Calculus Examples

$f (x) = \sqrt{x + 8}$ , $(8, 4)$

Step 1

Find the first derivative and evaluate at $x = 8$ and $y = 4$ to find the slope of the tangent line.

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Step 1.1

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{x + 8}$ as ${(x + 8)}^{\frac{1}{2}}$ .

$\frac{d}{d x} [{(x + 8)}^{\frac{1}{2}}]$

Step 1.2

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = x^{\frac{1}{2}}$ and $g (x) = x + 8$ .

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Step 1.2.1

To apply the Chain Rule, set $u$ as $x + 8$ .

$\frac{d}{d u} [u^{\frac{1}{2}}] \frac{d}{d x} [x + 8]$

Step 1.2.2

Differentiate using the Power Rule which states that $\frac{d}{d u} [u^{n}]$ is $n u^{n - 1}$ where $n = \frac{1}{2}$ .

$\frac{1}{2} u^{\frac{1}{2} - 1} \frac{d}{d x} [x + 8]$

Step 1.2.3

Replace all occurrences of $u$ with $x + 8$ .

$\frac{1}{2} {(x + 8)}^{\frac{1}{2} - 1} \frac{d}{d x} [x + 8]$

Step 1.3

To write $- 1$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$\frac{1}{2} {(x + 8)}^{\frac{1}{2} - 1 \cdot \frac{2}{2}} \frac{d}{d x} [x + 8]$

Step 1.4

Combine $- 1$ and $\frac{2}{2}$ .

$\frac{1}{2} {(x + 8)}^{\frac{1}{2} + \frac{- 1 \cdot 2}{2}} \frac{d}{d x} [x + 8]$

Step 1.5

Combine the numerators over the common denominator.

$\frac{1}{2} {(x + 8)}^{\frac{1 - 1 \cdot 2}{2}} \frac{d}{d x} [x + 8]$

Step 1.6

Simplify the numerator.

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Step 1.6.1

Multiply $- 1$ by $2$ .

$\frac{1}{2} {(x + 8)}^{\frac{1 - 2}{2}} \frac{d}{d x} [x + 8]$

Step 1.6.2

Subtract $2$ from $1$ .

$\frac{1}{2} {(x + 8)}^{\frac{- 1}{2}} \frac{d}{d x} [x + 8]$

Step 1.7

Combine fractions.

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Step 1.7.1

Move the negative in front of the fraction.

$\frac{1}{2} {(x + 8)}^{- \frac{1}{2}} \frac{d}{d x} [x + 8]$

Step 1.7.2

Combine $\frac{1}{2}$ and ${(x + 8)}^{- \frac{1}{2}}$ .

$\frac{{(x + 8)}^{- \frac{1}{2}}}{2} \frac{d}{d x} [x + 8]$

Step 1.7.3

Move ${(x + 8)}^{- \frac{1}{2}}$ to the denominator using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$\frac{1}{2 {(x + 8)}^{\frac{1}{2}}} \frac{d}{d x} [x + 8]$

Step 1.8

By the Sum Rule, the derivative of $x + 8$ with respect to $x$ is $\frac{d}{d x} [x] + \frac{d}{d x} [8]$ .

$\frac{1}{2 {(x + 8)}^{\frac{1}{2}}} (\frac{d}{d x} [x] + \frac{d}{d x} [8])$

Step 1.9

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$\frac{1}{2 {(x + 8)}^{\frac{1}{2}}} (1 + \frac{d}{d x} [8])$

Step 1.10

Since $8$ is constant with respect to $x$ , the derivative of $8$ with respect to $x$ is $0$ .

$\frac{1}{2 {(x + 8)}^{\frac{1}{2}}} (1 + 0)$

Step 1.11

Simplify the expression.

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Step 1.11.1

Add $1$ and $0$ .

$\frac{1}{2 {(x + 8)}^{\frac{1}{2}}} \cdot 1$

Step 1.11.2

Multiply $\frac{1}{2 {(x + 8)}^{\frac{1}{2}}}$ by $1$ .

$\frac{1}{2 {(x + 8)}^{\frac{1}{2}}}$

Step 1.12

Evaluate the derivative at $x = 8$ .

$\frac{1}{2 {((8) + 8)}^{\frac{1}{2}}}$

Step 1.13

Simplify.

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Step 1.13.1

Simplify the denominator.

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Step 1.13.1.1

Add $8$ and $8$ .

$\frac{1}{2 \cdot 16^{\frac{1}{2}}}$

Step 1.13.1.2

Rewrite $16$ as $4^{2}$ .

$\frac{1}{2 \cdot {(4^{2})}^{\frac{1}{2}}}$

Step 1.13.1.3

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$\frac{1}{2 \cdot 4^{2 (\frac{1}{2})}}$

Step 1.13.1.4

Cancel the common factor of $2$ .

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Step 1.13.1.4.1

Cancel the common factor.

$\frac{1}{2 \cdot 4^{2 (\frac{1}{2})}}$

Step 1.13.1.4.2

Rewrite the expression.

$\frac{1}{2 \cdot 4^{1}}$

Step 1.13.1.5

Evaluate the exponent.

$\frac{1}{2 \cdot 4}$

Step 1.13.2

Multiply $2$ by $4$ .

$\frac{1}{8}$

Step 2

Plug the slope and point values into the point-slope formula and solve for $y$ .

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Step 2.1

Use the slope $\frac{1}{8}$ and a given point $(8, 4)$ to substitute for $x_{1}$ and $y_{1}$ in the point-slope form $y - y_{1} = m (x - x_{1})$ , which is derived from the slope equation $m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ .

$y - (4) = \frac{1}{8} \cdot (x - (8))$

Step 2.2

Simplify the equation and keep it in point-slope form.

$y - 4 = \frac{1}{8} \cdot (x - 8)$

Step 2.3

Solve for $y$ .

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Step 2.3.1

Simplify $\frac{1}{8} \cdot (x - 8)$ .

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Step 2.3.1.1

Rewrite.

$y - 4 = 0 + 0 + \frac{1}{8} \cdot (x - 8)$

Step 2.3.1.2

Simplify by adding zeros.

$y - 4 = \frac{1}{8} \cdot (x - 8)$

Step 2.3.1.3

Apply the distributive property.

$y - 4 = \frac{1}{8} x + \frac{1}{8} \cdot - 8$

Step 2.3.1.4

Combine $\frac{1}{8}$ and $x$ .

$y - 4 = \frac{x}{8} + \frac{1}{8} \cdot - 8$

Step 2.3.1.5

Cancel the common factor of $8$ .

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Step 2.3.1.5.1

Factor $8$ out of $- 8$ .

$y - 4 = \frac{x}{8} + \frac{1}{8} \cdot (8 (- 1))$

Step 2.3.1.5.2

Cancel the common factor.

$y - 4 = \frac{x}{8} + \frac{1}{8} \cdot (8 \cdot - 1)$

Step 2.3.1.5.3

Rewrite the expression.

$y - 4 = \frac{x}{8} - 1$

Step 2.3.2

Move all terms not containing $y$ to the right side of the equation.

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Step 2.3.2.1

Add $4$ to both sides of the equation.

$y = \frac{x}{8} - 1 + 4$

Step 2.3.2.2

Add $- 1$ and $4$ .

$y = \frac{x}{8} + 3$

Step 2.3.3

Reorder terms.

$y = \frac{1}{8} x + 3$

Step 3