Calculus Examples

${(x^{2} + y^{2} - 1)}^{3} - x^{2} y^{3} = 0$

Step 1

Differentiate both sides of the equation.

$\frac{d}{d x} ({(x^{2} + y^{2} - 1)}^{3} - x^{2} y^{3}) = \frac{d}{d x} (0)$

Step 2

Differentiate the left side of the equation.

Tap for more steps...

Step 2.1

By the Sum Rule, the derivative of ${(x^{2} + y^{2} - 1)}^{3} - x^{2} y^{3}$ with respect to $x$ is $\frac{d}{d x} [{(x^{2} + y^{2} - 1)}^{3}] + \frac{d}{d x} [- x^{2} y^{3}]$ .

$\frac{d}{d x} [{(x^{2} + y^{2} - 1)}^{3}] + \frac{d}{d x} [- x^{2} y^{3}]$

Step 2.2

Evaluate $\frac{d}{d x} [{(x^{2} + y^{2} - 1)}^{3}]$ .

Tap for more steps...

Step 2.2.1

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = x^{3}$ and $g (x) = x^{2} + y^{2} - 1$ .

Tap for more steps...

Step 2.2.1.1

To apply the Chain Rule, set $u_{1}$ as $x^{2} + y^{2} - 1$ .

$\frac{d}{d u_{1}} [{u_{1}}^{3}] \frac{d}{d x} [x^{2} + y^{2} - 1] + \frac{d}{d x} [- x^{2} y^{3}]$

Step 2.2.1.2

Differentiate using the Power Rule which states that $\frac{d}{d u_{1}} [{u_{1}}^{n}]$ is $n {u_{1}}^{n - 1}$ where $n = 3$ .

$3 {u_{1}}^{2} \frac{d}{d x} [x^{2} + y^{2} - 1] + \frac{d}{d x} [- x^{2} y^{3}]$

Step 2.2.1.3

Replace all occurrences of $u_{1}$ with $x^{2} + y^{2} - 1$ .

$3 {(x^{2} + y^{2} - 1)}^{2} \frac{d}{d x} [x^{2} + y^{2} - 1] + \frac{d}{d x} [- x^{2} y^{3}]$

Step 2.2.2

By the Sum Rule, the derivative of $x^{2} + y^{2} - 1$ with respect to $x$ is $\frac{d}{d x} [x^{2}] + \frac{d}{d x} [y^{2}] + \frac{d}{d x} [- 1]$ .

$3 {(x^{2} + y^{2} - 1)}^{2} (\frac{d}{d x} [x^{2}] + \frac{d}{d x} [y^{2}] + \frac{d}{d x} [- 1]) + \frac{d}{d x} [- x^{2} y^{3}]$

Step 2.2.3

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 2$ .

$3 {(x^{2} + y^{2} - 1)}^{2} (2 x + \frac{d}{d x} [y^{2}] + \frac{d}{d x} [- 1]) + \frac{d}{d x} [- x^{2} y^{3}]$

Step 2.2.4

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = x^{2}$ and $g (x) = y$ .

Tap for more steps...

Step 2.2.4.1

To apply the Chain Rule, set $u_{2}$ as $y$ .

$3 {(x^{2} + y^{2} - 1)}^{2} (2 x + \frac{d}{d u_{2}} [{u_{2}}^{2}] \frac{d}{d x} [y] + \frac{d}{d x} [- 1]) + \frac{d}{d x} [- x^{2} y^{3}]$

Step 2.2.4.2

Differentiate using the Power Rule which states that $\frac{d}{d u_{2}} [{u_{2}}^{n}]$ is $n {u_{2}}^{n - 1}$ where $n = 2$ .

$3 {(x^{2} + y^{2} - 1)}^{2} (2 x + 2 u_{2} \frac{d}{d x} [y] + \frac{d}{d x} [- 1]) + \frac{d}{d x} [- x^{2} y^{3}]$

Step 2.2.4.3

Replace all occurrences of $u_{2}$ with $y$ .

