Calculus Examples

$y = {(9 x^{2} - 2 x + 2)}^{- \frac{3}{4}}$

Step 1

Differentiate both sides of the equation.

$\frac{d}{d x} (y) = \frac{d}{d x} ({(9 x^{2} - 2 x + 2)}^{- \frac{3}{4}})$

Step 2

The derivative of $y$ with respect to $x$ is $y'$ .

$y'$

Step 3

Differentiate the right side of the equation.

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Step 3.1

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = x^{- \frac{3}{4}}$ and $g (x) = 9 x^{2} - 2 x + 2$ .

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Step 3.1.1

To apply the Chain Rule, set $u$ as $9 x^{2} - 2 x + 2$ .

$\frac{d}{d u} [u^{- \frac{3}{4}}] \frac{d}{d x} [9 x^{2} - 2 x + 2]$

Step 3.1.2

Differentiate using the Power Rule which states that $\frac{d}{d u} [u^{n}]$ is $n u^{n - 1}$ where $n = - \frac{3}{4}$ .

$- \frac{3}{4} u^{- \frac{3}{4} - 1} \frac{d}{d x} [9 x^{2} - 2 x + 2]$

Step 3.1.3

Replace all occurrences of $u$ with $9 x^{2} - 2 x + 2$ .

$- \frac{3}{4} {(9 x^{2} - 2 x + 2)}^{- \frac{3}{4} - 1} \frac{d}{d x} [9 x^{2} - 2 x + 2]$

Step 3.2

To write $- 1$ as a fraction with a common denominator, multiply by $\frac{4}{4}$ .

$- \frac{3}{4} {(9 x^{2} - 2 x + 2)}^{- \frac{3}{4} - 1 \cdot \frac{4}{4}} \frac{d}{d x} [9 x^{2} - 2 x + 2]$

Step 3.3

Combine $- 1$ and $\frac{4}{4}$ .

$- \frac{3}{4} {(9 x^{2} - 2 x + 2)}^{- \frac{3}{4} + \frac{- 1 \cdot 4}{4}} \frac{d}{d x} [9 x^{2} - 2 x + 2]$

Step 3.4

Combine the numerators over the common denominator.

$- \frac{3}{4} {(9 x^{2} - 2 x + 2)}^{\frac{- 3 - 1 \cdot 4}{4}} \frac{d}{d x} [9 x^{2} - 2 x + 2]$

Step 3.5

Simplify the numerator.

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Step 3.5.1

Multiply $- 1$ by $4$ .

$- \frac{3}{4} {(9 x^{2} - 2 x + 2)}^{\frac{- 3 - 4}{4}} \frac{d}{d x} [9 x^{2} - 2 x + 2]$

Step 3.5.2

Subtract $4$ from $- 3$ .

$- \frac{3}{4} {(9 x^{2} - 2 x + 2)}^{\frac{- 7}{4}} \frac{d}{d x} [9 x^{2} - 2 x + 2]$

Step 3.6

Combine fractions.

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Step 3.6.1

Move the negative in front of the fraction.

$- \frac{3}{4} {(9 x^{2} - 2 x + 2)}^{- \frac{7}{4}} \frac{d}{d x} [9 x^{2} - 2 x + 2]$

Step 3.6.2

Combine ${(9 x^{2} - 2 x + 2)}^{- \frac{7}{4}}$ and $\frac{3}{4}$ .

$- \frac{{(9 x^{2} - 2 x + 2)}^{- \frac{7}{4}} \cdot 3}{4} \frac{d}{d x} [9 x^{2} - 2 x + 2]$

Step 3.6.3

Simplify the expression.

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Step 3.6.3.1

Move $3$ to the left of ${(9 x^{2} - 2 x + 2)}^{- \frac{7}{4}}$ .

$- \frac{3 \cdot {(9 x^{2} - 2 x + 2)}^{- \frac{7}{4}}}{4} \frac{d}{d x} [9 x^{2} - 2 x + 2]$

Step 3.6.3.2

Move ${(9 x^{2} - 2 x + 2)}^{- \frac{7}{4}}$ to the denominator using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$- \frac{3}{4 {(9 x^{2} - 2 x + 2)}^{\frac{7}{4}}} \frac{d}{d x} [9 x^{2} - 2 x + 2]$

Step 3.7

By the Sum Rule, the derivative of $9 x^{2} - 2 x + 2$ with respect to $x$ is $\frac{d}{d x} [9 x^{2}] + \frac{d}{d x} [- 2 x] + \frac{d}{d x} [2]$ .

$- \frac{3}{4 {(9 x^{2} - 2 x + 2)}^{\frac{7}{4}}} (\frac{d}{d x} [9 x^{2}] + \frac{d}{d x} [- 2 x] + \frac{d}{d x} [2])$

Step 3.8

Since $9$ is constant with respect to $x$ , the derivative of $9 x^{2}$ with respect to $x$ is $9 \frac{d}{d x} [x^{2}]$ .

$- \frac{3}{4 {(9 x^{2} - 2 x + 2)}^{\frac{7}{4}}} (9 \frac{d}{d x} [x^{2}] + \frac{d}{d x} [- 2 x] + \frac{d}{d x} [2])$

Step 3.9

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 2$ .

$- \frac{3}{4 {(9 x^{2} - 2 x + 2)}^{\frac{7}{4}}} (9 (2 x) + \frac{d}{d x} [- 2 x] + \frac{d}{d x} [2])$

Step 3.10

Multiply $2$ by $9$ .

