Calculus Examples

$e^{2 x} + 1$

Step 1

Write $e^{2 x} + 1$ as a function.

$f (x) = e^{2 x} + 1$

Step 2

The function $F (x)$ can be found by finding the indefinite integral of the derivative $f (x)$ .

$F (x) = \int f (x) d x$

Step 3

Set up the integral to solve.

$F (x) = \int e^{2 x} + 1 d x$

Step 4

Split the single integral into multiple integrals.

$\int e^{2 x} d x + \int d x$

Step 5

Let $u = 2 x$ . Then $d u = 2 d x$ , so $\frac{1}{2} d u = d x$ . Rewrite using $u$ and $d$ $u$ .

Tap for more steps...

Step 5.1

Let $u = 2 x$ . Find $\frac{d u}{d x}$ .

Tap for more steps...

Step 5.1.1

Differentiate $2 x$ .

$\frac{d}{d x} [2 x]$

Step 5.1.2

Since $2$ is constant with respect to $x$ , the derivative of $2 x$ with respect to $x$ is $2 \frac{d}{d x} [x]$ .

$2 \frac{d}{d x} [x]$

Step 5.1.3

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$2 \cdot 1$

Step 5.1.4

Multiply $2$ by $1$ .

$2$

Step 5.2

Rewrite the problem using $u$ and $d u$ .

$\int e^{u} \frac{1}{2} d u + \int d x$

Step 6

Combine $e^{u}$ and $\frac{1}{2}$ .

$\int \frac{e^{u}}{2} d u + \int d x$

Step 7

Since $\frac{1}{2}$ is constant with respect to $u$ , move $\frac{1}{2}$ out of the integral.

$\frac{1}{2} \int e^{u} d u + \int d x$

Step 8

The integral of $e^{u}$ with respect to $u$ is $e^{u}$ .

$\frac{1}{2} (e^{u} + C) + \int d x$

Step 9

Apply the constant rule.

$\frac{1}{2} (e^{u} + C) + x + C$

Step 10

Simplify.

$\frac{1}{2} e^{u} + x + C$

Step 11

Replace all occurrences of $u$ with $2 x$ .

$\frac{1}{2} e^{2 x} + x + C$

Step 12

The answer is the antiderivative of the function $f (x) = e^{2 x} + 1$ .

$F (x) =$ $\frac{1}{2} e^{2 x} + x + C$