$3 {(x^{2} + y^{2} - 1)}^{2} (2 x + 2 y \frac{d}{d x} [y] + \frac{d}{d x} [- 1]) + \frac{d}{d x} [- x^{2} y^{3}]$

Step 2.2.5

Rewrite $\frac{d}{d x} [y]$ as $y'$ .

$3 {(x^{2} + y^{2} - 1)}^{2} (2 x + 2 y y' + \frac{d}{d x} [- 1]) + \frac{d}{d x} [- x^{2} y^{3}]$

Step 2.2.6

Since $- 1$ is constant with respect to $x$ , the derivative of $- 1$ with respect to $x$ is $0$ .

$3 {(x^{2} + y^{2} - 1)}^{2} (2 x + 2 y y' + 0) + \frac{d}{d x} [- x^{2} y^{3}]$

Step 2.2.7

Add $2 x + 2 y y'$ and $0$ .

$3 {(x^{2} + y^{2} - 1)}^{2} (2 x + 2 y y') + \frac{d}{d x} [- x^{2} y^{3}]$

Step 2.3

Evaluate $\frac{d}{d x} [- x^{2} y^{3}]$ .

Tap for more steps...

Step 2.3.1

Since $- 1$ is constant with respect to $x$ , the derivative of $- x^{2} y^{3}$ with respect to $x$ is $- \frac{d}{d x} [x^{2} y^{3}]$ .

$3 {(x^{2} + y^{2} - 1)}^{2} (2 x + 2 y y') - \frac{d}{d x} [x^{2} y^{3}]$

Step 2.3.2

Differentiate using the Product Rule which states that $\frac{d}{d x} [f (x) g (x)]$ is $f (x) \frac{d}{d x} [g (x)] + g (x) \frac{d}{d x} [f (x)]$ where $f (x) = x^{2}$ and $g (x) = y^{3}$ .

$3 {(x^{2} + y^{2} - 1)}^{2} (2 x + 2 y y') - (x^{2} \frac{d}{d x} [y^{3}] + y^{3} \frac{d}{d x} [x^{2}])$

Step 2.3.3

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = x^{3}$ and $g (x) = y$ .

Tap for more steps...

Step 2.3.3.1

To apply the Chain Rule, set $u_{3}$ as $y$ .

$3 {(x^{2} + y^{2} - 1)}^{2} (2 x + 2 y y') - (x^{2} (\frac{d}{d u_{3}} [{u_{3}}^{3}] \frac{d}{d x} [y]) + y^{3} \frac{d}{d x} [x^{2}])$

Step 2.3.3.2

Differentiate using the Power Rule which states that $\frac{d}{d u_{3}} [{u_{3}}^{n}]$ is $n {u_{3}}^{n - 1}$ where $n = 3$ .

$3 {(x^{2} + y^{2} - 1)}^{2} (2 x + 2 y y') - (x^{2} (3 {u_{3}}^{2} \frac{d}{d x} [y]) + y^{3} \frac{d}{d x} [x^{2}])$

Step 2.3.3.3

Replace all occurrences of $u_{3}$ with $y$ .

$3 {(x^{2} + y^{2} - 1)}^{2} (2 x + 2 y y') - (x^{2} (3 y^{2} \frac{d}{d x} [y]) + y^{3} \frac{d}{d x} [x^{2}])$

Step 2.3.4

Rewrite $\frac{d}{d x} [y]$ as $y'$ .

$3 {(x^{2} + y^{2} - 1)}^{2} (2 x + 2 y y') - (x^{2} (3 y^{2} y') + y^{3} \frac{d}{d x} [x^{2}])$

Step 2.3.5

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 2$ .

$3 {(x^{2} + y^{2} - 1)}^{2} (2 x + 2 y y') - (x^{2} (3 y^{2} y') + y^{3} (2 x))$

Step 2.3.6

Move $3$ to the left of $x^{2}$ .

$3 {(x^{2} + y^{2} - 1)}^{2} (2 x + 2 y y') - (3 \cdot x^{2} y^{2} y' + y^{3} (2 x))$

Step 2.3.7

Move $2$ to the left of $y^{3}$ .

