Calculus Examples

$\int (x^{3} + 5 x^{2} - 2) e^{2 x} d x$

Step 1

Apply the distributive property.

$\int x^{3} e^{2 x} + 5 x^{2} e^{2 x} - 2 e^{2 x} d x$

Step 2

Split the single integral into multiple integrals.

$\int x^{3} e^{2 x} d x + \int 5 x^{2} e^{2 x} d x + \int - 2 e^{2 x} d x$

Step 3

Integrate by parts using the formula $\int u d v = u v - \int v d u$ , where $u = x^{3}$ and $d v = e^{2 x}$ .

$x^{3} (\frac{1}{2} e^{2 x}) - \int \frac{1}{2} e^{2 x} (3 x^{2}) d x + \int 5 x^{2} e^{2 x} d x + \int - 2 e^{2 x} d x$

Step 4

Simplify.

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Step 4.1

Combine $\frac{1}{2}$ and $e^{2 x}$ .

$x^{3} \frac{e^{2 x}}{2} - \int \frac{1}{2} e^{2 x} (3 x^{2}) d x + \int 5 x^{2} e^{2 x} d x + \int - 2 e^{2 x} d x$

Step 4.2

Combine $x^{3}$ and $\frac{e^{2 x}}{2}$ .

$\frac{x^{3} e^{2 x}}{2} - \int \frac{1}{2} e^{2 x} (3 x^{2}) d x + \int 5 x^{2} e^{2 x} d x + \int - 2 e^{2 x} d x$

Step 5

Since $\frac{1}{2} \cdot 3$ is constant with respect to $x$ , move $\frac{1}{2} \cdot 3$ out of the integral.

$\frac{x^{3} e^{2 x}}{2} - (\frac{1}{2} \cdot 3 \int e^{2 x} (x^{2}) d x) + \int 5 x^{2} e^{2 x} d x + \int - 2 e^{2 x} d x$

Step 6

Combine $\frac{1}{2}$ and $3$ .

$\frac{x^{3} e^{2 x}}{2} - \frac{3}{2} \int e^{2 x} (x^{2}) d x + \int 5 x^{2} e^{2 x} d x + \int - 2 e^{2 x} d x$

Step 7

Integrate by parts using the formula $\int u d v = u v - \int v d u$ , where $u = x^{2}$ and $d v = e^{2 x}$ .

$\frac{x^{3} e^{2 x}}{2} - \frac{3}{2} (x^{2} (\frac{1}{2} e^{2 x}) - \int \frac{1}{2} e^{2 x} (2 x) d x) + \int 5 x^{2} e^{2 x} d x + \int - 2 e^{2 x} d x$

Step 8

Simplify.

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Step 8.1

Combine $\frac{1}{2}$ and $e^{2 x}$ .

$\frac{x^{3} e^{2 x}}{2} - \frac{3}{2} (x^{2} \frac{e^{2 x}}{2} - \int \frac{1}{2} e^{2 x} (2 x) d x) + \int 5 x^{2} e^{2 x} d x + \int - 2 e^{2 x} d x$

Step 8.2

Combine $x^{2}$ and $\frac{e^{2 x}}{2}$ .

$\frac{x^{3} e^{2 x}}{2} - \frac{3}{2} (\frac{x^{2} e^{2 x}}{2} - \int \frac{1}{2} e^{2 x} (2 x) d x) + \int 5 x^{2} e^{2 x} d x + \int - 2 e^{2 x} d x$

Step 8.3

Combine $\frac{1}{2}$ and $e^{2 x}$ .

$\frac{x^{3} e^{2 x}}{2} - \frac{3}{2} (\frac{x^{2} e^{2 x}}{2} - \int \frac{e^{2 x}}{2} (2 x) d x) + \int 5 x^{2} e^{2 x} d x + \int - 2 e^{2 x} d x$

Step 8.4

Combine $2$ and $\frac{e^{2 x}}{2}$ .

$\frac{x^{3} e^{2 x}}{2} - \frac{3}{2} (\frac{x^{2} e^{2 x}}{2} - \int \frac{2 e^{2 x}}{2} x d x) + \int 5 x^{2} e^{2 x} d x + \int - 2 e^{2 x} d x$

Step 8.5

Combine $\frac{2 e^{2 x}}{2}$ and $x$ .

$\frac{x^{3} e^{2 x}}{2} - \frac{3}{2} (\frac{x^{2} e^{2 x}}{2} - \int \frac{2 e^{2 x} x}{2} d x) + \int 5 x^{2} e^{2 x} d x + \int - 2 e^{2 x} d x$

Step 8.6

Cancel the common factor of $2$ .

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Step 8.6.1

Cancel the common factor.

