Calculus Examples

$\int_{1}^{2} (- 4 x^{\frac{3}{2}} + 2 \sqrt{x} - 4 x^{3}) d x$

Step 1

Remove parentheses.

$\int_{1}^{2} - 4 x^{\frac{3}{2}} + 2 \sqrt{x} - 4 x^{3} d x$

Step 2

Split the single integral into multiple integrals.

$\int_{1}^{2} - 4 x^{\frac{3}{2}} d x + \int_{1}^{2} 2 \sqrt{x} d x + \int_{1}^{2} - 4 x^{3} d x$

Step 3

Since $- 4$ is constant with respect to $x$ , move $- 4$ out of the integral.

$- 4 \int_{1}^{2} x^{\frac{3}{2}} d x + \int_{1}^{2} 2 \sqrt{x} d x + \int_{1}^{2} - 4 x^{3} d x$

Step 4

By the Power Rule, the integral of $x^{\frac{3}{2}}$ with respect to $x$ is $\frac{2}{5} x^{\frac{5}{2}}$ .

$- 4 (\frac{2}{5} x^{\frac{5}{2}}]_{1}^{2}) + \int_{1}^{2} 2 \sqrt{x} d x + \int_{1}^{2} - 4 x^{3} d x$

Step 5

Combine $\frac{2}{5}$ and $x^{\frac{5}{2}}$ .

$- 4 (\frac{2 x^{\frac{5}{2}}}{5}]_{1}^{2}) + \int_{1}^{2} 2 \sqrt{x} d x + \int_{1}^{2} - 4 x^{3} d x$

Step 6

Since $2$ is constant with respect to $x$ , move $2$ out of the integral.

$- 4 (\frac{2 x^{\frac{5}{2}}}{5}]_{1}^{2}) + 2 \int_{1}^{2} \sqrt{x} d x + \int_{1}^{2} - 4 x^{3} d x$

Step 7

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{x}$ as $x^{\frac{1}{2}}$ .

$- 4 (\frac{2 x^{\frac{5}{2}}}{5}]_{1}^{2}) + 2 \int_{1}^{2} x^{\frac{1}{2}} d x + \int_{1}^{2} - 4 x^{3} d x$

Step 8

By the Power Rule, the integral of $x^{\frac{1}{2}}$ with respect to $x$ is $\frac{2}{3} x^{\frac{3}{2}}$ .

$- 4 (\frac{2 x^{\frac{5}{2}}}{5}]_{1}^{2}) + 2 (\frac{2}{3} x^{\frac{3}{2}}]_{1}^{2}) + \int_{1}^{2} - 4 x^{3} d x$

Step 9

Combine $\frac{2}{3}$ and $x^{\frac{3}{2}}$ .

$- 4 (\frac{2 x^{\frac{5}{2}}}{5}]_{1}^{2}) + 2 (\frac{2 x^{\frac{3}{2}}}{3}]_{1}^{2}) + \int_{1}^{2} - 4 x^{3} d x$

Step 10

Since $- 4$ is constant with respect to $x$ , move $- 4$ out of the integral.

$- 4 (\frac{2 x^{\frac{5}{2}}}{5}]_{1}^{2}) + 2 (\frac{2 x^{\frac{3}{2}}}{3}]_{1}^{2}) - 4 \int_{1}^{2} x^{3} d x$

Step 11

By the Power Rule, the integral of $x^{3}$ with respect to $x$ is $\frac{1}{4} x^{4}$ .

$- 4 (\frac{2 x^{\frac{5}{2}}}{5}]_{1}^{2}) + 2 (\frac{2 x^{\frac{3}{2}}}{3}]_{1}^{2}) - 4 (\frac{1}{4} x^{4}]_{1}^{2})$

Step 12

Simplify the answer.

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Step 12.1

Combine $\frac{1}{4}$ and $x^{4}$ .

$- 4 (\frac{2 x^{\frac{5}{2}}}{5}]_{1}^{2}) + 2 (\frac{2 x^{\frac{3}{2}}}{3}]_{1}^{2}) - 4 (\frac{x^{4}}{4}]_{1}^{2})$

Step 12.2

Substitute and simplify.

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Step 12.2.1

Evaluate $\frac{2 x^{\frac{5}{2}}}{5}$ at $2$ and at $1$ .

$- 4 ((\frac{2 \cdot 2^{\frac{5}{2}}}{5}) - \frac{2 \cdot 1^{\frac{5}{2}}}{5}) + 2 (\frac{2 x^{\frac{3}{2}}}{3}]_{1}^{2}) - 4 (\frac{x^{4}}{4}]_{1}^{2})$

Step 12.2.2

Evaluate $\frac{2 x^{\frac{3}{2}}}{3}$ at $2$ and at $1$ .