$3 {(x^{2} + y^{2} - 1)}^{2} (2 x + 2 y y') - (3 x^{2} y^{2} y' + 2 y^{3} x)$

Step 2.4

Simplify.

Tap for more steps...

Step 2.4.1

Apply the distributive property.

$3 {(x^{2} + y^{2} - 1)}^{2} (2 x + 2 y y') - (3 x^{2} y^{2} y') - (2 y^{3} x)$

Step 2.4.2

Apply the distributive property.

$3 {(x^{2} + y^{2} - 1)}^{2} (2 x) + 3 {(x^{2} + y^{2} - 1)}^{2} (2 y y') - (3 x^{2} y^{2} y') - (2 y^{3} x)$

Step 2.4.3

Combine terms.

Tap for more steps...

Step 2.4.3.1

Multiply $2$ by $3$ .

$6 {(x^{2} + y^{2} - 1)}^{2} x + 3 {(x^{2} + y^{2} - 1)}^{2} (2 y y') - (3 x^{2} y^{2} y') - (2 y^{3} x)$

Step 2.4.3.2

Multiply $2$ by $3$ .

$6 {(x^{2} + y^{2} - 1)}^{2} x + 6 {(x^{2} + y^{2} - 1)}^{2} (y y') - (3 x^{2} y^{2} y') - (2 y^{3} x)$

Step 2.4.3.3

Multiply $3$ by $- 1$ .

$6 {(x^{2} + y^{2} - 1)}^{2} x + 6 {(x^{2} + y^{2} - 1)}^{2} (y y') - 3 (x^{2} y^{2} y') - (2 y^{3} x)$

Step 2.4.3.4

Multiply $2$ by $- 1$ .

$6 {(x^{2} + y^{2} - 1)}^{2} x + 6 {(x^{2} + y^{2} - 1)}^{2} (y y') - 3 x^{2} y^{2} y' - 2 y^{3} x$

Step 2.4.4

Reorder terms.

$6 x {(x^{2} + y^{2} - 1)}^{2} + 6 y {(x^{2} + y^{2} - 1)}^{2} y' - 3 x^{2} y^{2} y' - 2 y^{3} x$

Step 3

Since $0$ is constant with respect to $x$ , the derivative of $0$ with respect to $x$ is $0$ .

$0$

Step 4

Reform the equation by setting the left side equal to the right side.

$6 x {(x^{2} + y^{2} - 1)}^{2} + 6 y {(x^{2} + y^{2} - 1)}^{2} y' - 3 x^{2} y^{2} y' - 2 y^{3} x = 0$

Step 5

Solve for $y'$ .

Tap for more steps...

Step 5.1

Reorder factors in $6 x {(x^{2} + y^{2} - 1)}^{2} + 6 y {(x^{2} + y^{2} - 1)}^{2} y' - 3 x^{2} y^{2} y' - 2 y^{3} x$ .

$6 x {(x^{2} + y^{2} - 1)}^{2} + 6 y y' {(x^{2} + y^{2} - 1)}^{2} - 3 x^{2} y^{2} y' - 2 y^{3} x = 0$

Step 5.2

Move all terms not containing $y'$ to the right side of the equation.

Tap for more steps...

Step 5.2.1

Subtract $6 x {(x^{2} + y^{2} - 1)}^{2}$ from both sides of the equation.

$6 y y' {(x^{2} + y^{2} - 1)}^{2} - 3 x^{2} y^{2} y' - 2 y^{3} x = - 6 x {(x^{2} + y^{2} - 1)}^{2}$

Step 5.2.2

Add $2 y^{3} x$ to both sides of the equation.

$6 y y' {(x^{2} + y^{2} - 1)}^{2} - 3 x^{2} y^{2} y' = - 6 x {(x^{2} + y^{2} - 1)}^{2} + 2 y^{3} x$

Step 5.3

Factor $3 y y'$ out of $6 y y' {(x^{2} + y^{2} - 1)}^{2} - 3 x^{2} y^{2} y'$ .

