Calculus Examples

$\frac{3}{4} x^{\frac{4}{3}} - \frac{3}{8} x^{\frac{2}{3}} + 9$

Step 1

By the Sum Rule, the derivative of $\frac{3}{4} x^{\frac{4}{3}} - \frac{3}{8} x^{\frac{2}{3}} + 9$ with respect to $x$ is $\frac{d}{d x} [\frac{3}{4} x^{\frac{4}{3}}] + \frac{d}{d x} [- \frac{3}{8} x^{\frac{2}{3}}] + \frac{d}{d x} [9]$ .

$\frac{d}{d x} [\frac{3}{4} x^{\frac{4}{3}}] + \frac{d}{d x} [- \frac{3}{8} x^{\frac{2}{3}}] + \frac{d}{d x} [9]$

Step 2

Evaluate $\frac{d}{d x} [\frac{3}{4} x^{\frac{4}{3}}]$ .

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Step 2.1

Since $\frac{3}{4}$ is constant with respect to $x$ , the derivative of $\frac{3}{4} x^{\frac{4}{3}}$ with respect to $x$ is $\frac{3}{4} \frac{d}{d x} [x^{\frac{4}{3}}]$ .

$\frac{3}{4} \frac{d}{d x} [x^{\frac{4}{3}}] + \frac{d}{d x} [- \frac{3}{8} x^{\frac{2}{3}}] + \frac{d}{d x} [9]$

Step 2.2

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = \frac{4}{3}$ .

$\frac{3}{4} (\frac{4}{3} x^{\frac{4}{3} - 1}) + \frac{d}{d x} [- \frac{3}{8} x^{\frac{2}{3}}] + \frac{d}{d x} [9]$

Step 2.3

To write $- 1$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$\frac{3}{4} (\frac{4}{3} x^{\frac{4}{3} - 1 \cdot \frac{3}{3}}) + \frac{d}{d x} [- \frac{3}{8} x^{\frac{2}{3}}] + \frac{d}{d x} [9]$

Step 2.4

Combine $- 1$ and $\frac{3}{3}$ .

$\frac{3}{4} (\frac{4}{3} x^{\frac{4}{3} + \frac{- 1 \cdot 3}{3}}) + \frac{d}{d x} [- \frac{3}{8} x^{\frac{2}{3}}] + \frac{d}{d x} [9]$

Step 2.5

Combine the numerators over the common denominator.

$\frac{3}{4} (\frac{4}{3} x^{\frac{4 - 1 \cdot 3}{3}}) + \frac{d}{d x} [- \frac{3}{8} x^{\frac{2}{3}}] + \frac{d}{d x} [9]$

Step 2.6

Simplify the numerator.

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Step 2.6.1

Multiply $- 1$ by $3$ .

$\frac{3}{4} (\frac{4}{3} x^{\frac{4 - 3}{3}}) + \frac{d}{d x} [- \frac{3}{8} x^{\frac{2}{3}}] + \frac{d}{d x} [9]$

Step 2.6.2

Subtract $3$ from $4$ .

$\frac{3}{4} (\frac{4}{3} x^{\frac{1}{3}}) + \frac{d}{d x} [- \frac{3}{8} x^{\frac{2}{3}}] + \frac{d}{d x} [9]$

Step 2.7

Combine $\frac{4}{3}$ and $x^{\frac{1}{3}}$ .

$\frac{3}{4} \cdot \frac{4 x^{\frac{1}{3}}}{3} + \frac{d}{d x} [- \frac{3}{8} x^{\frac{2}{3}}] + \frac{d}{d x} [9]$

Step 2.8

Multiply $\frac{3}{4}$ by $\frac{4 x^{\frac{1}{3}}}{3}$ .

$\frac{3 (4 x^{\frac{1}{3}})}{4 \cdot 3} + \frac{d}{d x} [- \frac{3}{8} x^{\frac{2}{3}}] + \frac{d}{d x} [9]$

Step 2.9

Multiply $4$ by $3$ .

$\frac{12 x^{\frac{1}{3}}}{4 \cdot 3} + \frac{d}{d x} [- \frac{3}{8} x^{\frac{2}{3}}] + \frac{d}{d x} [9]$

Step 2.10

Multiply $4$ by $3$ .

$\frac{12 x^{\frac{1}{3}}}{12} + \frac{d}{d x} [- \frac{3}{8} x^{\frac{2}{3}}] + \frac{d}{d x} [9]$

Step 2.11

Cancel the common factor.

$\frac{12 x^{\frac{1}{3}}}{12} + \frac{d}{d x} [- \frac{3}{8} x^{\frac{2}{3}}] + \frac{d}{d x} [9]$

Step 2.12

Divide $x^{\frac{1}{3}}$ by $1$ .

$x^{\frac{1}{3}} + \frac{d}{d x} [- \frac{3}{8} x^{\frac{2}{3}}] + \frac{d}{d x} [9]$

Step 3

Evaluate $\frac{d}{d x} [- \frac{3}{8} x^{\frac{2}{3}}]$ .

