Calculus Examples

$\frac{1}{e^{2 - 5 x}}$

Step 1

Write $\frac{1}{e^{2 - 5 x}}$ as a function.

$f (x) = \frac{1}{e^{2 - 5 x}}$

Step 2

The function $F (x)$ can be found by finding the indefinite integral of the derivative $f (x)$ .

$F (x) = \int f (x) d x$

Step 3

Set up the integral to solve.

$F (x) = \int \frac{1}{e^{2 - 5 x}} d x$

Step 4

Simplify the expression.

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Step 4.1

Negate the exponent of $e^{2 - 5 x}$ and move it out of the denominator.

$\int 1 {(e^{2 - 5 x})}^{- 1} d x$

Step 4.2

Simplify.

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Step 4.2.1

Multiply the exponents in ${(e^{2 - 5 x})}^{- 1}$ .

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Step 4.2.1.1

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$\int 1 e^{(2 - 5 x) \cdot - 1} d x$

Step 4.2.1.2

Apply the distributive property.

$\int 1 e^{2 \cdot - 1 - 5 x \cdot - 1} d x$

Step 4.2.1.3

Multiply $2$ by $- 1$ .

$\int 1 e^{- 2 - 5 x \cdot - 1} d x$

Step 4.2.1.4

Multiply $- 1$ by $- 5$ .

$\int 1 e^{- 2 + 5 x} d x$

Step 4.2.2

Multiply $e^{- 2 + 5 x}$ by $1$ .

$\int e^{- 2 + 5 x} d x$

Step 5

Let $u = - 2 + 5 x$ . Then $d u = 5 d x$ , so $\frac{1}{5} d u = d x$ . Rewrite using $u$ and $d$ $u$ .

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Step 5.1

Let $u = - 2 + 5 x$ . Find $\frac{d u}{d x}$ .

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Step 5.1.1

Differentiate $- 2 + 5 x$ .

$\frac{d}{d x} [- 2 + 5 x]$

Step 5.1.2

Differentiate.

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Step 5.1.2.1

By the Sum Rule, the derivative of $- 2 + 5 x$ with respect to $x$ is $\frac{d}{d x} [- 2] + \frac{d}{d x} [5 x]$ .

$\frac{d}{d x} [- 2] + \frac{d}{d x} [5 x]$

Step 5.1.2.2

Since $- 2$ is constant with respect to $x$ , the derivative of $- 2$ with respect to $x$ is $0$ .

$0 + \frac{d}{d x} [5 x]$

Step 5.1.3

Evaluate $\frac{d}{d x} [5 x]$ .

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Step 5.1.3.1

Since $5$ is constant with respect to $x$ , the derivative of $5 x$ with respect to $x$ is $5 \frac{d}{d x} [x]$ .

$0 + 5 \frac{d}{d x} [x]$

Step 5.1.3.2

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$0 + 5 \cdot 1$

Step 5.1.3.3

Multiply $5$ by $1$ .

$0 + 5$

Step 5.1.4

Add $0$ and $5$ .

$5$

Step 5.2

Rewrite the problem using $u$ and $d u$ .

$\int e^{u} \frac{1}{5} d u$

Step 6

Combine $e^{u}$ and $\frac{1}{5}$ .

$\int \frac{e^{u}}{5} d u$

Step 7

Since $\frac{1}{5}$ is constant with respect to $u$ , move $\frac{1}{5}$ out of the integral.

$\frac{1}{5} \int e^{u} d u$

Step 8

The integral of $e^{u}$ with respect to $u$ is $e^{u}$ .

$\frac{1}{5} (e^{u} + C)$

Step 9

Simplify.

$\frac{1}{5} e^{u} + C$

Step 10

Replace all occurrences of $u$ with $- 2 + 5 x$ .

$\frac{1}{5} e^{- 2 + 5 x} + C$

Step 11

The answer is the antiderivative of the function $f (x) = \frac{1}{e^{2 - 5 x}}$ .

$F (x) =$ $\frac{1}{5} e^{- 2 + 5 x} + C$