Tap for more steps...

Step 5.3.1

Factor $3 y y'$ out of $6 y y' {(x^{2} + y^{2} - 1)}^{2}$ .

$3 y y' (2 {(x^{2} + y^{2} - 1)}^{2}) - 3 x^{2} y^{2} y' = - 6 x {(x^{2} + y^{2} - 1)}^{2} + 2 y^{3} x$

Step 5.3.2

Factor $3 y y'$ out of $- 3 x^{2} y^{2} y'$ .

$3 y y' (2 {(x^{2} + y^{2} - 1)}^{2}) + 3 y y' (- x^{2} y) = - 6 x {(x^{2} + y^{2} - 1)}^{2} + 2 y^{3} x$

Step 5.3.3

Factor $3 y y'$ out of $3 y y' (2 {(x^{2} + y^{2} - 1)}^{2}) + 3 y y' (- x^{2} y)$ .

$3 y y' (2 {(x^{2} + y^{2} - 1)}^{2} - x^{2} y) = - 6 x {(x^{2} + y^{2} - 1)}^{2} + 2 y^{3} x$

Step 5.4

Rewrite ${(x^{2} + y^{2} - 1)}^{2}$ as $(x^{2} + y^{2} - 1) (x^{2} + y^{2} - 1)$ .

$3 y y' (2 ((x^{2} + y^{2} - 1) (x^{2} + y^{2} - 1)) - x^{2} y) = - 6 x {(x^{2} + y^{2} - 1)}^{2} + 2 y^{3} x$

Step 5.5

Expand $(x^{2} + y^{2} - 1) (x^{2} + y^{2} - 1)$ by multiplying each term in the first expression by each term in the second expression.

$3 y y' (2 (x^{2} x^{2} + x^{2} y^{2} + x^{2} \cdot - 1 + y^{2} x^{2} + y^{2} y^{2} + y^{2} \cdot - 1 - 1 x^{2} - 1 y^{2} - 1 \cdot - 1) - x^{2} y) = - 6 x {(x^{2} + y^{2} - 1)}^{2} + 2 y^{3} x$

Step 5.6

Simplify each term.

Tap for more steps...

Step 5.6.1

Multiply $x^{2}$ by $x^{2}$ by adding the exponents.

Tap for more steps...

Step 5.6.1.1

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$3 y y' (2 (x^{2 + 2} + x^{2} y^{2} + x^{2} \cdot - 1 + y^{2} x^{2} + y^{2} y^{2} + y^{2} \cdot - 1 - 1 x^{2} - 1 y^{2} - 1 \cdot - 1) - x^{2} y) = - 6 x {(x^{2} + y^{2} - 1)}^{2} + 2 y^{3} x$

Step 5.6.1.2

Add $2$ and $2$ .

$3 y y' (2 (x^{4} + x^{2} y^{2} + x^{2} \cdot - 1 + y^{2} x^{2} + y^{2} y^{2} + y^{2} \cdot - 1 - 1 x^{2} - 1 y^{2} - 1 \cdot - 1) - x^{2} y) = - 6 x {(x^{2} + y^{2} - 1)}^{2} + 2 y^{3} x$

Step 5.6.2

Move $- 1$ to the left of $x^{2}$ .

$3 y y' (2 (x^{4} + x^{2} y^{2} - 1 x^{2} + y^{2} x^{2} + y^{2} y^{2} + y^{2} \cdot - 1 - 1 x^{2} - 1 y^{2} - 1 \cdot - 1) - x^{2} y) = - 6 x {(x^{2} + y^{2} - 1)}^{2} + 2 y^{3} x$

Step 5.6.3

Rewrite $- 1 x^{2}$ as $- x^{2}$ .

$3 y y' (2 (x^{4} + x^{2} y^{2} - x^{2} + y^{2} x^{2} + y^{2} y^{2} + y^{2} \cdot - 1 - 1 x^{2} - 1 y^{2} - 1 \cdot - 1) - x^{2} y) = - 6 x {(x^{2} + y^{2} - 1)}^{2} + 2 y^{3} x$

Step 5.6.4

Multiply $y^{2}$ by $y^{2}$ by adding the exponents.