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Step 3.1

Since $- \frac{3}{8}$ is constant with respect to $x$ , the derivative of $- \frac{3}{8} x^{\frac{2}{3}}$ with respect to $x$ is $- \frac{3}{8} \frac{d}{d x} [x^{\frac{2}{3}}]$ .

$x^{\frac{1}{3}} - \frac{3}{8} \frac{d}{d x} [x^{\frac{2}{3}}] + \frac{d}{d x} [9]$

Step 3.2

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = \frac{2}{3}$ .

$x^{\frac{1}{3}} - \frac{3}{8} (\frac{2}{3} x^{\frac{2}{3} - 1}) + \frac{d}{d x} [9]$

Step 3.3

To write $- 1$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$x^{\frac{1}{3}} - \frac{3}{8} (\frac{2}{3} x^{\frac{2}{3} - 1 \cdot \frac{3}{3}}) + \frac{d}{d x} [9]$

Step 3.4

Combine $- 1$ and $\frac{3}{3}$ .

$x^{\frac{1}{3}} - \frac{3}{8} (\frac{2}{3} x^{\frac{2}{3} + \frac{- 1 \cdot 3}{3}}) + \frac{d}{d x} [9]$

Step 3.5

Combine the numerators over the common denominator.

$x^{\frac{1}{3}} - \frac{3}{8} (\frac{2}{3} x^{\frac{2 - 1 \cdot 3}{3}}) + \frac{d}{d x} [9]$

Step 3.6

Simplify the numerator.

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Step 3.6.1

Multiply $- 1$ by $3$ .

$x^{\frac{1}{3}} - \frac{3}{8} (\frac{2}{3} x^{\frac{2 - 3}{3}}) + \frac{d}{d x} [9]$

Step 3.6.2

Subtract $3$ from $2$ .

$x^{\frac{1}{3}} - \frac{3}{8} (\frac{2}{3} x^{\frac{- 1}{3}}) + \frac{d}{d x} [9]$

Step 3.7

Move the negative in front of the fraction.

$x^{\frac{1}{3}} - \frac{3}{8} (\frac{2}{3} x^{- \frac{1}{3}}) + \frac{d}{d x} [9]$

Step 3.8

Combine $\frac{2}{3}$ and $x^{- \frac{1}{3}}$ .

$x^{\frac{1}{3}} - \frac{3}{8} \cdot \frac{2 x^{- \frac{1}{3}}}{3} + \frac{d}{d x} [9]$

Step 3.9

Multiply $\frac{2 x^{- \frac{1}{3}}}{3}$ by $\frac{3}{8}$ .

$x^{\frac{1}{3}} - \frac{2 x^{- \frac{1}{3}} \cdot 3}{3 \cdot 8} + \frac{d}{d x} [9]$

Step 3.10

Multiply $3$ by $2$ .

$x^{\frac{1}{3}} - \frac{6 x^{- \frac{1}{3}}}{3 \cdot 8} + \frac{d}{d x} [9]$

Step 3.11

Multiply $3$ by $8$ .

$x^{\frac{1}{3}} - \frac{6 x^{- \frac{1}{3}}}{24} + \frac{d}{d x} [9]$

Step 3.12

Move $x^{- \frac{1}{3}}$ to the denominator using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$x^{\frac{1}{3}} - \frac{6}{24 x^{\frac{1}{3}}} + \frac{d}{d x} [9]$

Step 3.13

Factor $6$ out of $6$ .

$x^{\frac{1}{3}} - \frac{6 (1)}{24 x^{\frac{1}{3}}} + \frac{d}{d x} [9]$

Step 3.14

Cancel the common factors.

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Step 3.14.1

Factor $6$ out of $24 x^{\frac{1}{3}}$ .

$x^{\frac{1}{3}} - \frac{6 (1)}{6 (4 x^{\frac{1}{3}})} + \frac{d}{d x} [9]$

Step 3.14.2

Cancel the common factor.

$x^{\frac{1}{3}} - \frac{6 \cdot 1}{6 (4 x^{\frac{1}{3}})} + \frac{d}{d x} [9]$

Step 3.14.3

Rewrite the expression.

$x^{\frac{1}{3}} - \frac{1}{4 x^{\frac{1}{3}}} + \frac{d}{d x} [9]$

Step 4

Differentiate using the Constant Rule.

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Step 4.1

Since $9$ is constant with respect to $x$ , the derivative of $9$ with respect to $x$ is $0$ .

$x^{\frac{1}{3}} - \frac{1}{4 x^{\frac{1}{3}}} + 0$

Step 4.2

Add $x^{\frac{1}{3}} - \frac{1}{4 x^{\frac{1}{3}}}$ and $0$ .

$x^{\frac{1}{3}} - \frac{1}{4 x^{\frac{1}{3}}}$