Calculus Examples

$1 + \cos^{2} (x)$

Step 1

Write $1 + \cos^{2} (x)$ as a function.

$f (x) = 1 + \cos^{2} (x)$

Step 2

The function $F (x)$ can be found by finding the indefinite integral of the derivative $f (x)$ .

$F (x) = \int f (x) d x$

Step 3

Set up the integral to solve.

$F (x) = \int 1 + \cos^{2} (x) d x$

Step 4

Split the single integral into multiple integrals.

$\int d x + \int \cos^{2} (x) d x$

Step 5

Apply the constant rule.

$x + C + \int \cos^{2} (x) d x$

Step 6

Use the half-angle formula to rewrite $\cos^{2} (x)$ as $\frac{1 + \cos (2 x)}{2}$ .

$x + C + \int \frac{1 + \cos (2 x)}{2} d x$

Step 7

Since $\frac{1}{2}$ is constant with respect to $x$ , move $\frac{1}{2}$ out of the integral.

$x + C + \frac{1}{2} \int 1 + \cos (2 x) d x$

Step 8

Split the single integral into multiple integrals.

$x + C + \frac{1}{2} (\int d x + \int \cos (2 x) d x)$

Step 9

Apply the constant rule.

$x + C + \frac{1}{2} (x + C + \int \cos (2 x) d x)$

Step 10

Let $u = 2 x$ . Then $d u = 2 d x$ , so $\frac{1}{2} d u = d x$ . Rewrite using $u$ and $d$ $u$ .

Tap for more steps...

Step 10.1

Let $u = 2 x$ . Find $\frac{d u}{d x}$ .

Tap for more steps...

Step 10.1.1

Differentiate $2 x$ .

$\frac{d}{d x} [2 x]$

Step 10.1.2

Since $2$ is constant with respect to $x$ , the derivative of $2 x$ with respect to $x$ is $2 \frac{d}{d x} [x]$ .

$2 \frac{d}{d x} [x]$

Step 10.1.3

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$2 \cdot 1$

Step 10.1.4

Multiply $2$ by $1$ .

$2$

Step 10.2

Rewrite the problem using $u$ and $d u$ .

$x + C + \frac{1}{2} (x + C + \int \cos (u) \frac{1}{2} d u)$

Step 11

Combine $\cos (u)$ and $\frac{1}{2}$ .

$x + C + \frac{1}{2} (x + C + \int \frac{\cos (u)}{2} d u)$

Step 12

Since $\frac{1}{2}$ is constant with respect to $u$ , move $\frac{1}{2}$ out of the integral.

$x + C + \frac{1}{2} (x + C + \frac{1}{2} \int \cos (u) d u)$

Step 13

The integral of $\cos (u)$ with respect to $u$ is $\sin (u)$ .

$x + C + \frac{1}{2} (x + C + \frac{1}{2} (\sin (u) + C))$

Step 14

Simplify.

$x + \frac{1}{2} (x + \frac{1}{2} \sin (u)) + C$

Step 15

Replace all occurrences of $u$ with $2 x$ .

$x + \frac{1}{2} (x + \frac{1}{2} \sin (2 x)) + C$

Step 16

Simplify.

Tap for more steps...

Step 16.1

Combine $\frac{1}{2}$ and $\sin (2 x)$ .

$x + \frac{1}{2} (x + \frac{\sin (2 x)}{2}) + C$

Step 16.2

Apply the distributive property.

$x + \frac{1}{2} x + \frac{1}{2} \cdot \frac{\sin (2 x)}{2} + C$

Step 16.3

Combine $\frac{1}{2}$ and $x$ .

$x + \frac{x}{2} + \frac{1}{2} \cdot \frac{\sin (2 x)}{2} + C$

Step 16.4

Multiply $\frac{1}{2} \cdot \frac{\sin (2 x)}{2}$ .

Tap for more steps...

Step 16.4.1

Multiply $\frac{1}{2}$ by $\frac{\sin (2 x)}{2}$ .

$x + \frac{x}{2} + \frac{\sin (2 x)}{2 \cdot 2} + C$

Step 16.4.2

Multiply $2$ by $2$ .

$x + \frac{x}{2} + \frac{\sin (2 x)}{4} + C$

Step 17

Reorder terms.

$x + \frac{1}{2} x + \frac{1}{4} \sin (2 x) + C$

Step 18

The answer is the antiderivative of the function $f (x) = 1 + \cos^{2} (x)$ .

$F (x) =$ $x + \frac{1}{2} x + \frac{1}{4} \sin (2 x) + C$