Tap for more steps...

Step 5.6.4.1

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$3 y y' (2 (x^{4} + x^{2} y^{2} - x^{2} + y^{2} x^{2} + y^{2 + 2} + y^{2} \cdot - 1 - 1 x^{2} - 1 y^{2} - 1 \cdot - 1) - x^{2} y) = - 6 x {(x^{2} + y^{2} - 1)}^{2} + 2 y^{3} x$

Step 5.6.4.2

Add $2$ and $2$ .

$3 y y' (2 (x^{4} + x^{2} y^{2} - x^{2} + y^{2} x^{2} + y^{4} + y^{2} \cdot - 1 - 1 x^{2} - 1 y^{2} - 1 \cdot - 1) - x^{2} y) = - 6 x {(x^{2} + y^{2} - 1)}^{2} + 2 y^{3} x$

Step 5.6.5

Move $- 1$ to the left of $y^{2}$ .

$3 y y' (2 (x^{4} + x^{2} y^{2} - x^{2} + y^{2} x^{2} + y^{4} - 1 y^{2} - 1 x^{2} - 1 y^{2} - 1 \cdot - 1) - x^{2} y) = - 6 x {(x^{2} + y^{2} - 1)}^{2} + 2 y^{3} x$

Step 5.6.6

Rewrite $- 1 y^{2}$ as $- y^{2}$ .

$3 y y' (2 (x^{4} + x^{2} y^{2} - x^{2} + y^{2} x^{2} + y^{4} - y^{2} - 1 x^{2} - 1 y^{2} - 1 \cdot - 1) - x^{2} y) = - 6 x {(x^{2} + y^{2} - 1)}^{2} + 2 y^{3} x$

Step 5.6.7

Rewrite $- 1 x^{2}$ as $- x^{2}$ .

$3 y y' (2 (x^{4} + x^{2} y^{2} - x^{2} + y^{2} x^{2} + y^{4} - y^{2} - x^{2} - 1 y^{2} - 1 \cdot - 1) - x^{2} y) = - 6 x {(x^{2} + y^{2} - 1)}^{2} + 2 y^{3} x$

Step 5.6.8

Rewrite $- 1 y^{2}$ as $- y^{2}$ .

$3 y y' (2 (x^{4} + x^{2} y^{2} - x^{2} + y^{2} x^{2} + y^{4} - y^{2} - x^{2} - y^{2} - 1 \cdot - 1) - x^{2} y) = - 6 x {(x^{2} + y^{2} - 1)}^{2} + 2 y^{3} x$

Step 5.6.9

Multiply $- 1$ by $- 1$ .

$3 y y' (2 (x^{4} + x^{2} y^{2} - x^{2} + y^{2} x^{2} + y^{4} - y^{2} - x^{2} - y^{2} + 1) - x^{2} y) = - 6 x {(x^{2} + y^{2} - 1)}^{2} + 2 y^{3} x$

Step 5.7

Add $x^{2} y^{2}$ and $y^{2} x^{2}$ .

Tap for more steps...

Step 5.7.1

Reorder $y^{2}$ and $x^{2}$ .

$3 y y' (2 (x^{4} - x^{2} + x^{2} y^{2} + x^{2} y^{2} + y^{4} - y^{2} - x^{2} - y^{2} + 1) - x^{2} y) = - 6 x {(x^{2} + y^{2} - 1)}^{2} + 2 y^{3} x$

Step 5.7.2

Add $x^{2} y^{2}$ and $x^{2} y^{2}$ .

$3 y y' (2 (x^{4} - x^{2} + 2 x^{2} y^{2} + y^{4} - y^{2} - x^{2} - y^{2} + 1) - x^{2} y) = - 6 x {(x^{2} + y^{2} - 1)}^{2} + 2 y^{3} x$

Step 5.8

Subtract $x^{2}$ from $- x^{2}$ .

