Calculus Examples

$\frac{1}{2 x^{\frac{1}{2}}}$

Step 1

Write $\frac{1}{2 x^{\frac{1}{2}}}$ as a function.

$f (x) = \frac{1}{2 x^{\frac{1}{2}}}$

Step 2

The function $F (x)$ can be found by finding the indefinite integral of the derivative $f (x)$ .

$F (x) = \int f (x) d x$

Step 3

Set up the integral to solve.

$F (x) = \int \frac{1}{2 x^{\frac{1}{2}}} d x$

Step 4

Since $\frac{1}{2}$ is constant with respect to $x$ , move $\frac{1}{2}$ out of the integral.

$\frac{1}{2} \int \frac{1}{x^{\frac{1}{2}}} d x$

Step 5

Apply basic rules of exponents.

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Step 5.1

Move $x^{\frac{1}{2}}$ out of the denominator by raising it to the $- 1$ power.

$\frac{1}{2} \int {(x^{\frac{1}{2}})}^{- 1} d x$

Step 5.2

Multiply the exponents in ${(x^{\frac{1}{2}})}^{- 1}$ .

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Step 5.2.1

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$\frac{1}{2} \int x^{\frac{1}{2} \cdot - 1} d x$

Step 5.2.2

Combine $\frac{1}{2}$ and $- 1$ .

$\frac{1}{2} \int x^{\frac{- 1}{2}} d x$

Step 5.2.3

Move the negative in front of the fraction.

$\frac{1}{2} \int x^{- \frac{1}{2}} d x$

Step 6

By the Power Rule, the integral of $x^{- \frac{1}{2}}$ with respect to $x$ is $2 x^{\frac{1}{2}}$ .

$\frac{1}{2} (2 x^{\frac{1}{2}} + C)$

Step 7

Simplify the answer.

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Step 7.1

Rewrite $\frac{1}{2} (2 x^{\frac{1}{2}} + C)$ as $\frac{1}{2} \cdot 2 x^{\frac{1}{2}} + C$ .

$\frac{1}{2} \cdot 2 x^{\frac{1}{2}} + C$

Step 7.2

Simplify.

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Step 7.2.1

Combine $\frac{1}{2}$ and $2$ .

$\frac{2}{2} x^{\frac{1}{2}} + C$

Step 7.2.2

Cancel the common factor of $2$ .

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Step 7.2.2.1

Cancel the common factor.

$\frac{2}{2} x^{\frac{1}{2}} + C$

Step 7.2.2.2

Rewrite the expression.

$1 x^{\frac{1}{2}} + C$

Step 7.2.3

Multiply $x^{\frac{1}{2}}$ by $1$ .

$x^{\frac{1}{2}} + C$

Step 8

The answer is the antiderivative of the function $f (x) = \frac{1}{2 x^{\frac{1}{2}}}$ .

$F (x) =$ $x^{\frac{1}{2}} + C$