Calculus Examples

$y = x^{2^{x}}$

Step 1

Differentiate both sides of the equation.

$\frac{d}{d x} (y) = \frac{d}{d x} (x^{2^{x}})$

Step 2

The derivative of $y$ with respect to $x$ is $y'$ .

$y'$

Step 3

Differentiate the right side of the equation.

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Step 3.1

Use the properties of logarithms to simplify the differentiation.

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Step 3.1.1

Rewrite $x^{2^{x}}$ as $e^{\ln (x^{2^{x}})}$ .

$\frac{d}{d x} [e^{\ln (x^{2^{x}})}]$

Step 3.1.2

Expand $\ln (x^{2^{x}})$ by moving $2^{x}$ outside the logarithm.

$\frac{d}{d x} [e^{2^{x} \ln (x)}]$

Step 3.2

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = e^{x}$ and $g (x) = 2^{x} \ln (x)$ .

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Step 3.2.1

To apply the Chain Rule, set $u$ as $2^{x} \ln (x)$ .

$\frac{d}{d u} [e^{u}] \frac{d}{d x} [2^{x} \ln (x)]$

Step 3.2.2

Differentiate using the Exponential Rule which states that $\frac{d}{d u} [a^{u}]$ is $a^{u} \ln (a)$ where $a$ = $e$ .

$e^{u} \frac{d}{d x} [2^{x} \ln (x)]$

Step 3.2.3

Replace all occurrences of $u$ with $2^{x} \ln (x)$ .

$e^{2^{x} \ln (x)} \frac{d}{d x} [2^{x} \ln (x)]$

Step 3.3

Differentiate using the Product Rule which states that $\frac{d}{d x} [f (x) g (x)]$ is $f (x) \frac{d}{d x} [g (x)] + g (x) \frac{d}{d x} [f (x)]$ where $f (x) = 2^{x}$ and $g (x) = \ln (x)$ .

$e^{2^{x} \ln (x)} (2^{x} \frac{d}{d x} [\ln (x)] + \ln (x) \frac{d}{d x} [2^{x}])$

Step 3.4

The derivative of $\ln (x)$ with respect to $x$ is $\frac{1}{x}$ .

$e^{2^{x} \ln (x)} (2^{x} \frac{1}{x} + \ln (x) \frac{d}{d x} [2^{x}])$

Step 3.5

Combine $2^{x}$ and $\frac{1}{x}$ .

$e^{2^{x} \ln (x)} (\frac{2^{x}}{x} + \ln (x) \frac{d}{d x} [2^{x}])$

Step 3.6

Differentiate using the Exponential Rule which states that $\frac{d}{d x} [a^{x}]$ is $a^{x} \ln (a)$ where $a$ = $2$ .

$e^{2^{x} \ln (x)} (\frac{2^{x}}{x} + \ln (x) (2^{x} \ln (2)))$

Step 3.7

Simplify.

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Step 3.7.1

Apply the distributive property.

$e^{2^{x} \ln (x)} \frac{2^{x}}{x} + e^{2^{x} \ln (x)} (\ln (x) (2^{x} \ln (2)))$

Step 3.7.2

Combine $e^{2^{x} \ln (x)}$ and $\frac{2^{x}}{x}$ .

$\frac{e^{2^{x} \ln (x)} \cdot 2^{x}}{x} + e^{2^{x} \ln (x)} (\ln (x) (2^{x} \ln (2)))$

Step 3.7.3

Reorder terms.

$2^{x} e^{2^{x} \ln (x)} \ln (2) \ln (x) + \frac{e^{2^{x} \ln (x)} \cdot 2^{x}}{x}$

Step 4

Reform the equation by setting the left side equal to the right side.

$y' = 2^{x} e^{2^{x} \ln (x)} \ln (2) \ln (x) + \frac{e^{2^{x} \ln (x)} \cdot 2^{x}}{x}$

Step 5

Replace $y'$ with $\frac{d y}{d x}$ .

$\frac{d y}{d x} = 2^{x} e^{2^{x} \ln (x)} \ln (2) \ln (x) + \frac{e^{2^{x} \ln (x)} \cdot 2^{x}}{x}$