$\frac{x^{3} e^{2 x}}{2} - \frac{3}{2} (\frac{x^{2} e^{2 x}}{2} - \int \frac{2 e^{2 x} x}{2} d x) + \int 5 x^{2} e^{2 x} d x + \int - 2 e^{2 x} d x$

Step 8.6.2

Divide $e^{2 x} x$ by $1$ .

$\frac{x^{3} e^{2 x}}{2} - \frac{3}{2} (\frac{x^{2} e^{2 x}}{2} - \int e^{2 x} x d x) + \int 5 x^{2} e^{2 x} d x + \int - 2 e^{2 x} d x$

Step 9

Integrate by parts using the formula $\int u d v = u v - \int v d u$ , where $u = x$ and $d v = e^{2 x}$ .

$\frac{x^{3} e^{2 x}}{2} - \frac{3}{2} (\frac{x^{2} e^{2 x}}{2} - (x (\frac{1}{2} e^{2 x}) - \int \frac{1}{2} e^{2 x} d x)) + \int 5 x^{2} e^{2 x} d x + \int - 2 e^{2 x} d x$

Step 10

Simplify.

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Step 10.1

Combine $\frac{1}{2}$ and $e^{2 x}$ .

$\frac{x^{3} e^{2 x}}{2} - \frac{3}{2} (\frac{x^{2} e^{2 x}}{2} - (x \frac{e^{2 x}}{2} - \int \frac{1}{2} e^{2 x} d x)) + \int 5 x^{2} e^{2 x} d x + \int - 2 e^{2 x} d x$

Step 10.2

Combine $x$ and $\frac{e^{2 x}}{2}$ .

$\frac{x^{3} e^{2 x}}{2} - \frac{3}{2} (\frac{x^{2} e^{2 x}}{2} - (\frac{x e^{2 x}}{2} - \int \frac{1}{2} e^{2 x} d x)) + \int 5 x^{2} e^{2 x} d x + \int - 2 e^{2 x} d x$

Step 10.3

Combine $\frac{1}{2}$ and $e^{2 x}$ .

$\frac{x^{3} e^{2 x}}{2} - \frac{3}{2} (\frac{x^{2} e^{2 x}}{2} - (\frac{x e^{2 x}}{2} - \int \frac{e^{2 x}}{2} d x)) + \int 5 x^{2} e^{2 x} d x + \int - 2 e^{2 x} d x$

Step 11

Since $\frac{1}{2}$ is constant with respect to $x$ , move $\frac{1}{2}$ out of the integral.

$\frac{x^{3} e^{2 x}}{2} - \frac{3}{2} (\frac{x^{2} e^{2 x}}{2} - (\frac{x e^{2 x}}{2} - (\frac{1}{2} \int e^{2 x} d x))) + \int 5 x^{2} e^{2 x} d x + \int - 2 e^{2 x} d x$

Step 12

Let $u_{1} = 2 x$ . Then $d u_{1} = 2 d x$ , so $\frac{1}{2} d u_{1} = d x$ . Rewrite using $u_{1}$ and $d$ $u_{1}$ .

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Step 12.1

Let $u_{1} = 2 x$ . Find $\frac{d u_{1}}{d x}$ .

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Step 12.1.1

Differentiate $2 x$ .

$\frac{d}{d x} [2 x]$

Step 12.1.2

Since $2$ is constant with respect to $x$ , the derivative of $2 x$ with respect to $x$ is $2 \frac{d}{d x} [x]$ .

$2 \frac{d}{d x} [x]$

Step 12.1.3

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$2 \cdot 1$

Step 12.1.4

Multiply $2$ by $1$ .

$2$

Step 12.2

Rewrite the problem using $u_{1}$ and $d u_{1}$ .

$\frac{x^{3} e^{2 x}}{2} - \frac{3}{2} (\frac{x^{2} e^{2 x}}{2} - (\frac{x e^{2 x}}{2} - \frac{1}{2} \int e^{u_{1}} \frac{1}{2} d u_{1})) + \int 5 x^{2} e^{2 x} d x + \int - 2 e^{2 x} d x$

Step 13

Combine $e^{u_{1}}$ and $\frac{1}{2}$ .

$\frac{x^{3} e^{2 x}}{2} - \frac{3}{2} (\frac{x^{2} e^{2 x}}{2} - (\frac{x e^{2 x}}{2} - \frac{1}{2} \int \frac{e^{u_{1}}}{2} d u_{1})) + \int 5 x^{2} e^{2 x} d x + \int - 2 e^{2 x} d x$

Step 14

Since $\frac{1}{2}$ is constant with respect to $u_{1}$ , move $\frac{1}{2}$ out of the integral.

$\frac{x^{3} e^{2 x}}{2} - \frac{3}{2} (\frac{x^{2} e^{2 x}}{2} - (\frac{x e^{2 x}}{2} - \frac{1}{2} (\frac{1}{2} \int e^{u_{1}} d u_{1}))) + \int 5 x^{2} e^{2 x} d x + \int - 2 e^{2 x} d x$

Step 15

Simplify.