$- 4 (\frac{2 \cdot 2^{\frac{5}{2}}}{5} - \frac{2 \cdot 1^{\frac{5}{2}}}{5}) + 2 (\frac{2 \cdot 2^{\frac{3}{2}}}{3} - \frac{2 \cdot 1^{\frac{3}{2}}}{3}) - 4 (\frac{x^{4}}{4}]_{1}^{2})$

Step 12.2.3

Evaluate $\frac{x^{4}}{4}$ at $2$ and at $1$ .

$- 4 (\frac{2 \cdot 2^{\frac{5}{2}}}{5} - \frac{2 \cdot 1^{\frac{5}{2}}}{5}) + 2 (\frac{2 \cdot 2^{\frac{3}{2}}}{3} - \frac{2 \cdot 1^{\frac{3}{2}}}{3}) - 4 ((\frac{2^{4}}{4}) - \frac{1^{4}}{4})$

Step 12.2.4

Simplify.

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Step 12.2.4.1

Multiply $2$ by $2^{\frac{5}{2}}$ by adding the exponents.

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Step 12.2.4.1.1

Multiply $2$ by $2^{\frac{5}{2}}$ .

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Step 12.2.4.1.1.1

Raise $2$ to the power of $1$ .

$- 4 (\frac{2^{1} \cdot 2^{\frac{5}{2}}}{5} - \frac{2 \cdot 1^{\frac{5}{2}}}{5}) + 2 (\frac{2 \cdot 2^{\frac{3}{2}}}{3} - \frac{2 \cdot 1^{\frac{3}{2}}}{3}) - 4 ((\frac{2^{4}}{4}) - \frac{1^{4}}{4})$

Step 12.2.4.1.1.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$- 4 (\frac{2^{1 + \frac{5}{2}}}{5} - \frac{2 \cdot 1^{\frac{5}{2}}}{5}) + 2 (\frac{2 \cdot 2^{\frac{3}{2}}}{3} - \frac{2 \cdot 1^{\frac{3}{2}}}{3}) - 4 ((\frac{2^{4}}{4}) - \frac{1^{4}}{4})$

Step 12.2.4.1.2

Write $1$ as a fraction with a common denominator.

$- 4 (\frac{2^{\frac{2}{2} + \frac{5}{2}}}{5} - \frac{2 \cdot 1^{\frac{5}{2}}}{5}) + 2 (\frac{2 \cdot 2^{\frac{3}{2}}}{3} - \frac{2 \cdot 1^{\frac{3}{2}}}{3}) - 4 ((\frac{2^{4}}{4}) - \frac{1^{4}}{4})$

Step 12.2.4.1.3

Combine the numerators over the common denominator.

$- 4 (\frac{2^{\frac{2 + 5}{2}}}{5} - \frac{2 \cdot 1^{\frac{5}{2}}}{5}) + 2 (\frac{2 \cdot 2^{\frac{3}{2}}}{3} - \frac{2 \cdot 1^{\frac{3}{2}}}{3}) - 4 ((\frac{2^{4}}{4}) - \frac{1^{4}}{4})$

Step 12.2.4.1.4

Add $2$ and $5$ .

$- 4 (\frac{2^{\frac{7}{2}}}{5} - \frac{2 \cdot 1^{\frac{5}{2}}}{5}) + 2 (\frac{2 \cdot 2^{\frac{3}{2}}}{3} - \frac{2 \cdot 1^{\frac{3}{2}}}{3}) - 4 ((\frac{2^{4}}{4}) - \frac{1^{4}}{4})$

Step 12.2.4.2

One to any power is one.

$- 4 (\frac{2^{\frac{7}{2}}}{5} - \frac{2 \cdot 1}{5}) + 2 (\frac{2 \cdot 2^{\frac{3}{2}}}{3} - \frac{2 \cdot 1^{\frac{3}{2}}}{3}) - 4 ((\frac{2^{4}}{4}) - \frac{1^{4}}{4})$

Step 12.2.4.3

Multiply $2$ by $1$ .

$- 4 (\frac{2^{\frac{7}{2}}}{5} - \frac{2}{5}) + 2 (\frac{2 \cdot 2^{\frac{3}{2}}}{3} - \frac{2 \cdot 1^{\frac{3}{2}}}{3}) - 4 ((\frac{2^{4}}{4}) - \frac{1^{4}}{4})$

Step 12.2.4.4

Combine the numerators over the common denominator.

