Calculus Examples

Find the Tangent Line at (2,4) y=x^3-3x+2 , (2,4)
y=x3-3x+2 , (2,4)
Step 1
Find the first derivative and evaluate at x=2 and y=4 to find the slope of the tangent line.
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Step 1.1
Differentiate.
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Step 1.1.1
By the Sum Rule, the derivative of x3-3x+2 with respect to x is ddx[x3]+ddx[-3x]+ddx[2].
ddx[x3]+ddx[-3x]+ddx[2]
Step 1.1.2
Differentiate using the Power Rule which states that ddx[xn] is nxn-1 where n=3.
3x2+ddx[-3x]+ddx[2]
3x2+ddx[-3x]+ddx[2]
Step 1.2
Evaluate ddx[-3x].
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Step 1.2.1
Since -3 is constant with respect to x, the derivative of -3x with respect to x is -3ddx[x].
3x2-3ddx[x]+ddx[2]
Step 1.2.2
Differentiate using the Power Rule which states that ddx[xn] is nxn-1 where n=1.
3x2-31+ddx[2]
Step 1.2.3
Multiply -3 by 1.
3x2-3+ddx[2]
3x2-3+ddx[2]
Step 1.3
Differentiate using the Constant Rule.
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Step 1.3.1
Since 2 is constant with respect to x, the derivative of 2 with respect to x is 0.
3x2-3+0
Step 1.3.2
Add 3x2-3 and 0.
3x2-3
3x2-3
Step 1.4
Evaluate the derivative at x=2.
3(2)2-3
Step 1.5
Simplify.
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Step 1.5.1
Simplify each term.
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Step 1.5.1.1
Raise 2 to the power of 2.
34-3
Step 1.5.1.2
Multiply 3 by 4.
12-3
12-3
Step 1.5.2
Subtract 3 from 12.
9
9
9
Step 2
Plug the slope and point values into the point-slope formula and solve for y.
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Step 2.1
Use the slope 9 and a given point (2,4) to substitute for x1 and y1 in the point-slope form y-y1=m(x-x1), which is derived from the slope equation m=y2-y1x2-x1.
y-(4)=9(x-(2))
Step 2.2
Simplify the equation and keep it in point-slope form.
y-4=9(x-2)
Step 2.3
Solve for y.
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Step 2.3.1
Simplify 9(x-2).
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Step 2.3.1.1
Rewrite.
y-4=0+0+9(x-2)
Step 2.3.1.2
Simplify by adding zeros.
y-4=9(x-2)
Step 2.3.1.3
Apply the distributive property.
y-4=9x+9-2
Step 2.3.1.4
Multiply 9 by -2.
y-4=9x-18
y-4=9x-18
Step 2.3.2
Move all terms not containing y to the right side of the equation.
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Step 2.3.2.1
Add 4 to both sides of the equation.
y=9x-18+4
Step 2.3.2.2
Add -18 and 4.
y=9x-14
y=9x-14
y=9x-14
y=9x-14
Step 3
 [x2  12  π  xdx ]