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Step 15.1

Multiply $\frac{1}{2}$ by $\frac{1}{2}$ .

$\frac{x^{3} e^{2 x}}{2} - \frac{3}{2} (\frac{x^{2} e^{2 x}}{2} - (\frac{x e^{2 x}}{2} - \frac{1}{2 \cdot 2} \int e^{u_{1}} d u_{1})) + \int 5 x^{2} e^{2 x} d x + \int - 2 e^{2 x} d x$

Step 15.2

Multiply $2$ by $2$ .

$\frac{x^{3} e^{2 x}}{2} - \frac{3}{2} (\frac{x^{2} e^{2 x}}{2} - (\frac{x e^{2 x}}{2} - \frac{1}{4} \int e^{u_{1}} d u_{1})) + \int 5 x^{2} e^{2 x} d x + \int - 2 e^{2 x} d x$

Step 16

The integral of $e^{u_{1}}$ with respect to $u_{1}$ is $e^{u_{1}}$ .

$\frac{x^{3} e^{2 x}}{2} - \frac{3}{2} (\frac{x^{2} e^{2 x}}{2} - (\frac{x e^{2 x}}{2} - \frac{1}{4} (e^{u_{1}} + C))) + \int 5 x^{2} e^{2 x} d x + \int - 2 e^{2 x} d x$

Step 17

Since $5$ is constant with respect to $x$ , move $5$ out of the integral.

$\frac{x^{3} e^{2 x}}{2} - \frac{3}{2} (\frac{x^{2} e^{2 x}}{2} - (\frac{x e^{2 x}}{2} - \frac{1}{4} (e^{u_{1}} + C))) + 5 \int x^{2} e^{2 x} d x + \int - 2 e^{2 x} d x$

Step 18

Integrate by parts using the formula $\int u d v = u v - \int v d u$ , where $u = x^{2}$ and $d v = e^{2 x}$ .

$\frac{x^{3} e^{2 x}}{2} - \frac{3}{2} (\frac{x^{2} e^{2 x}}{2} - (\frac{x e^{2 x}}{2} - \frac{1}{4} (e^{u_{1}} + C))) + 5 (x^{2} (\frac{1}{2} e^{2 x}) - \int \frac{1}{2} e^{2 x} (2 x) d x) + \int - 2 e^{2 x} d x$

Step 19

Simplify.

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Step 19.1

Combine $\frac{1}{2}$ and $e^{2 x}$ .

$\frac{x^{3} e^{2 x}}{2} - \frac{3}{2} (\frac{x^{2} e^{2 x}}{2} - (\frac{x e^{2 x}}{2} - \frac{1}{4} (e^{u_{1}} + C))) + 5 (x^{2} \frac{e^{2 x}}{2} - \int \frac{1}{2} e^{2 x} (2 x) d x) + \int - 2 e^{2 x} d x$

Step 19.2

Combine $x^{2}$ and $\frac{e^{2 x}}{2}$ .

$\frac{x^{3} e^{2 x}}{2} - \frac{3}{2} (\frac{x^{2} e^{2 x}}{2} - (\frac{x e^{2 x}}{2} - \frac{1}{4} (e^{u_{1}} + C))) + 5 (\frac{x^{2} e^{2 x}}{2} - \int \frac{1}{2} e^{2 x} (2 x) d x) + \int - 2 e^{2 x} d x$

Step 19.3

Combine $\frac{1}{2}$ and $e^{2 x}$ .

$\frac{x^{3} e^{2 x}}{2} - \frac{3}{2} (\frac{x^{2} e^{2 x}}{2} - (\frac{x e^{2 x}}{2} - \frac{1}{4} (e^{u_{1}} + C))) + 5 (\frac{x^{2} e^{2 x}}{2} - \int \frac{e^{2 x}}{2} (2 x) d x) + \int - 2 e^{2 x} d x$

Step 19.4

Combine $2$ and $\frac{e^{2 x}}{2}$ .

$\frac{x^{3} e^{2 x}}{2} - \frac{3}{2} (\frac{x^{2} e^{2 x}}{2} - (\frac{x e^{2 x}}{2} - \frac{1}{4} (e^{u_{1}} + C))) + 5 (\frac{x^{2} e^{2 x}}{2} - \int \frac{2 e^{2 x}}{2} x d x) + \int - 2 e^{2 x} d x$

Step 19.5

Combine $\frac{2 e^{2 x}}{2}$ and $x$ .

$\frac{x^{3} e^{2 x}}{2} - \frac{3}{2} (\frac{x^{2} e^{2 x}}{2} - (\frac{x e^{2 x}}{2} - \frac{1}{4} (e^{u_{1}} + C))) + 5 (\frac{x^{2} e^{2 x}}{2} - \int \frac{2 e^{2 x} x}{2} d x) + \int - 2 e^{2 x} d x$

Step 19.6

Cancel the common factor of $2$ .

