Calculus Examples

Find the Derivative - d/dx y^(xy)
yxyyxy
Step 1
Differentiate using the Generalized Power Rule which states that ddx[fg]ddx[fg] is fg(fgf+gln(f)) where f=y and g=xy.
ddx[y](xyyxy-1)+ddx[xy](yxyln(y))
Step 2
Multiply y by yxy-1 by adding the exponents.
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Step 2.1
Move yxy-1.
ddx[y](x(yxy-1y))+ddx[xy](yxyln(y))
Step 2.2
Multiply yxy-1 by y.
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Step 2.2.1
Raise y to the power of 1.
ddx[y](x(yxy-1y1))+ddx[xy](yxyln(y))
Step 2.2.2
Use the power rule aman=am+n to combine exponents.
ddx[y](xyxy-1+1)+ddx[xy](yxyln(y))
ddx[y](xyxy-1+1)+ddx[xy](yxyln(y))
Step 2.3
Combine the opposite terms in xy-1+1.
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Step 2.3.1
Add -1 and 1.
ddx[y](xyxy+0)+ddx[xy](yxyln(y))
Step 2.3.2
Add xy and 0.
ddx[y](xyxy)+ddx[xy](yxyln(y))
ddx[y](xyxy)+ddx[xy](yxyln(y))
ddx[y](xyxy)+ddx[xy](yxyln(y))
Step 3
Since y is constant with respect to x, the derivative of y with respect to x is 0.
0(xyxy)+ddx[xy](yxyln(y))
Step 4
Simplify the expression.
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Step 4.1
Multiply x by 0.
0yxy+ddx[xy](yxyln(y))
Step 4.2
Multiply 0 by yxy.
0+ddx[xy](yxyln(y))
Step 4.3
Add 0 and ddx[xy](yxyln(y)).
ddx[xy](yxyln(y))
ddx[xy](yxyln(y))
Step 5
Since y is constant with respect to x, the derivative of xy with respect to x is yddx[x].
yddx[x](yxyln(y))
Step 6
Raise y to the power of 1.
yxyy1ddx[x]ln(y)
Step 7
Use the power rule aman=am+n to combine exponents.
yxy+1ddx[x]ln(y)
Step 8
Differentiate using the Power Rule which states that ddx[xn] is nxn-1 where n=1.
yxy+11ln(y)
Step 9
Multiply yxy+1 by 1.
yxy+1ln(y)
 [x2  12  π  xdx ]