Calculus Examples

$\int (π + e^{3 x}) d x$

Step 1

Remove parentheses.

$\int π + e^{3 x} d x$

Step 2

Split the single integral into multiple integrals.

$\int π d x + \int e^{3 x} d x$

Step 3

Apply the constant rule.

$π x + C + \int e^{3 x} d x$

Step 4

Let $u = 3 x$ . Then $d u = 3 d x$ , so $\frac{1}{3} d u = d x$ . Rewrite using $u$ and $d$ $u$ .

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Step 4.1

Let $u = 3 x$ . Find $\frac{d u}{d x}$ .

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Step 4.1.1

Differentiate $3 x$ .

$\frac{d}{d x} [3 x]$

Step 4.1.2

Since $3$ is constant with respect to $x$ , the derivative of $3 x$ with respect to $x$ is $3 \frac{d}{d x} [x]$ .

$3 \frac{d}{d x} [x]$

Step 4.1.3

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$3 \cdot 1$

Step 4.1.4

Multiply $3$ by $1$ .

$3$

Step 4.2

Rewrite the problem using $u$ and $d u$ .

$π x + C + \int e^{u} \frac{1}{3} d u$

Step 5

Combine $e^{u}$ and $\frac{1}{3}$ .

$π x + C + \int \frac{e^{u}}{3} d u$

Step 6

Since $\frac{1}{3}$ is constant with respect to $u$ , move $\frac{1}{3}$ out of the integral.

$π x + C + \frac{1}{3} \int e^{u} d u$

Step 7

The integral of $e^{u}$ with respect to $u$ is $e^{u}$ .

$π x + C + \frac{1}{3} (e^{u} + C)$

Step 8

Simplify.

$π x + \frac{1}{3} e^{u} + C$

Step 9

Replace all occurrences of $u$ with $3 x$ .

$π x + \frac{1}{3} e^{3 x} + C$