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Step 19.6.1

Cancel the common factor.

Step 19.6.2

Divide $e^{2 x} x$ by $1$ .

$\frac{x^{3} e^{2 x}}{2} - \frac{3}{2} (\frac{x^{2} e^{2 x}}{2} - (\frac{x e^{2 x}}{2} - \frac{1}{4} (e^{u_{1}} + C))) + 5 (\frac{x^{2} e^{2 x}}{2} - \int e^{2 x} x d x) + \int - 2 e^{2 x} d x$

Step 20

Integrate by parts using the formula $\int u d v = u v - \int v d u$ , where $u = x$ and $d v = e^{2 x}$ .

$\frac{x^{3} e^{2 x}}{2} - \frac{3}{2} (\frac{x^{2} e^{2 x}}{2} - (\frac{x e^{2 x}}{2} - \frac{1}{4} (e^{u_{1}} + C))) + 5 (\frac{x^{2} e^{2 x}}{2} - (x (\frac{1}{2} e^{2 x}) - \int \frac{1}{2} e^{2 x} d x)) + \int - 2 e^{2 x} d x$

Step 21

Simplify.

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Step 21.1

Combine $\frac{1}{2}$ and $e^{2 x}$ .

$\frac{x^{3} e^{2 x}}{2} - \frac{3}{2} (\frac{x^{2} e^{2 x}}{2} - (\frac{x e^{2 x}}{2} - \frac{1}{4} (e^{u_{1}} + C))) + 5 (\frac{x^{2} e^{2 x}}{2} - (x \frac{e^{2 x}}{2} - \int \frac{1}{2} e^{2 x} d x)) + \int - 2 e^{2 x} d x$

Step 21.2

Combine $x$ and $\frac{e^{2 x}}{2}$ .

$\frac{x^{3} e^{2 x}}{2} - \frac{3}{2} (\frac{x^{2} e^{2 x}}{2} - (\frac{x e^{2 x}}{2} - \frac{1}{4} (e^{u_{1}} + C))) + 5 (\frac{x^{2} e^{2 x}}{2} - (\frac{x e^{2 x}}{2} - \int \frac{1}{2} e^{2 x} d x)) + \int - 2 e^{2 x} d x$

Step 21.3

Combine $\frac{1}{2}$ and $e^{2 x}$ .

Step 22

Since $\frac{1}{2}$ is constant with respect to $x$ , move $\frac{1}{2}$ out of the integral.

$\frac{x^{3} e^{2 x}}{2} - \frac{3}{2} (\frac{x^{2} e^{2 x}}{2} - (\frac{x e^{2 x}}{2} - \frac{1}{4} (e^{u_{1}} + C))) + 5 (\frac{x^{2} e^{2 x}}{2} - (\frac{x e^{2 x}}{2} - (\frac{1}{2} \int e^{2 x} d x))) + \int - 2 e^{2 x} d x$

Step 23

Let $u_{2} = 2 x$ . Then $d u_{2} = 2 d x$ , so $\frac{1}{2} d u_{2} = d x$ . Rewrite using $u_{2}$ and $d$ $u_{2}$ .

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Step 23.1

Let $u_{2} = 2 x$ . Find $\frac{d u_{2}}{d x}$ .

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Step 23.1.1

Differentiate $2 x$ .

$\frac{d}{d x} [2 x]$

Step 23.1.2

Since $2$ is constant with respect to $x$ , the derivative of $2 x$ with respect to $x$ is $2 \frac{d}{d x} [x]$ .

$2 \frac{d}{d x} [x]$

Step 23.1.3

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$2 \cdot 1$

Step 23.1.4

Multiply $2$ by $1$ .

$2$

Step 23.2

Rewrite the problem using $u_{2}$ and $d u_{2}$ .

$\frac{x^{3} e^{2 x}}{2} - \frac{3}{2} (\frac{x^{2} e^{2 x}}{2} - (\frac{x e^{2 x}}{2} - \frac{1}{4} (e^{u_{1}} + C))) + 5 (\frac{x^{2} e^{2 x}}{2} - (\frac{x e^{2 x}}{2} - \frac{1}{2} \int e^{u_{2}} \frac{1}{2} d u_{2})) + \int - 2 e^{2 x} d x$

Step 24

Combine $e^{u_{2}}$ and $\frac{1}{2}$ .

$\frac{x^{3} e^{2 x}}{2} - \frac{3}{2} (\frac{x^{2} e^{2 x}}{2} - (\frac{x e^{2 x}}{2} - \frac{1}{4} (e^{u_{1}} + C))) + 5 (\frac{x^{2} e^{2 x}}{2} - (\frac{x e^{2 x}}{2} - \frac{1}{2} \int \frac{e^{u_{2}}}{2} d u_{2})) + \int - 2 e^{2 x} d x$

Step 25

Since $\frac{1}{2}$ is constant with respect to $u_{2}$ , move $\frac{1}{2}$ out of the integral.