$3 y y' (2 (x^{4} - 2 x^{2} + 2 x^{2} y^{2} + y^{4} - y^{2} - y^{2} + 1) - x^{2} y) = - 6 x {(x^{2} + y^{2} - 1)}^{2} + 2 y^{3} x$

Step 5.9

Subtract $y^{2}$ from $- y^{2}$ .

$3 y y' (2 (x^{4} - 2 x^{2} + 2 x^{2} y^{2} + y^{4} - 2 y^{2} + 1) - x^{2} y) = - 6 x {(x^{2} + y^{2} - 1)}^{2} + 2 y^{3} x$

Step 5.10

Apply the distributive property.

$3 y y' (2 x^{4} + 2 (- 2 x^{2}) + 2 (2 x^{2} y^{2}) + 2 y^{4} + 2 (- 2 y^{2}) + 2 \cdot 1 - x^{2} y) = - 6 x {(x^{2} + y^{2} - 1)}^{2} + 2 y^{3} x$

Step 5.11

Simplify.

Tap for more steps...

Step 5.11.1

Multiply $- 2$ by $2$ .

$3 y y' (2 x^{4} - 4 x^{2} + 2 (2 x^{2} y^{2}) + 2 y^{4} + 2 (- 2 y^{2}) + 2 \cdot 1 - x^{2} y) = - 6 x {(x^{2} + y^{2} - 1)}^{2} + 2 y^{3} x$

Step 5.11.2

Multiply $2$ by $2$ .

$3 y y' (2 x^{4} - 4 x^{2} + 4 (x^{2} y^{2}) + 2 y^{4} + 2 (- 2 y^{2}) + 2 \cdot 1 - x^{2} y) = - 6 x {(x^{2} + y^{2} - 1)}^{2} + 2 y^{3} x$

Step 5.11.3

Multiply $- 2$ by $2$ .

$3 y y' (2 x^{4} - 4 x^{2} + 4 (x^{2} y^{2}) + 2 y^{4} - 4 y^{2} + 2 \cdot 1 - x^{2} y) = - 6 x {(x^{2} + y^{2} - 1)}^{2} + 2 y^{3} x$

Step 5.11.4

Multiply $2$ by $1$ .

$3 y y' (2 x^{4} - 4 x^{2} + 4 (x^{2} y^{2}) + 2 y^{4} - 4 y^{2} + 2 - x^{2} y) = - 6 x {(x^{2} + y^{2} - 1)}^{2} + 2 y^{3} x$

Step 5.12

Remove parentheses.

$3 y y' (2 x^{4} - 4 x^{2} + 4 x^{2} y^{2} + 2 y^{4} - 4 y^{2} + 2 - x^{2} y) = - 6 x {(x^{2} + y^{2} - 1)}^{2} + 2 y^{3} x$

Step 5.13

Divide each term in $3 y y' (2 x^{4} - 4 x^{2} + 4 x^{2} y^{2} + 2 y^{4} - 4 y^{2} + 2 - x^{2} y) = - 6 x {(x^{2} + y^{2} - 1)}^{2} + 2 y^{3} x$ by $3 y (2 x^{4} - 4 x^{2} + 4 x^{2} y^{2} + 2 y^{4} - 4 y^{2} + 2 - x^{2} y)$ and simplify.

Tap for more steps...

Step 5.13.1

$\frac{3 y y' (2 x^{4} - 4 x^{2} + 4 x^{2} y^{2} + 2 y^{4} - 4 y^{2} + 2 - x^{2} y)}{3 y (2 x^{4} - 4 x^{2} + 4 x^{2} y^{2} + 2 y^{4} - 4 y^{2} + 2 - x^{2} y)} = \frac{- 6 x {(x^{2} + y^{2} - 1)}^{2}}{3 y (2 x^{4} - 4 x^{2} + 4 x^{2} y^{2} + 2 y^{4} - 4 y^{2} + 2 - x^{2} y)} + \frac{2 y^{3} x}{3 y (2 x^{4} - 4 x^{2} + 4 x^{2} y^{2} + 2 y^{4} - 4 y^{2} + 2 - x^{2} y)}$

Step 5.13.2

Simplify the left side.

