Calculus Examples

$\int \frac{x^{7} \sqrt{x}}{x^{5}} - 3 \sqrt[3]{x} + 5 x^{4} - \frac{1}{2 x} + e^{x} + 2021 d x$

Step 1

Simplify.

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Step 1.1

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{x}$ as $x^{\frac{1}{2}}$ .

$\int \frac{x^{7} x^{\frac{1}{2}}}{x^{5}} - 3 \sqrt[3]{x} + 5 x^{4} - \frac{1}{2 x} + e^{x} + 2021 d x$

Step 1.2

Multiply $x^{7}$ by $x^{\frac{1}{2}}$ by adding the exponents.

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Step 1.2.1

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\int \frac{x^{7 + \frac{1}{2}}}{x^{5}} - 3 \sqrt[3]{x} + 5 x^{4} - \frac{1}{2 x} + e^{x} + 2021 d x$

Step 1.2.2

To write $7$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$\int \frac{x^{7 \cdot \frac{2}{2} + \frac{1}{2}}}{x^{5}} - 3 \sqrt[3]{x} + 5 x^{4} - \frac{1}{2 x} + e^{x} + 2021 d x$

Step 1.2.3

Combine $7$ and $\frac{2}{2}$ .

$\int \frac{x^{\frac{7 \cdot 2}{2} + \frac{1}{2}}}{x^{5}} - 3 \sqrt[3]{x} + 5 x^{4} - \frac{1}{2 x} + e^{x} + 2021 d x$

Step 1.2.4

Combine the numerators over the common denominator.

$\int \frac{x^{\frac{7 \cdot 2 + 1}{2}}}{x^{5}} - 3 \sqrt[3]{x} + 5 x^{4} - \frac{1}{2 x} + e^{x} + 2021 d x$

Step 1.2.5

Simplify the numerator.

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Step 1.2.5.1

Multiply $7$ by $2$ .

$\int \frac{x^{\frac{14 + 1}{2}}}{x^{5}} - 3 \sqrt[3]{x} + 5 x^{4} - \frac{1}{2 x} + e^{x} + 2021 d x$

Step 1.2.5.2

Add $14$ and $1$ .

$\int \frac{x^{\frac{15}{2}}}{x^{5}} - 3 \sqrt[3]{x} + 5 x^{4} - \frac{1}{2 x} + e^{x} + 2021 d x$

Step 1.3

Move $x^{5}$ to the numerator using the negative exponent rule $\frac{1}{b^{n}} = b^{- n}$ .

$\int x^{\frac{15}{2}} x^{- 5} - 3 \sqrt[3]{x} + 5 x^{4} - \frac{1}{2 x} + e^{x} + 2021 d x$

Step 1.4

Multiply $x^{\frac{15}{2}}$ by $x^{- 5}$ by adding the exponents.

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Step 1.4.1

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\int x^{\frac{15}{2} - 5} - 3 \sqrt[3]{x} + 5 x^{4} - \frac{1}{2 x} + e^{x} + 2021 d x$

Step 1.4.2

To write $- 5$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$\int x^{\frac{15}{2} - 5 \cdot \frac{2}{2}} - 3 \sqrt[3]{x} + 5 x^{4} - \frac{1}{2 x} + e^{x} + 2021 d x$

Step 1.4.3

Combine $- 5$ and $\frac{2}{2}$ .

$\int x^{\frac{15}{2} + \frac{- 5 \cdot 2}{2}} - 3 \sqrt[3]{x} + 5 x^{4} - \frac{1}{2 x} + e^{x} + 2021 d x$

Step 1.4.4

Combine the numerators over the common denominator.

$\int x^{\frac{15 - 5 \cdot 2}{2}} - 3 \sqrt[3]{x} + 5 x^{4} - \frac{1}{2 x} + e^{x} + 2021 d x$

Step 1.4.5

Simplify the numerator.

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Step 1.4.5.1

Multiply $- 5$ by $2$ .

$\int x^{\frac{15 - 10}{2}} - 3 \sqrt[3]{x} + 5 x^{4} - \frac{1}{2 x} + e^{x} + 2021 d x$

Step 1.4.5.2

Subtract $10$ from $15$ .

$\int x^{\frac{5}{2}} - 3 \sqrt[3]{x} + 5 x^{4} - \frac{1}{2 x} + e^{x} + 2021 d x$

Step 2

Split the single integral into multiple integrals.

$\int x^{\frac{5}{2}} d x + \int - 3 \sqrt[3]{x} d x + \int 5 x^{4} d x + \int - \frac{1}{2 x} d x + \int e^{x} d x + \int 2021 d x$

Step 3

By the Power Rule, the integral of $x^{\frac{5}{2}}$ with respect to $x$ is $\frac{2}{7} x^{\frac{7}{2}}$ .

$\frac{2}{7} x^{\frac{7}{2}} + C + \int - 3 \sqrt[3]{x} d x + \int 5 x^{4} d x + \int - \frac{1}{2 x} d x + \int e^{x} d x + \int 2021 d x$

Step 4

Since $- 3$ is constant with respect to $x$ , move $- 3$ out of the integral.