$\frac{x^{3} e^{2 x}}{2} - \frac{3}{2} (\frac{x^{2} e^{2 x}}{2} - (\frac{x e^{2 x}}{2} - \frac{1}{4} (e^{u_{1}} + C))) + 5 (\frac{x^{2} e^{2 x}}{2} - (\frac{x e^{2 x}}{2} - \frac{1}{2} (\frac{1}{2} \int e^{u_{2}} d u_{2}))) + \int - 2 e^{2 x} d x$

Step 26

Simplify.

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Step 26.1

Multiply $\frac{1}{2}$ by $\frac{1}{2}$ .

$\frac{x^{3} e^{2 x}}{2} - \frac{3}{2} (\frac{x^{2} e^{2 x}}{2} - (\frac{x e^{2 x}}{2} - \frac{1}{4} (e^{u_{1}} + C))) + 5 (\frac{x^{2} e^{2 x}}{2} - (\frac{x e^{2 x}}{2} - \frac{1}{2 \cdot 2} \int e^{u_{2}} d u_{2})) + \int - 2 e^{2 x} d x$

Step 26.2

Multiply $2$ by $2$ .

$\frac{x^{3} e^{2 x}}{2} - \frac{3}{2} (\frac{x^{2} e^{2 x}}{2} - (\frac{x e^{2 x}}{2} - \frac{1}{4} (e^{u_{1}} + C))) + 5 (\frac{x^{2} e^{2 x}}{2} - (\frac{x e^{2 x}}{2} - \frac{1}{4} \int e^{u_{2}} d u_{2})) + \int - 2 e^{2 x} d x$

Step 27

The integral of $e^{u_{2}}$ with respect to $u_{2}$ is $e^{u_{2}}$ .

Step 28

Since $- 2$ is constant with respect to $x$ , move $- 2$ out of the integral.

Step 29

Let $u_{3} = 2 x$ . Then $d u_{3} = 2 d x$ , so $\frac{1}{2} d u_{3} = d x$ . Rewrite using $u_{3}$ and $d$ $u_{3}$ .

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Step 29.1

Let $u_{3} = 2 x$ . Find $\frac{d u_{3}}{d x}$ .

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Step 29.1.1

Differentiate $2 x$ .

$\frac{d}{d x} [2 x]$

Step 29.1.2

Since $2$ is constant with respect to $x$ , the derivative of $2 x$ with respect to $x$ is $2 \frac{d}{d x} [x]$ .

$2 \frac{d}{d x} [x]$

Step 29.1.3

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$2 \cdot 1$

Step 29.1.4

Multiply $2$ by $1$ .

$2$

Step 29.2

Rewrite the problem using $u_{3}$ and $d u_{3}$ .

$\frac{x^{3} e^{2 x}}{2} - \frac{3}{2} (\frac{x^{2} e^{2 x}}{2} - (\frac{x e^{2 x}}{2} - \frac{1}{4} (e^{u_{1}} + C))) + 5 (\frac{x^{2} e^{2 x}}{2} - (\frac{x e^{2 x}}{2} - \frac{1}{4} (e^{u_{2}} + C))) - 2 \int e^{u_{3}} \frac{1}{2} d u_{3}$

Step 30

Combine $e^{u_{3}}$ and $\frac{1}{2}$ .

$\frac{x^{3} e^{2 x}}{2} - \frac{3}{2} (\frac{x^{2} e^{2 x}}{2} - (\frac{x e^{2 x}}{2} - \frac{1}{4} (e^{u_{1}} + C))) + 5 (\frac{x^{2} e^{2 x}}{2} - (\frac{x e^{2 x}}{2} - \frac{1}{4} (e^{u_{2}} + C))) - 2 \int \frac{e^{u_{3}}}{2} d u_{3}$

Step 31

Since $\frac{1}{2}$ is constant with respect to $u_{3}$ , move $\frac{1}{2}$ out of the integral.

$\frac{x^{3} e^{2 x}}{2} - \frac{3}{2} (\frac{x^{2} e^{2 x}}{2} - (\frac{x e^{2 x}}{2} - \frac{1}{4} (e^{u_{1}} + C))) + 5 (\frac{x^{2} e^{2 x}}{2} - (\frac{x e^{2 x}}{2} - \frac{1}{4} (e^{u_{2}} + C))) - 2 (\frac{1}{2} \int e^{u_{3}} d u_{3})$

Step 32

Simplify.

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Step 32.1

Combine $\frac{1}{2}$ and $- 2$ .