Tap for more steps...

Step 5.13.2.1

Cancel the common factor of $3$ .

Tap for more steps...

Step 5.13.2.1.1

Cancel the common factor.

Step 5.13.2.1.2

Rewrite the expression.

$\frac{y y' (2 x^{4} - 4 x^{2} + 4 x^{2} y^{2} + 2 y^{4} - 4 y^{2} + 2 - x^{2} y)}{y (2 x^{4} - 4 x^{2} + 4 x^{2} y^{2} + 2 y^{4} - 4 y^{2} + 2 - x^{2} y)} = \frac{- 6 x {(x^{2} + y^{2} - 1)}^{2}}{3 y (2 x^{4} - 4 x^{2} + 4 x^{2} y^{2} + 2 y^{4} - 4 y^{2} + 2 - x^{2} y)} + \frac{2 y^{3} x}{3 y (2 x^{4} - 4 x^{2} + 4 x^{2} y^{2} + 2 y^{4} - 4 y^{2} + 2 - x^{2} y)}$

Step 5.13.2.2

Cancel the common factor of $y$ .

Tap for more steps...

Step 5.13.2.2.1

Cancel the common factor.

Step 5.13.2.2.2

Rewrite the expression.

$\frac{y' (2 x^{4} - 4 x^{2} + 4 x^{2} y^{2} + 2 y^{4} - 4 y^{2} + 2 - x^{2} y)}{2 x^{4} - 4 x^{2} + 4 x^{2} y^{2} + 2 y^{4} - 4 y^{2} + 2 - x^{2} y} = \frac{- 6 x {(x^{2} + y^{2} - 1)}^{2}}{3 y (2 x^{4} - 4 x^{2} + 4 x^{2} y^{2} + 2 y^{4} - 4 y^{2} + 2 - x^{2} y)} + \frac{2 y^{3} x}{3 y (2 x^{4} - 4 x^{2} + 4 x^{2} y^{2} + 2 y^{4} - 4 y^{2} + 2 - x^{2} y)}$

Step 5.13.2.3

Cancel the common factor of $2 x^{4} - 4 x^{2} + 4 x^{2} y^{2} + 2 y^{4} - 4 y^{2} + 2 - x^{2} y$ .

Tap for more steps...

Step 5.13.2.3.1

Cancel the common factor.

Step 5.13.2.3.2

Divide $y'$ by $1$ .

$y' = \frac{- 6 x {(x^{2} + y^{2} - 1)}^{2}}{3 y (2 x^{4} - 4 x^{2} + 4 x^{2} y^{2} + 2 y^{4} - 4 y^{2} + 2 - x^{2} y)} + \frac{2 y^{3} x}{3 y (2 x^{4} - 4 x^{2} + 4 x^{2} y^{2} + 2 y^{4} - 4 y^{2} + 2 - x^{2} y)}$

Step 5.13.3

Simplify the right side.

Tap for more steps...

Step 5.13.3.1

Combine the numerators over the common denominator.

$y' = \frac{- 6 x {(x^{2} + y^{2} - 1)}^{2} + 2 y^{3} x}{3 y (2 x^{4} - 4 x^{2} + 4 x^{2} y^{2} + 2 y^{4} - 4 y^{2} + 2 - x^{2} y)}$

Step 5.13.3.2

Factor $2 x$ out of $- 6 x {(x^{2} + y^{2} - 1)}^{2} + 2 y^{3} x$ .

Tap for more steps...

Step 5.13.3.2.1

Factor $2 x$ out of $- 6 x {(x^{2} + y^{2} - 1)}^{2}$ .

$y' = \frac{2 x (- 3 {(x^{2} + y^{2} - 1)}^{2}) + 2 y^{3} x}{3 y (2 x^{4} - 4 x^{2} + 4 x^{2} y^{2} + 2 y^{4} - 4 y^{2} + 2 - x^{2} y)}$

Step 5.13.3.2.2

Factor $2 x$ out of $2 y^{3} x$ .

