Calculus Examples

$y = \frac{5}{5 x^{2} + 5}$

Step 1

Differentiate both sides of the equation.

$\frac{d}{d x} (y) = \frac{d}{d x} (\frac{5}{5 x^{2} + 5})$

Step 2

The derivative of $y$ with respect to $x$ is $y'$ .

$y'$

Step 3

Differentiate the right side of the equation.

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Step 3.1

Reduce the expression by cancelling the common factors.

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Step 3.1.1

Cancel the common factor of $5$ and $5 x^{2} + 5$ .

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Step 3.1.1.1

Factor $5$ out of $5$ .

$\frac{d}{d x} [\frac{5 \cdot 1}{5 x^{2} + 5}]$

Step 3.1.1.2

Cancel the common factors.

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Step 3.1.1.2.1

Factor $5$ out of $5 x^{2}$ .

$\frac{d}{d x} [\frac{5 \cdot 1}{5 (x^{2}) + 5}]$

Step 3.1.1.2.2

Factor $5$ out of $5$ .

$\frac{d}{d x} [\frac{5 \cdot 1}{5 (x^{2}) + 5 (1)}]$

Step 3.1.1.2.3

Factor $5$ out of $5 (x^{2}) + 5 (1)$ .

$\frac{d}{d x} [\frac{5 \cdot 1}{5 (x^{2} + 1)}]$

Step 3.1.1.2.4

Cancel the common factor.

$\frac{d}{d x} [\frac{5 \cdot 1}{5 (x^{2} + 1)}]$

Step 3.1.1.2.5

Rewrite the expression.

$\frac{d}{d x} [\frac{1}{x^{2} + 1}]$

Step 3.1.2

Rewrite $\frac{1}{x^{2} + 1}$ as ${(x^{2} + 1)}^{- 1}$ .

$\frac{d}{d x} [{(x^{2} + 1)}^{- 1}]$

Step 3.2

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = x^{- 1}$ and $g (x) = x^{2} + 1$ .

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Step 3.2.1

To apply the Chain Rule, set $u$ as $x^{2} + 1$ .

$\frac{d}{d u} [u^{- 1}] \frac{d}{d x} [x^{2} + 1]$

Step 3.2.2

Differentiate using the Power Rule which states that $\frac{d}{d u} [u^{n}]$ is $n u^{n - 1}$ where $n = - 1$ .

$- u^{- 2} \frac{d}{d x} [x^{2} + 1]$

Step 3.2.3

Replace all occurrences of $u$ with $x^{2} + 1$ .

$- {(x^{2} + 1)}^{- 2} \frac{d}{d x} [x^{2} + 1]$

Step 3.3

Differentiate.

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Step 3.3.1

By the Sum Rule, the derivative of $x^{2} + 1$ with respect to $x$ is $\frac{d}{d x} [x^{2}] + \frac{d}{d x} [1]$ .

$- {(x^{2} + 1)}^{- 2} (\frac{d}{d x} [x^{2}] + \frac{d}{d x} [1])$

Step 3.3.2

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 2$ .

$- {(x^{2} + 1)}^{- 2} (2 x + \frac{d}{d x} [1])$

Step 3.3.3

Since $1$ is constant with respect to $x$ , the derivative of $1$ with respect to $x$ is $0$ .

$- {(x^{2} + 1)}^{- 2} (2 x + 0)$

Step 3.3.4

Simplify the expression.

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Step 3.3.4.1

Add $2 x$ and $0$ .

$- {(x^{2} + 1)}^{- 2} (2 x)$

Step 3.3.4.2

Multiply $2$ by $- 1$ .

$- 2 {(x^{2} + 1)}^{- 2} x$

Step 3.4

Simplify.

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Step 3.4.1

Rewrite the expression using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$- 2 \frac{1}{{(x^{2} + 1)}^{2}} x$

Step 3.4.2

Combine terms.

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Step 3.4.2.1

Combine $- 2$ and $\frac{1}{{(x^{2} + 1)}^{2}}$ .

$\frac{- 2}{{(x^{2} + 1)}^{2}} x$

Step 3.4.2.2

Move the negative in front of the fraction.

$- \frac{2}{{(x^{2} + 1)}^{2}} x$

Step 3.4.2.3

Combine $x$ and $\frac{2}{{(x^{2} + 1)}^{2}}$ .

$- \frac{x \cdot 2}{{(x^{2} + 1)}^{2}}$

Step 3.4.2.4

Move $2$ to the left of $x$ .

$- \frac{2 x}{{(x^{2} + 1)}^{2}}$

Step 4

Reform the equation by setting the left side equal to the right side.

$y' = - \frac{2 x}{{(x^{2} + 1)}^{2}}$

Step 5

Replace $y'$ with $\frac{d y}{d x}$ .

$\frac{d y}{d x} = - \frac{2 x}{{(x^{2} + 1)}^{2}}$