$\frac{x^{3} e^{2 x}}{2} - \frac{3}{2} (\frac{x^{2} e^{2 x}}{2} - (\frac{x e^{2 x}}{2} - \frac{1}{4} (e^{u_{1}} + C))) + 5 (\frac{x^{2} e^{2 x}}{2} - (\frac{x e^{2 x}}{2} - \frac{1}{4} (e^{u_{2}} + C))) + \frac{- 2}{2} \int e^{u_{3}} d u_{3}$

Step 32.2

Cancel the common factor of $- 2$ and $2$ .

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Step 32.2.1

Factor $2$ out of $- 2$ .

$\frac{x^{3} e^{2 x}}{2} - \frac{3}{2} (\frac{x^{2} e^{2 x}}{2} - (\frac{x e^{2 x}}{2} - \frac{1}{4} (e^{u_{1}} + C))) + 5 (\frac{x^{2} e^{2 x}}{2} - (\frac{x e^{2 x}}{2} - \frac{1}{4} (e^{u_{2}} + C))) + \frac{2 \cdot - 1}{2} \int e^{u_{3}} d u_{3}$

Step 32.2.2

Cancel the common factors.

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Step 32.2.2.1

Factor $2$ out of $2$ .

$\frac{x^{3} e^{2 x}}{2} - \frac{3}{2} (\frac{x^{2} e^{2 x}}{2} - (\frac{x e^{2 x}}{2} - \frac{1}{4} (e^{u_{1}} + C))) + 5 (\frac{x^{2} e^{2 x}}{2} - (\frac{x e^{2 x}}{2} - \frac{1}{4} (e^{u_{2}} + C))) + \frac{2 \cdot - 1}{2 (1)} \int e^{u_{3}} d u_{3}$

Step 32.2.2.2

Cancel the common factor.

$\frac{x^{3} e^{2 x}}{2} - \frac{3}{2} (\frac{x^{2} e^{2 x}}{2} - (\frac{x e^{2 x}}{2} - \frac{1}{4} (e^{u_{1}} + C))) + 5 (\frac{x^{2} e^{2 x}}{2} - (\frac{x e^{2 x}}{2} - \frac{1}{4} (e^{u_{2}} + C))) + \frac{2 \cdot - 1}{2 \cdot 1} \int e^{u_{3}} d u_{3}$

Step 32.2.2.3

Rewrite the expression.

$\frac{x^{3} e^{2 x}}{2} - \frac{3}{2} (\frac{x^{2} e^{2 x}}{2} - (\frac{x e^{2 x}}{2} - \frac{1}{4} (e^{u_{1}} + C))) + 5 (\frac{x^{2} e^{2 x}}{2} - (\frac{x e^{2 x}}{2} - \frac{1}{4} (e^{u_{2}} + C))) + \frac{- 1}{1} \int e^{u_{3}} d u_{3}$

Step 32.2.2.4

Divide $- 1$ by $1$ .

Step 33

The integral of $e^{u_{3}}$ with respect to $u_{3}$ is $e^{u_{3}}$ .

Step 34

Simplify.

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Step 34.1

Simplify.

$\frac{x^{3} e^{2 x}}{2} - \frac{3 x^{2} e^{2 x}}{4} + \frac{3 x e^{2 x}}{4} - \frac{3 e^{u_{1}}}{8} + \frac{5 x^{2} e^{2 x}}{2} - \frac{5 x e^{2 x}}{2} + \frac{5 e^{u_{2}}}{4} - e^{u_{3}} + C$

Step 34.2

Simplify.

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Step 34.2.1

To write $\frac{5 x^{2} e^{2 x}}{2}$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$\frac{x^{3} e^{2 x}}{2} - \frac{3 x^{2} e^{2 x}}{4} + \frac{5 x^{2} e^{2 x}}{2} \cdot \frac{2}{2} + \frac{3 x e^{2 x}}{4} - \frac{3 e^{u_{1}}}{8} - \frac{5 x e^{2 x}}{2} + \frac{5 e^{u_{2}}}{4} - e^{u_{3}} + C$

Step 34.2.2

Write each expression with a common denominator of $4$ , by multiplying each by an appropriate factor of $1$ .

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Step 34.2.2.1

Multiply $\frac{5 x^{2} e^{2 x}}{2}$ by $\frac{2}{2}$ .

$\frac{x^{3} e^{2 x}}{2} - \frac{3 x^{2} e^{2 x}}{4} + \frac{5 x^{2} e^{2 x} \cdot 2}{2 \cdot 2} + \frac{3 x e^{2 x}}{4} - \frac{3 e^{u_{1}}}{8} - \frac{5 x e^{2 x}}{2} + \frac{5 e^{u_{2}}}{4} - e^{u_{3}} + C$

Step 34.2.2.2

Multiply $2$ by $2$ .

