Calculus Examples

$3 \csc (2 x)$

Step 1

Since $3$ is constant with respect to $x$ , the derivative of $3 \csc (2 x)$ with respect to $x$ is $3 \frac{d}{d x} [\csc (2 x)]$ .

$3 \frac{d}{d x} [\csc (2 x)]$

Step 2

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = \csc (x)$ and $g (x) = 2 x$ .

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Step 2.1

To apply the Chain Rule, set $u$ as $2 x$ .

$3 (\frac{d}{d u} [\csc (u)] \frac{d}{d x} [2 x])$

Step 2.2

The derivative of $\csc (u)$ with respect to $u$ is $- \csc (u) \cot (u)$ .

$3 (- \csc (u) \cot (u) \frac{d}{d x} [2 x])$

Step 2.3

Replace all occurrences of $u$ with $2 x$ .

$3 (- \csc (2 x) \cot (2 x) \frac{d}{d x} [2 x])$

Step 3

Differentiate.

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Step 3.1

Multiply $- 1$ by $3$ .

$- 3 (\csc (2 x) \cot (2 x) \frac{d}{d x} [2 x])$

Step 3.2

Since $2$ is constant with respect to $x$ , the derivative of $2 x$ with respect to $x$ is $2 \frac{d}{d x} [x]$ .

$- 3 \csc (2 x) \cot (2 x) (2 \frac{d}{d x} [x])$

Step 3.3

Multiply $2$ by $- 3$ .

$- 6 \csc (2 x) \cot (2 x) \frac{d}{d x} [x]$

Step 3.4

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$- 6 \csc (2 x) \cot (2 x) \cdot 1$

Step 3.5

Simplify the expression.

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Step 3.5.1

Multiply $- 6$ by $1$ .

$- 6 \csc (2 x) \cot (2 x)$

Step 3.5.2

Reorder the factors of $- 6 \csc (2 x) \cot (2 x)$ .

$- 6 \cot (2 x) \csc (2 x)$