Calculus Examples

$x (e^{x} - 1)$

Step 1

Differentiate using the Product Rule which states that $\frac{d}{d x} [f (x) g (x)]$ is $f (x) \frac{d}{d x} [g (x)] + g (x) \frac{d}{d x} [f (x)]$ where $f (x) = x$ and $g (x) = e^{x} - 1$ .

$x \frac{d}{d x} [e^{x} - 1] + (e^{x} - 1) \frac{d}{d x} [x]$

Step 2

By the Sum Rule, the derivative of $e^{x} - 1$ with respect to $x$ is $\frac{d}{d x} [e^{x}] + \frac{d}{d x} [- 1]$ .

$x (\frac{d}{d x} [e^{x}] + \frac{d}{d x} [- 1]) + (e^{x} - 1) \frac{d}{d x} [x]$

Step 3

Differentiate using the Exponential Rule which states that $\frac{d}{d x} [a^{x}]$ is $a^{x} \ln (a)$ where $a$ = $e$ .

$x (e^{x} + \frac{d}{d x} [- 1]) + (e^{x} - 1) \frac{d}{d x} [x]$

Step 4

Differentiate.

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Step 4.1

Since $- 1$ is constant with respect to $x$ , the derivative of $- 1$ with respect to $x$ is $0$ .

$x (e^{x} + 0) + (e^{x} - 1) \frac{d}{d x} [x]$

Step 4.2

Add $e^{x}$ and $0$ .

$x e^{x} + (e^{x} - 1) \frac{d}{d x} [x]$

Step 4.3

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$x e^{x} + (e^{x} - 1) \cdot 1$

Step 4.4

Multiply $e^{x} - 1$ by $1$ .

$x e^{x} + e^{x} - 1$