$\frac{x^{3} e^{2 x}}{2} - \frac{3 x^{2} e^{2 x}}{4} + \frac{5 x^{2} e^{2 x} \cdot 2}{4} + \frac{3 x e^{2 x}}{4} - \frac{3 e^{u_{1}}}{8} - \frac{5 x e^{2 x}}{2} + \frac{5 e^{u_{2}}}{4} - e^{u_{3}} + C$

Step 34.2.3

Combine the numerators over the common denominator.

$\frac{x^{3} e^{2 x}}{2} + \frac{- 3 x^{2} e^{2 x} + 5 x^{2} e^{2 x} \cdot 2}{4} + \frac{3 x e^{2 x}}{4} - \frac{3 e^{u_{1}}}{8} - \frac{5 x e^{2 x}}{2} + \frac{5 e^{u_{2}}}{4} - e^{u_{3}} + C$

Step 34.2.4

Multiply $2$ by $5$ .

$\frac{x^{3} e^{2 x}}{2} + \frac{- 3 x^{2} e^{2 x} + 10 x^{2} e^{2 x}}{4} + \frac{3 x e^{2 x}}{4} - \frac{3 e^{u_{1}}}{8} - \frac{5 x e^{2 x}}{2} + \frac{5 e^{u_{2}}}{4} - e^{u_{3}} + C$

Step 34.2.5

Add $- 3 x^{2} e^{2 x}$ and $10 x^{2} e^{2 x}$ .

$\frac{x^{3} e^{2 x}}{2} + \frac{7 x^{2} e^{2 x}}{4} + \frac{3 x e^{2 x}}{4} - \frac{3 e^{u_{1}}}{8} - \frac{5 x e^{2 x}}{2} + \frac{5 e^{u_{2}}}{4} - e^{u_{3}} + C$

Step 34.2.6

To write $- \frac{5 x e^{2 x}}{2}$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$\frac{x^{3} e^{2 x}}{2} + \frac{7 x^{2} e^{2 x}}{4} + \frac{3 x e^{2 x}}{4} - \frac{5 x e^{2 x}}{2} \cdot \frac{2}{2} - \frac{3 e^{u_{1}}}{8} + \frac{5 e^{u_{2}}}{4} - e^{u_{3}} + C$

Step 34.2.7

Write each expression with a common denominator of $4$ , by multiplying each by an appropriate factor of $1$ .

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Step 34.2.7.1

Multiply $\frac{5 x e^{2 x}}{2}$ by $\frac{2}{2}$ .

$\frac{x^{3} e^{2 x}}{2} + \frac{7 x^{2} e^{2 x}}{4} + \frac{3 x e^{2 x}}{4} - \frac{5 x e^{2 x} \cdot 2}{2 \cdot 2} - \frac{3 e^{u_{1}}}{8} + \frac{5 e^{u_{2}}}{4} - e^{u_{3}} + C$

Step 34.2.7.2

Multiply $2$ by $2$ .

$\frac{x^{3} e^{2 x}}{2} + \frac{7 x^{2} e^{2 x}}{4} + \frac{3 x e^{2 x}}{4} - \frac{5 x e^{2 x} \cdot 2}{4} - \frac{3 e^{u_{1}}}{8} + \frac{5 e^{u_{2}}}{4} - e^{u_{3}} + C$

Step 34.2.8

Combine the numerators over the common denominator.

$\frac{x^{3} e^{2 x}}{2} + \frac{7 x^{2} e^{2 x}}{4} + \frac{3 x e^{2 x} - 5 x e^{2 x} \cdot 2}{4} - \frac{3 e^{u_{1}}}{8} + \frac{5 e^{u_{2}}}{4} - e^{u_{3}} + C$

Step 34.2.9

Multiply $2$ by $- 5$ .

$\frac{x^{3} e^{2 x}}{2} + \frac{7 x^{2} e^{2 x}}{4} + \frac{3 x e^{2 x} - 10 x e^{2 x}}{4} - \frac{3 e^{u_{1}}}{8} + \frac{5 e^{u_{2}}}{4} - e^{u_{3}} + C$

Step 34.2.10

Subtract $10 x e^{2 x}$ from $3 x e^{2 x}$ .

$\frac{x^{3} e^{2 x}}{2} + \frac{7 x^{2} e^{2 x}}{4} + \frac{- 7 x e^{2 x}}{4} - \frac{3 e^{u_{1}}}{8} + \frac{5 e^{u_{2}}}{4} - e^{u_{3}} + C$

Step 34.2.11

Move the negative in front of the fraction.

$\frac{x^{3} e^{2 x}}{2} + \frac{7 x^{2} e^{2 x}}{4} - \frac{7 x e^{2 x}}{4} - \frac{3 e^{u_{1}}}{8} + \frac{5 e^{u_{2}}}{4} - e^{u_{3}} + C$

Step 34.2.12

To write $\frac{5 e^{u_{2}}}{4}$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$\frac{x^{3} e^{2 x}}{2} + \frac{7 x^{2} e^{2 x}}{4} - \frac{7 x e^{2 x}}{4} - \frac{3 e^{u_{1}}}{8} + \frac{5 e^{u_{2}}}{4} \cdot \frac{2}{2} - e^{u_{3}} + C$

Step 34.2.13

Write each expression with a common denominator of $8$ , by multiplying each by an appropriate factor of $1$ .

