Calculus Examples

$\int_{1}^{4} \frac{e^{\sqrt{x}}}{\sqrt{x}} d x$

Step 1

Apply basic rules of exponents.

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Step 1.1

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{x}$ as $x^{\frac{1}{2}}$ .

$\int_{1}^{4} \frac{e^{x^{\frac{1}{2}}}}{\sqrt{x}} d x$

Step 1.2

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{x}$ as $x^{\frac{1}{2}}$ .

$\int_{1}^{4} \frac{e^{x^{\frac{1}{2}}}}{x^{\frac{1}{2}}} d x$

Step 1.3

Move $x^{\frac{1}{2}}$ out of the denominator by raising it to the $- 1$ power.

$\int_{1}^{4} e^{x^{\frac{1}{2}}} {(x^{\frac{1}{2}})}^{- 1} d x$

Step 1.4

Multiply the exponents in ${(x^{\frac{1}{2}})}^{- 1}$ .

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Step 1.4.1

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$\int_{1}^{4} e^{x^{\frac{1}{2}}} x^{\frac{1}{2} \cdot - 1} d x$

Step 1.4.2

Combine $\frac{1}{2}$ and $- 1$ .

$\int_{1}^{4} e^{x^{\frac{1}{2}}} x^{\frac{- 1}{2}} d x$

Step 1.4.3

Move the negative in front of the fraction.

$\int_{1}^{4} e^{x^{\frac{1}{2}}} x^{- \frac{1}{2}} d x$

Step 2

Let $u = x^{\frac{1}{2}}$ . Then $d u = \frac{1}{2 x^{\frac{1}{2}}} d x$ , so $- d u = \frac{- 1}{2 x^{\frac{1}{2}}} d x$ . Rewrite using $u$ and $d$ $u$ .

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Step 2.1

Let $u = x^{\frac{1}{2}}$ . Find $\frac{d u}{d x}$ .

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Step 2.1.1

Differentiate $x^{\frac{1}{2}}$ .

$\frac{d}{d x} [x^{\frac{1}{2}}]$

Step 2.1.2

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = \frac{1}{2}$ .

$\frac{1}{2} x^{\frac{1}{2} - 1}$

Step 2.1.3

To write $- 1$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$\frac{1}{2} x^{\frac{1}{2} - 1 \cdot \frac{2}{2}}$

Step 2.1.4

Combine $- 1$ and $\frac{2}{2}$ .

$\frac{1}{2} x^{\frac{1}{2} + \frac{- 1 \cdot 2}{2}}$

Step 2.1.5

Combine the numerators over the common denominator.

$\frac{1}{2} x^{\frac{1 - 1 \cdot 2}{2}}$

Step 2.1.6

Simplify the numerator.

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Step 2.1.6.1

Multiply $- 1$ by $2$ .

$\frac{1}{2} x^{\frac{1 - 2}{2}}$

Step 2.1.6.2

Subtract $2$ from $1$ .

$\frac{1}{2} x^{\frac{- 1}{2}}$

Step 2.1.7

Move the negative in front of the fraction.

$\frac{1}{2} x^{- \frac{1}{2}}$

Step 2.1.8

Simplify.

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Step 2.1.8.1

Rewrite the expression using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$\frac{1}{2} \cdot \frac{1}{x^{\frac{1}{2}}}$

Step 2.1.8.2

Multiply $\frac{1}{2}$ by $\frac{1}{x^{\frac{1}{2}}}$ .

$\frac{1}{2 x^{\frac{1}{2}}}$

Step 2.2

Substitute the lower limit in for $x$ in $u = x^{\frac{1}{2}}$ .

$u_{lower} = 1^{\frac{1}{2}}$

Step 2.3

One to any power is one.

$u_{lower} = 1$

Step 2.4

Substitute the upper limit in for $x$ in $u = x^{\frac{1}{2}}$ .

$u_{upper} = 4^{\frac{1}{2}}$

Step 2.5

Simplify.

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Step 2.5.1

Rewrite $4$ as $2^{2}$ .

$u_{upper} = {(2^{2})}^{\frac{1}{2}}$

Step 2.5.2

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$u_{upper} = 2^{2 (\frac{1}{2})}$

Step 2.5.3

Cancel the common factor of $2$ .

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Step 2.5.3.1

Cancel the common factor.

$u_{upper} = 2^{2 (\frac{1}{2})}$

Step 2.5.3.2

Rewrite the expression.

$u_{upper} = 2^{1}$

Step 2.5.4

Evaluate the exponent.

$u_{upper} = 2$

Step 2.6

The values found for $u_{lower}$ and $u_{upper}$ will be used to evaluate the definite integral.

$u_{lower} = 1$

$u_{upper} = 2$

Step 2.7

Rewrite the problem using $u$ , $d u$ , and the new limits of integration.

$\int_{1}^{2} 2 e^{u} d u$

Step 3

Since $2$ is constant with respect to $u$ , move $2$ out of the integral.

$2 \int_{1}^{2} e^{u} d u$

Step 4

The integral of $e^{u}$ with respect to $u$ is $e^{u}$ .

$2 (e^{u}]_{1}^{2})$

Step 5

Substitute and simplify.

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Step 5.1

Evaluate $e^{u}$ at $2$ and at $1$ .

$2 ((e^{2}) - e^{1})$

Step 5.2

Simplify.

$2 (e^{2} - e)$

Step 6

Simplify.

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Step 6.1

Apply the distributive property.

$2 e^{2} + 2 (- e)$

Step 6.2

Multiply $- 1$ by $2$ .

$2 e^{2} - 2 e$

Step 7

The result can be shown in multiple forms.

Exact Form:

$2 e^{2} - 2 e$

Decimal Form:

$9.34154854 \dots$

Step 8