Calculus Examples

Find the Tangent Line at (-1,1) y=(2x)/(x-1) at (-1,1)
y=2xx-1y=2xx1 at (-1,1)(1,1)
Step 1
Find the first derivative and evaluate at x=-1x=1 and y=1y=1 to find the slope of the tangent line.
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Step 1.1
Since 22 is constant with respect to xx, the derivative of 2xx-12xx1 with respect to xx is 2ddx[xx-1]2ddx[xx1].
2ddx[xx-1]2ddx[xx1]
Step 1.2
Differentiate using the Quotient Rule which states that ddx[f(x)g(x)]ddx[f(x)g(x)] is g(x)ddx[f(x)]-f(x)ddx[g(x)]g(x)2g(x)ddx[f(x)]f(x)ddx[g(x)]g(x)2 where f(x)=xf(x)=x and g(x)=x-1g(x)=x1.
2(x-1)ddx[x]-xddx[x-1](x-1)22(x1)ddx[x]xddx[x1](x1)2
Step 1.3
Differentiate.
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Step 1.3.1
Differentiate using the Power Rule which states that ddx[xn] is nxn-1 where n=1.
2(x-1)1-xddx[x-1](x-1)2
Step 1.3.2
Multiply x-1 by 1.
2x-1-xddx[x-1](x-1)2
Step 1.3.3
By the Sum Rule, the derivative of x-1 with respect to x is ddx[x]+ddx[-1].
2x-1-x(ddx[x]+ddx[-1])(x-1)2
Step 1.3.4
Differentiate using the Power Rule which states that ddx[xn] is nxn-1 where n=1.
2x-1-x(1+ddx[-1])(x-1)2
Step 1.3.5
Since -1 is constant with respect to x, the derivative of -1 with respect to x is 0.
2x-1-x(1+0)(x-1)2
Step 1.3.6
Simplify terms.
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Step 1.3.6.1
Add 1 and 0.
2x-1-x1(x-1)2
Step 1.3.6.2
Multiply -1 by 1.
2x-1-x(x-1)2
Step 1.3.6.3
Subtract x from x.
20-1(x-1)2
Step 1.3.6.4
Simplify the expression.
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Step 1.3.6.4.1
Subtract 1 from 0.
2-1(x-1)2
Step 1.3.6.4.2
Move the negative in front of the fraction.
2(-1(x-1)2)
Step 1.3.6.4.3
Multiply -1 by 2.
-21(x-1)2
-21(x-1)2
Step 1.3.6.5
Combine -2 and 1(x-1)2.
-2(x-1)2
Step 1.3.6.6
Move the negative in front of the fraction.
-2(x-1)2
-2(x-1)2
-2(x-1)2
Step 1.4
Evaluate the derivative at x=-1.
-2((-1)-1)2
Step 1.5
Simplify.
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Step 1.5.1
Simplify the denominator.
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Step 1.5.1.1
Subtract 1 from -1.
-2(-2)2
Step 1.5.1.2
Raise -2 to the power of 2.
-24
-24
Step 1.5.2
Cancel the common factor of 2 and 4.
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Step 1.5.2.1
Factor 2 out of 2.
-2(1)4
Step 1.5.2.2
Cancel the common factors.
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Step 1.5.2.2.1
Factor 2 out of 4.
-2122
Step 1.5.2.2.2
Cancel the common factor.
-2122
Step 1.5.2.2.3
Rewrite the expression.
-12
-12
-12
-12
-12
Step 2
Plug the slope and point values into the point-slope formula and solve for y.
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Step 2.1
Use the slope -12 and a given point (-1,1) to substitute for x1 and y1 in the point-slope form y-y1=m(x-x1), which is derived from the slope equation m=y2-y1x2-x1.
y-(1)=-12(x-(-1))
Step 2.2
Simplify the equation and keep it in point-slope form.
y-1=-12(x+1)
Step 2.3
Solve for y.
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Step 2.3.1
Simplify -12(x+1).
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Step 2.3.1.1
Rewrite.
y-1=0+0-12(x+1)
Step 2.3.1.2
Simplify by adding zeros.
y-1=-12(x+1)
Step 2.3.1.3
Apply the distributive property.
y-1=-12x-121
Step 2.3.1.4
Combine x and 12.
y-1=-x2-121
Step 2.3.1.5
Multiply -1 by 1.
y-1=-x2-12
y-1=-x2-12
Step 2.3.2
Move all terms not containing y to the right side of the equation.
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Step 2.3.2.1
Add 1 to both sides of the equation.
y=-x2-12+1
Step 2.3.2.2
Write 1 as a fraction with a common denominator.
y=-x2-12+22
Step 2.3.2.3
Combine the numerators over the common denominator.
y=-x2+-1+22
Step 2.3.2.4
Add -1 and 2.
y=-x2+12
y=-x2+12
Step 2.3.3
Write in y=mx+b form.
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Step 2.3.3.1
Reorder terms.
y=-(12x)+12
Step 2.3.3.2
Remove parentheses.
y=-12x+12
y=-12x+12
y=-12x+12
y=-12x+12
Step 3
 [x2  12  π  xdx ]