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Step 34.2.13.1

Multiply $\frac{5 e^{u_{2}}}{4}$ by $\frac{2}{2}$ .

$\frac{x^{3} e^{2 x}}{2} + \frac{7 x^{2} e^{2 x}}{4} - \frac{7 x e^{2 x}}{4} - \frac{3 e^{u_{1}}}{8} + \frac{5 e^{u_{2}} \cdot 2}{4 \cdot 2} - e^{u_{3}} + C$

Step 34.2.13.2

Multiply $4$ by $2$ .

$\frac{x^{3} e^{2 x}}{2} + \frac{7 x^{2} e^{2 x}}{4} - \frac{7 x e^{2 x}}{4} - \frac{3 e^{u_{1}}}{8} + \frac{5 e^{u_{2}} \cdot 2}{8} - e^{u_{3}} + C$

Step 34.2.14

Combine the numerators over the common denominator.

$\frac{x^{3} e^{2 x}}{2} + \frac{7 x^{2} e^{2 x}}{4} - \frac{7 x e^{2 x}}{4} + \frac{- 3 e^{u_{1}} + 5 e^{u_{2}} \cdot 2}{8} - e^{u_{3}} + C$

Step 34.2.15

Multiply $2$ by $5$ .

$\frac{x^{3} e^{2 x}}{2} + \frac{7 x^{2} e^{2 x}}{4} - \frac{7 x e^{2 x}}{4} + \frac{- 3 e^{u_{1}} + 10 e^{u_{2}}}{8} - e^{u_{3}} + C$

Step 34.2.16

Add $- 3 e^{u_{1}}$ and $10 e^{u_{2}}$ .

$\frac{x^{3} e^{2 x}}{2} + \frac{7 x^{2} e^{2 x}}{4} - \frac{7 x e^{2 x}}{4} + \frac{7 e^{u_{1}}}{8} - e^{u_{3}} + C$

Step 34.2.17

To write $- e^{u_{3}}$ as a fraction with a common denominator, multiply by $\frac{8}{8}$ .

$\frac{x^{3} e^{2 x}}{2} + \frac{7 x^{2} e^{2 x}}{4} - \frac{7 x e^{2 x}}{4} + \frac{7 e^{u_{1}}}{8} - e^{u_{3}} \cdot \frac{8}{8} + C$

Step 34.2.18

Combine $- e^{u_{3}}$ and $\frac{8}{8}$ .

$\frac{x^{3} e^{2 x}}{2} + \frac{7 x^{2} e^{2 x}}{4} - \frac{7 x e^{2 x}}{4} + \frac{7 e^{u_{1}}}{8} + \frac{- e^{u_{3}} \cdot 8}{8} + C$

Step 34.2.19

Combine the numerators over the common denominator.

$\frac{x^{3} e^{2 x}}{2} + \frac{7 x^{2} e^{2 x}}{4} - \frac{7 x e^{2 x}}{4} + \frac{7 e^{u_{1}} - e^{u_{3}} \cdot 8}{8} + C$

Step 34.2.20

Multiply $8$ by $- 1$ .

$\frac{x^{3} e^{2 x}}{2} + \frac{7 x^{2} e^{2 x}}{4} - \frac{7 x e^{2 x}}{4} + \frac{7 e^{u_{1}} - 8 e^{u_{3}}}{8} + C$

Step 34.2.21

Subtract $8 e^{u_{3}}$ from $7 e^{u_{1}}$ .

$\frac{x^{3} e^{2 x}}{2} + \frac{7 x^{2} e^{2 x}}{4} - \frac{7 x e^{2 x}}{4} + \frac{- e^{u_{1}}}{8} + C$

Step 34.2.22

Move the negative in front of the fraction.

$\frac{x^{3} e^{2 x}}{2} + \frac{7 x^{2} e^{2 x}}{4} - \frac{7 x e^{2 x}}{4} - \frac{e^{u_{1}}}{8} + C$

Step 35

Replace all occurrences of $u_{1}$ with $2 x$ .

$\frac{x^{3} e^{2 x}}{2} + \frac{7 x^{2} e^{2 x}}{4} - \frac{7 x e^{2 x}}{4} - \frac{e^{2 x}}{8} + C$

Step 36

Reorder terms.

$\frac{1}{2} x^{3} e^{2 x} + \frac{7}{4} x^{2} e^{2 x} - \frac{7}{4} x e^{2 x} - \frac{1}{8} e^{2 x} + C$