$\frac{2}{7} x^{\frac{7}{2}} + C - 3 \int \sqrt[3]{x} d x + \int 5 x^{4} d x + \int - \frac{1}{2 x} d x + \int e^{x} d x + \int 2021 d x$

Step 5

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt[3]{x}$ as $x^{\frac{1}{3}}$ .

$\frac{2}{7} x^{\frac{7}{2}} + C - 3 \int x^{\frac{1}{3}} d x + \int 5 x^{4} d x + \int - \frac{1}{2 x} d x + \int e^{x} d x + \int 2021 d x$

Step 6

By the Power Rule, the integral of $x^{\frac{1}{3}}$ with respect to $x$ is $\frac{3}{4} x^{\frac{4}{3}}$ .

$\frac{2}{7} x^{\frac{7}{2}} + C - 3 (\frac{3}{4} x^{\frac{4}{3}} + C) + \int 5 x^{4} d x + \int - \frac{1}{2 x} d x + \int e^{x} d x + \int 2021 d x$

Step 7

Since $5$ is constant with respect to $x$ , move $5$ out of the integral.

$\frac{2}{7} x^{\frac{7}{2}} + C - 3 (\frac{3}{4} x^{\frac{4}{3}} + C) + 5 \int x^{4} d x + \int - \frac{1}{2 x} d x + \int e^{x} d x + \int 2021 d x$

Step 8

By the Power Rule, the integral of $x^{4}$ with respect to $x$ is $\frac{1}{5} x^{5}$ .

$\frac{2}{7} x^{\frac{7}{2}} + C - 3 (\frac{3}{4} x^{\frac{4}{3}} + C) + 5 (\frac{1}{5} x^{5} + C) + \int - \frac{1}{2 x} d x + \int e^{x} d x + \int 2021 d x$

Step 9

Since $- 1$ is constant with respect to $x$ , move $- 1$ out of the integral.

$\frac{2}{7} x^{\frac{7}{2}} + C - 3 (\frac{3}{4} x^{\frac{4}{3}} + C) + 5 (\frac{1}{5} x^{5} + C) - \int \frac{1}{2 x} d x + \int e^{x} d x + \int 2021 d x$

Step 10

Since $\frac{1}{2}$ is constant with respect to $x$ , move $\frac{1}{2}$ out of the integral.

$\frac{2}{7} x^{\frac{7}{2}} + C - 3 (\frac{3}{4} x^{\frac{4}{3}} + C) + 5 (\frac{1}{5} x^{5} + C) - (\frac{1}{2} \int \frac{1}{x} d x) + \int e^{x} d x + \int 2021 d x$

Step 11

Simplify.

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Step 11.1

Combine $\frac{3}{4}$ and $x^{\frac{4}{3}}$ .

$\frac{2}{7} x^{\frac{7}{2}} + C - 3 (\frac{3 x^{\frac{4}{3}}}{4} + C) + 5 (\frac{1}{5} x^{5} + C) - (\frac{1}{2} \int \frac{1}{x} d x) + \int e^{x} d x + \int 2021 d x$

Step 11.2

Combine $\frac{1}{5}$ and $x^{5}$ .

$\frac{2}{7} x^{\frac{7}{2}} + C - 3 (\frac{3 x^{\frac{4}{3}}}{4} + C) + 5 (\frac{x^{5}}{5} + C) - (\frac{1}{2} \int \frac{1}{x} d x) + \int e^{x} d x + \int 2021 d x$

Step 12

The integral of $\frac{1}{x}$ with respect to $x$ is $\ln (| x |)$ .

$\frac{2}{7} x^{\frac{7}{2}} + C - 3 (\frac{3 x^{\frac{4}{3}}}{4} + C) + 5 (\frac{x^{5}}{5} + C) - (\frac{1}{2} (\ln (| x |) + C)) + \int e^{x} d x + \int 2021 d x$

Step 13

The integral of $e^{x}$ with respect to $x$ is $e^{x}$ .

$\frac{2}{7} x^{\frac{7}{2}} + C - 3 (\frac{3 x^{\frac{4}{3}}}{4} + C) + 5 (\frac{x^{5}}{5} + C) - \frac{1}{2} (\ln (| x |) + C) + e^{x} + C + \int 2021 d x$

Step 14

Apply the constant rule.

$\frac{2}{7} x^{\frac{7}{2}} + C - 3 (\frac{3 x^{\frac{4}{3}}}{4} + C) + 5 (\frac{x^{5}}{5} + C) - \frac{1}{2} (\ln (| x |) + C) + e^{x} + C + 2021 x + C$

Step 15

Simplify.

$\frac{2 x^{\frac{7}{2}}}{7} - \frac{9 x^{\frac{4}{3}}}{4} + x^{5} - \frac{\ln (| x |)}{2} + e^{x} + 2021 x + C$

Step 16

Reorder terms.

$\frac{2}{7} x^{\frac{7}{2}} - \frac{9}{4} x^{\frac{4}{3}} + x^{5} - \frac{1}{2} \ln (| x |) + e^{x} + 2021 x + C$