$- \frac{3}{4 {(9 x^{2} - 2 x + 2)}^{\frac{7}{4}}} (18 x + \frac{d}{d x} [- 2 x] + \frac{d}{d x} [2])$

Step 3.11

Since $- 2$ is constant with respect to $x$ , the derivative of $- 2 x$ with respect to $x$ is $- 2 \frac{d}{d x} [x]$ .

$- \frac{3}{4 {(9 x^{2} - 2 x + 2)}^{\frac{7}{4}}} (18 x - 2 \frac{d}{d x} [x] + \frac{d}{d x} [2])$

Step 3.12

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$- \frac{3}{4 {(9 x^{2} - 2 x + 2)}^{\frac{7}{4}}} (18 x - 2 \cdot 1 + \frac{d}{d x} [2])$

Step 3.13

Multiply $- 2$ by $1$ .

$- \frac{3}{4 {(9 x^{2} - 2 x + 2)}^{\frac{7}{4}}} (18 x - 2 + \frac{d}{d x} [2])$

Step 3.14

Since $2$ is constant with respect to $x$ , the derivative of $2$ with respect to $x$ is $0$ .

$- \frac{3}{4 {(9 x^{2} - 2 x + 2)}^{\frac{7}{4}}} (18 x - 2 + 0)$

Step 3.15

Add $18 x - 2$ and $0$ .

$- \frac{3}{4 {(9 x^{2} - 2 x + 2)}^{\frac{7}{4}}} (18 x - 2)$

Step 3.16

Simplify.

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Step 3.16.1

Reorder the factors of $- \frac{3}{4 {(9 x^{2} - 2 x + 2)}^{\frac{7}{4}}} (18 x - 2)$ .

$- (18 x - 2) \frac{3}{4 {(9 x^{2} - 2 x + 2)}^{\frac{7}{4}}}$

Step 3.16.2

Apply the distributive property.

$(- (18 x) - - 2) \frac{3}{4 {(9 x^{2} - 2 x + 2)}^{\frac{7}{4}}}$

Step 3.16.3

Multiply $18$ by $- 1$ .

$(- 18 x - - 2) \frac{3}{4 {(9 x^{2} - 2 x + 2)}^{\frac{7}{4}}}$

Step 3.16.4

Multiply $- 1$ by $- 2$ .

$(- 18 x + 2) \frac{3}{4 {(9 x^{2} - 2 x + 2)}^{\frac{7}{4}}}$

Step 3.16.5

Multiply $- 18 x + 2$ by $\frac{3}{4 {(9 x^{2} - 2 x + 2)}^{\frac{7}{4}}}$ .

$\frac{(- 18 x + 2) \cdot 3}{4 {(9 x^{2} - 2 x + 2)}^{\frac{7}{4}}}$

Step 3.16.6

Factor $2$ out of $(- 18 x + 2) \cdot 3$ .

$\frac{2 ((- 9 x + 1) \cdot 3)}{4 {(9 x^{2} - 2 x + 2)}^{\frac{7}{4}}}$

Step 3.16.7

Cancel the common factors.

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Step 3.16.7.1

Factor $2$ out of $4 {(9 x^{2} - 2 x + 2)}^{\frac{7}{4}}$ .

$\frac{2 ((- 9 x + 1) \cdot 3)}{2 (2 {(9 x^{2} - 2 x + 2)}^{\frac{7}{4}})}$

Step 3.16.7.2

Cancel the common factor.

$\frac{2 ((- 9 x + 1) \cdot 3)}{2 (2 {(9 x^{2} - 2 x + 2)}^{\frac{7}{4}})}$

Step 3.16.7.3

Rewrite the expression.

$\frac{(- 9 x + 1) \cdot 3}{2 {(9 x^{2} - 2 x + 2)}^{\frac{7}{4}}}$

Step 3.16.8

Move $3$ to the left of $- 9 x + 1$ .

$\frac{3 \cdot (- 9 x + 1)}{2 {(9 x^{2} - 2 x + 2)}^{\frac{7}{4}}}$

Step 3.16.9

Factor $- 1$ out of $- 9 x$ .

$\frac{3 (- (9 x) + 1)}{2 {(9 x^{2} - 2 x + 2)}^{\frac{7}{4}}}$

Step 3.16.10

Rewrite $1$ as $- 1 (- 1)$ .

$\frac{3 (- (9 x) - 1 (- 1))}{2 {(9 x^{2} - 2 x + 2)}^{\frac{7}{4}}}$

Step 3.16.11

Factor $- 1$ out of $- (9 x) - 1 (- 1)$ .

$\frac{3 (- (9 x - 1))}{2 {(9 x^{2} - 2 x + 2)}^{\frac{7}{4}}}$

Step 3.16.12

Rewrite $- (9 x - 1)$ as $- 1 (9 x - 1)$ .

$\frac{3 (- 1 (9 x - 1))}{2 {(9 x^{2} - 2 x + 2)}^{\frac{7}{4}}}$

Step 3.16.13

Move the negative in front of the fraction.

$- \frac{3 (9 x - 1)}{2 {(9 x^{2} - 2 x + 2)}^{\frac{7}{4}}}$

Step 4

Reform the equation by setting the left side equal to the right side.

$y' = - \frac{3 (9 x - 1)}{2 {(9 x^{2} - 2 x + 2)}^{\frac{7}{4}}}$

Step 5

Replace $y'$ with $\frac{d y}{d x}$ .

$\frac{d y}{d x} = - \frac{3 (9 x - 1)}{2 {(9 x^{2} - 2 x + 2)}^{\frac{7}{4}}}$