtract

$1$ from both sides of the equation.

$- \tan (x) = - 1$

Step 1.2.12

Divide each term in

$- \tan (x) = - 1$ by

$- 1$ and simplify.

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Step 1.2.12.1

Divide each term in

$- \tan (x) = - 1$ by

$- 1$ .

$\frac{- \tan (x)}{- 1} = \frac{- 1}{- 1}$

Step 1.2.12.2

Simplify the left side.

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Step 1.2.12.2.1

Dividing two negative values results in a positive value.

$\frac{\tan (x)}{1} = \frac{- 1}{- 1}$

Step 1.2.12.2.2

Divide

$\tan (x)$ by

$1$ .

$\tan (x) = \frac{- 1}{- 1}$

Step 1.2.12.3

Simplify the right side.

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Step 1.2.12.3.1

Divide

$- 1$ by

$- 1$ .

$\tan (x) = 1$

Step 1.2.13

Take the inverse tangent of both sides of the equation to extract

$x$ from inside the tangent.

$x = \arctan (1)$

Step 1.2.14

Simplify the right side.

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Step 1.2.14.1

The exact value of

$\arctan (1)$ is

$\frac{π}{4}$ .

$x = \frac{π}{4}$

Step 1.2.15

The tangent function is positive in the first and third quadrants. To find the second solution, add the reference angle from

$π$ to find the solution in the fourth quadrant.

$x = π + \frac{π}{4}$

Step 1.2.16

Simplify

$π + \frac{π}{4}$ .

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Step 1.2.16.1

To write

$π$ as a fraction with a common denominator, multiply by

$\frac{4}{4}$ .

$x = π \cdot \frac{4}{4} + \frac{π}{4}$

Step 1.2.16.2

Combine fractions.

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Step 1.2.16.2.1

Combine

$π$ and

$\frac{4}{4}$ .

$x = \frac{π \cdot 4}{4} + \frac{π}{4}$

Step 1.2.16.2.2

Combine the numerators over the common denominator.

$x = \frac{π \cdot 4 + π}{4}$

Step 1.2.16.3

Simplify the numerator.

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Step 1.2.16.3.1

Move

$4$ to the left of

$π$ .

$x = \frac{4 \cdot π + π}{4}$

Step 1.2.16.3.2

Add

$4 π$ and

$π$ .

$x = \frac{5 π}{4}$

Step 1.2.17

Find the period of

$\tan (x)$ .

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Step 1.2.17.1

The period of the function can be calculated using

$\frac{π}{| b |}$ .

$\frac{π}{| b |}$

Step 1.2.17.2

Replace

$b$ with

$1$ in the formula for period.

$\frac{π}{| 1 |}$

Step 1.2.17.3

The absolute value is the distance between a number and zero. The distance between

$0$ and

$1$ is

$1$ .

$\frac{π}{1}$

Step 1.2.17.4

Divide

$π$ by

$1$ .

$π$

Step 1.2.18

The period of the

$\tan (x)$ function is

$π$ so values will repeat every

$π$ radians in both directions.

$x = \frac{π}{4} + π n, \frac{5 π}{4} + π n$ , for any integer

$n$

$x = \frac{π}{4} + π n, \frac{5 π}{4} + π n$ , for any integer

$n$

Step 1.3

Find the values where the derivative is undefined.

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Step 1.3.1

The domain of the expression is all real numbers except where the expression is undefined. In this case, there is no real number that makes the expression undefined.

Step 1.4

Evaluate

$\sin (x) + \cos (x)$ at each

$x$ value where the derivative is

$0$ or undefined.

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Step 1.4.1

Evaluate at

$x = \frac{π}{4}$ .

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Step 1.4.1.1

Substitute

$\frac{π}{4}$ for

$x$ .

$\sin (\frac{π}{4}) + \cos (\frac{π}{4})$

Step 1.4.1.2

Simplify.

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Step 1.4.1.2.1

Simplify each term.

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Step 1.4.1.2.1.1

The exact value of

$\sin (\frac{π}{4})$ is

$\frac{\sqrt{2}}{2}$ .

$\frac{\sqrt{2}}{2} + \cos (\frac{π}{4})$

Step 1.4.1.2.1.2

The exact value of

$\cos (\frac{π}{4})$ is

$\frac{\sqrt{2}}{2}$ .

$\frac{\sqrt{2}}{2} + \frac{\sqrt{2}}{2}$

Step 1.4.1.2.2

Simplify terms.

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Step 1.4.1.2.2.1

Combine the numerators over the common denominator.

$\frac{\sqrt{2} + \sqrt{2}}{2}$

Step 1.4.1.2.2.2

Add

$\sqrt{2}$ and

$\sqrt{2}$ .

$\frac{2 \sqrt{2}}{2}$

Step 1.4.1.2.2.3

Cancel the common factor of

$2$ .

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Step 1.4.1.2.2.3.1

Cancel the common factor.

$\frac{2 \sqrt{2}}{2}$

Step 1.4.1.2.2.3.2

Divide

$\sqrt{2}$ by

$1$ .

$\sqrt{2}$

Step 1.4.2

Evaluate at

$x = \frac{5 π}{4}$ .

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Step 1.4.2.1

Substitute

$\frac{5 π}{4}$ for

$x$ .

