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Calculus Examples
y=x2y=x2
Step 1
Differentiate using the Power Rule which states that ddx[xn]ddx[xn] is nxn-1nxn−1 where n=2n=2.
2x2x
Step 2
Step 2.1
Since 22 is constant with respect to xx, the derivative of 2x2x with respect to xx is 2ddx[x]2ddx[x].
f′′(x)=2ddx(x)
Step 2.2
Differentiate using the Power Rule which states that ddx[xn] is nxn-1 where n=1.
f′′(x)=2⋅1
Step 2.3
Multiply 2 by 1.
f′′(x)=2
f′′(x)=2
Step 3
To find the local maximum and minimum values of the function, set the derivative equal to 0 and solve.
2x=0
Step 4
Step 4.1
Differentiate using the Power Rule which states that ddx[xn] is nxn-1 where n=2.
f′(x)=2x
Step 4.2
The first derivative of f(x) with respect to x is 2x.
2x
2x
Step 5
Step 5.1
Set the first derivative equal to 0.
2x=0
Step 5.2
Divide each term in 2x=0 by 2 and simplify.
Step 5.2.1
Divide each term in 2x=0 by 2.
2x2=02
Step 5.2.2
Simplify the left side.
Step 5.2.2.1
Cancel the common factor of 2.
Step 5.2.2.1.1
Cancel the common factor.
2x2=02
Step 5.2.2.1.2
Divide x by 1.
x=02
x=02
x=02
Step 5.2.3
Simplify the right side.
Step 5.2.3.1
Divide 0 by 2.
x=0
x=0
x=0
x=0
Step 6
Step 6.1
The domain of the expression is all real numbers except where the expression is undefined. In this case, there is no real number that makes the expression undefined.
Step 7
Critical points to evaluate.
x=0
Step 8
Evaluate the second derivative at x=0. If the second derivative is positive, then this is a local minimum. If it is negative, then this is a local maximum.
2
Step 9
x=0 is a local minimum because the value of the second derivative is positive. This is referred to as the second derivative test.
x=0 is a local minimum
Step 10
Step 10.1
Replace the variable x with 0 in the expression.
f(0)=(0)2
Step 10.2
Simplify the result.
Step 10.2.1
Raising 0 to any positive power yields 0.
f(0)=0
Step 10.2.2
The final answer is 0.
y=0
y=0
y=0
Step 11
These are the local extrema for f(x)=x2.
(0,0) is a local minima
Step 12