$y' = \frac{2 x (- 3 {(x^{2} + y^{2} - 1)}^{2}) + 2 x (y^{3})}{3 y (2 x^{4} - 4 x^{2} + 4 x^{2} y^{2} + 2 y^{4} - 4 y^{2} + 2 - x^{2} y)}$

Step 5.13.3.2.3

Factor $2 x$ out of $2 x (- 3 {(x^{2} + y^{2} - 1)}^{2}) + 2 x (y^{3})$ .

$y' = \frac{2 x (- 3 {(x^{2} + y^{2} - 1)}^{2} + y^{3})}{3 y (2 x^{4} - 4 x^{2} + 4 x^{2} y^{2} + 2 y^{4} - 4 y^{2} + 2 - x^{2} y)}$

Step 5.13.3.3

Factor $- 1$ out of $- 3 {(x^{2} + y^{2} - 1)}^{2}$ .

$y' = \frac{2 x (- (3 {(x^{2} + y^{2} - 1)}^{2}) + y^{3})}{3 y (2 x^{4} - 4 x^{2} + 4 x^{2} y^{2} + 2 y^{4} - 4 y^{2} + 2 - x^{2} y)}$

Step 5.13.3.4

Factor $- 1$ out of $y^{3}$ .

$y' = \frac{2 x (- (3 {(x^{2} + y^{2} - 1)}^{2}) - 1 (- y^{3}))}{3 y (2 x^{4} - 4 x^{2} + 4 x^{2} y^{2} + 2 y^{4} - 4 y^{2} + 2 - x^{2} y)}$

Step 5.13.3.5

Factor $- 1$ out of $- (3 {(x^{2} + y^{2} - 1)}^{2}) - 1 (- y^{3})$ .

$y' = \frac{2 x (- (3 {(x^{2} + y^{2} - 1)}^{2} - y^{3}))}{3 y (2 x^{4} - 4 x^{2} + 4 x^{2} y^{2} + 2 y^{4} - 4 y^{2} + 2 - x^{2} y)}$

Step 5.13.3.6

Simplify the expression.

Tap for more steps...

Step 5.13.3.6.1

Rewrite $- (3 {(x^{2} + y^{2} - 1)}^{2} - y^{3})$ as $- 1 (3 {(x^{2} + y^{2} - 1)}^{2} - y^{3})$ .

$y' = \frac{2 x (- 1 (3 {(x^{2} + y^{2} - 1)}^{2} - y^{3}))}{3 y (2 x^{4} - 4 x^{2} + 4 x^{2} y^{2} + 2 y^{4} - 4 y^{2} + 2 - x^{2} y)}$

Step 5.13.3.6.2

Move the negative in front of the fraction.

$y' = - \frac{(2 x) (3 {(x^{2} + y^{2} - 1)}^{2} - y^{3})}{3 y (2 x^{4} - 4 x^{2} + 4 x^{2} y^{2} + 2 y^{4} - 4 y^{2} + 2 - x^{2} y)}$

Step 5.13.3.6.3

Reorder factors in $- \frac{(2 x) (3 {(x^{2} + y^{2} - 1)}^{2} - y^{3})}{3 y (2 x^{4} - 4 x^{2} + 4 x^{2} y^{2} + 2 y^{4} - 4 y^{2} + 2 - x^{2} y)}$ .

$y' = - \frac{2 x (3 {(x^{2} + y^{2} - 1)}^{2} - y^{3})}{3 y (2 x^{4} - 4 x^{2} + 4 x^{2} y^{2} + 2 y^{4} - 4 y^{2} + 2 - x^{2} y)}$

Step 6

Replace $y'$ with $\frac{d y}{d x}$ .

$\frac{d y}{d x} = - \frac{2 x (3 {(x^{2} + y^{2} - 1)}^{2} - y^{3})}{3 y (2 x^{4} - 4 x^{2} + 4 x^{2} y^{2} + 2 y^{4} - 4 y^{2} + 2 - x^{2} y)}$