$\sin (\frac{5 π}{4}) + \cos (\frac{5 π}{4})$

Step 1.4.2.2

Simplify.

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Step 1.4.2.2.1

Simplify each term.

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Step 1.4.2.2.1.1

Apply the reference angle by finding the angle with equivalent trig values in the first quadrant. Make the expression negative because sine is negative in the third quadrant.

$- \sin (\frac{π}{4}) + \cos (\frac{5 π}{4})$

Step 1.4.2.2.1.2

The exact value of

$\sin (\frac{π}{4})$ is

$\frac{\sqrt{2}}{2}$ .

$- \frac{\sqrt{2}}{2} + \cos (\frac{5 π}{4})$

Step 1.4.2.2.1.3

Apply the reference angle by finding the angle with equivalent trig values in the first quadrant. Make the expression negative because cosine is negative in the third quadrant.

$- \frac{\sqrt{2}}{2} - \cos (\frac{π}{4})$

Step 1.4.2.2.1.4

The exact value of

$\cos (\frac{π}{4})$ is

$\frac{\sqrt{2}}{2}$ .

$- \frac{\sqrt{2}}{2} - \frac{\sqrt{2}}{2}$

Step 1.4.2.2.2

Simplify terms.

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Step 1.4.2.2.2.1

Combine the numerators over the common denominator.

$\frac{- \sqrt{2} - \sqrt{2}}{2}$

Step 1.4.2.2.2.2

Subtract

$\sqrt{2}$ from

$- \sqrt{2}$ .

$\frac{- 2 \sqrt{2}}{2}$

Step 1.4.2.2.2.3

Cancel the common factor of

$- 2$ and

$2$ .

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Step 1.4.2.2.2.3.1

Factor

$2$ out of

$- 2 \sqrt{2}$ .

$\frac{2 (- \sqrt{2})}{2}$

Step 1.4.2.2.2.3.2

Cancel the common factors.

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Step 1.4.2.2.2.3.2.1

Factor

$2$ out of

$2$ .

$\frac{2 (- \sqrt{2})}{2 (1)}$

Step 1.4.2.2.2.3.2.2

Cancel the common factor.

$\frac{2 (- \sqrt{2})}{2 \cdot 1}$

Step 1.4.2.2.2.3.2.3

Rewrite the expression.

$\frac{- \sqrt{2}}{1}$

Step 1.4.2.2.2.3.2.4

Divide

$- \sqrt{2}$ by

$1$ .

$- \sqrt{2}$

Step 1.4.3

List all of the points.

$(\frac{π}{4} + 2 π n, \sqrt{2}), (\frac{5 π}{4} + 2 π n, - \sqrt{2})$ , for any integer

$n$

$(\frac{π}{4} + 2 π n, \sqrt{2}), (\frac{5 π}{4} + 2 π n, - \sqrt{2})$ , for any integer

$n$

$(\frac{π}{4} + 2 π n, \sqrt{2}), (\frac{5 π}{4} + 2 π n, - \sqrt{2})$ , for any integer

$n$

Step 2

Exclude the points that are not on the interval.

$(\frac{π}{4}, \sqrt{2}), (\frac{5 π}{4}, - \sqrt{2})$

Step 3

Evaluate at the included endpoints.

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Step 3.1

Evaluate at

$x = 0$ .

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Step 3.1.1

Substitute

$0$ for

$x$ .

$\sin (0) + \cos (0)$

Step 3.1.2

Simplify.

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Step 3.1.2.1

Simplify each term.

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Step 3.1.2.1.1

The exact value of

$\sin (0)$ is

$0$ .

$0 + \cos (0)$

Step 3.1.2.1.2

The exact value of

$\cos (0)$ is

$1$ .

$0 + 1$

Step 3.1.2.2

Add

$0$ and

$1$ .

$1$

Step 3.2

Evaluate at

$x = 2 π$ .

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Step 3.2.1

Substitute

$2 π$ for

$x$ .

$\sin (2 π) + \cos (2 π)$

Step 3.2.2

Simplify.

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Step 3.2.2.1

Simplify each term.

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Step 3.2.2.1.1

Subtract full rotations of

$2 π$ until the angle is greater than or equal to

$0$ and less than

$2 π$ .

$\sin (0) + \cos (2 π)$

Step 3.2.2.1.2

The exact value of

$\sin (0)$ is

$0$ .

$0 + \cos (2 π)$

Step 3.2.2.1.3

Subtract full rotations of

$2 π$ until the angle is greater than or equal to

$0$ and less than

$2 π$ .

$0 + \cos (0)$

Step 3.2.2.1.4

The exact value of

$\cos (0)$ is

$1$ .

$0 + 1$

Step 3.2.2.2

Add

$0$ and

$1$ .

$1$

Step 3.3

List all of the points.

$(0, 1), (2 π, 1)$

Step 4

Compare the

$f (x)$ values found for each value of

$x$ in order to determine the absolute maximum and minimum over the given interval. The maximum will occur at the highest

$f (x)$ value and the minimum will occur at the lowest

$f (x)$ value.

Absolute Maximum:

$(\frac{π}{4}, \sqrt{2})$

Absolute Minimum:

$(\frac{5 π}{4}, - \sqrt{2})$

Step 5