Calculus Examples

$\int_{0}^{\sqrt{x}} t d t$

Step 1

Take the derivative of $\int_{0}^{\sqrt{x}} t d t$ with respect to $x$ using Fundamental Theorem of Calculus and the chain rule.

$\frac{d}{d x} [\sqrt{x}] \sqrt{x}$

Step 2

Differentiate using the Power Rule.

Tap for more steps...

Step 2.1

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{x}$ as $x^{\frac{1}{2}}$ .

$\frac{d}{d x} [x^{\frac{1}{2}}] \sqrt{x}$

Step 2.2

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = \frac{1}{2}$ .

$\frac{1}{2} x^{\frac{1}{2} - 1} \sqrt{x}$

Step 3

To write $- 1$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$\frac{1}{2} x^{\frac{1}{2} - 1 \cdot \frac{2}{2}} \sqrt{x}$

Step 4

Combine $- 1$ and $\frac{2}{2}$ .

$\frac{1}{2} x^{\frac{1}{2} + \frac{- 1 \cdot 2}{2}} \sqrt{x}$

Step 5

Combine the numerators over the common denominator.

$\frac{1}{2} x^{\frac{1 - 1 \cdot 2}{2}} \sqrt{x}$

Step 6

Simplify the numerator.

Tap for more steps...

Step 6.1

Multiply $- 1$ by $2$ .

$\frac{1}{2} x^{\frac{1 - 2}{2}} \sqrt{x}$

Step 6.2

Subtract $2$ from $1$ .

$\frac{1}{2} x^{\frac{- 1}{2}} \sqrt{x}$

Step 7

Move the negative in front of the fraction.

$\frac{1}{2} x^{- \frac{1}{2}} \sqrt{x}$

Step 8

Simplify.

Tap for more steps...

Step 8.1

Rewrite the expression using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$\frac{1}{2} \cdot \frac{1}{x^{\frac{1}{2}}} \sqrt{x}$

Step 8.2

Multiply $\frac{1}{2}$ by $\frac{1}{x^{\frac{1}{2}}}$ .

$\frac{1}{2 x^{\frac{1}{2}}} \sqrt{x}$

Step 9

Combine $\frac{1}{2 x^{\frac{1}{2}}}$ and $\sqrt{x}$ .

$\frac{\sqrt{x}}{2 x^{\frac{1}{2}}}$