$- 4 \frac{2^{\frac{7}{2}} - 2}{5} + 2 (\frac{2 \cdot 2^{\frac{3}{2}}}{3} - \frac{2 \cdot 1^{\frac{3}{2}}}{3}) - 4 ((\frac{2^{4}}{4}) - \frac{1^{4}}{4})$

Step 12.2.4.5

Combine $- 4$ and $\frac{2^{\frac{7}{2}} - 2}{5}$ .

$\frac{- 4 (2^{\frac{7}{2}} - 2)}{5} + 2 (\frac{2 \cdot 2^{\frac{3}{2}}}{3} - \frac{2 \cdot 1^{\frac{3}{2}}}{3}) - 4 ((\frac{2^{4}}{4}) - \frac{1^{4}}{4})$

Step 12.2.4.6

Move the negative in front of the fraction.

$- \frac{4 (2^{\frac{7}{2}} - 2)}{5} + 2 (\frac{2 \cdot 2^{\frac{3}{2}}}{3} - \frac{2 \cdot 1^{\frac{3}{2}}}{3}) - 4 ((\frac{2^{4}}{4}) - \frac{1^{4}}{4})$

Step 12.2.4.7

Multiply $2$ by $2^{\frac{3}{2}}$ by adding the exponents.

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Step 12.2.4.7.1

Multiply $2$ by $2^{\frac{3}{2}}$ .

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Step 12.2.4.7.1.1

Raise $2$ to the power of $1$ .

$- \frac{4 (2^{\frac{7}{2}} - 2)}{5} + 2 (\frac{2^{1} \cdot 2^{\frac{3}{2}}}{3} - \frac{2 \cdot 1^{\frac{3}{2}}}{3}) - 4 ((\frac{2^{4}}{4}) - \frac{1^{4}}{4})$

Step 12.2.4.7.1.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$- \frac{4 (2^{\frac{7}{2}} - 2)}{5} + 2 (\frac{2^{1 + \frac{3}{2}}}{3} - \frac{2 \cdot 1^{\frac{3}{2}}}{3}) - 4 ((\frac{2^{4}}{4}) - \frac{1^{4}}{4})$

Step 12.2.4.7.2

Write $1$ as a fraction with a common denominator.

$- \frac{4 (2^{\frac{7}{2}} - 2)}{5} + 2 (\frac{2^{\frac{2}{2} + \frac{3}{2}}}{3} - \frac{2 \cdot 1^{\frac{3}{2}}}{3}) - 4 ((\frac{2^{4}}{4}) - \frac{1^{4}}{4})$

Step 12.2.4.7.3

Combine the numerators over the common denominator.

$- \frac{4 (2^{\frac{7}{2}} - 2)}{5} + 2 (\frac{2^{\frac{2 + 3}{2}}}{3} - \frac{2 \cdot 1^{\frac{3}{2}}}{3}) - 4 ((\frac{2^{4}}{4}) - \frac{1^{4}}{4})$

Step 12.2.4.7.4

Add $2$ and $3$ .

$- \frac{4 (2^{\frac{7}{2}} - 2)}{5} + 2 (\frac{2^{\frac{5}{2}}}{3} - \frac{2 \cdot 1^{\frac{3}{2}}}{3}) - 4 ((\frac{2^{4}}{4}) - \frac{1^{4}}{4})$

Step 12.2.4.8

One to any power is one.

$- \frac{4 (2^{\frac{7}{2}} - 2)}{5} + 2 (\frac{2^{\frac{5}{2}}}{3} - \frac{2 \cdot 1}{3}) - 4 ((\frac{2^{4}}{4}) - \frac{1^{4}}{4})$

Step 12.2.4.9

Multiply $2$ by $1$ .

$- \frac{4 (2^{\frac{7}{2}} - 2)}{5} + 2 (\frac{2^{\frac{5}{2}}}{3} - \frac{2}{3}) - 4 ((\frac{2^{4}}{4}) - \frac{1^{4}}{4})$

Step 12.2.4.10

Combine the numerators over the common denominator.

$- \frac{4 (2^{\frac{7}{2}} - 2)}{5} + 2 \frac{2^{\frac{5}{2}} - 2}{3} - 4 ((\frac{2^{4}}{4}) - \frac{1^{4}}{4})$

Step 12.2.4.11

Combine $2$ and $\frac{2^{\frac{5}{2}} - 2}{3}$ .

$- \frac{4 (2^{\frac{7}{2}} - 2)}{5} + \frac{2 (2^{\frac{5}{2}} - 2)}{3} - 4 ((\frac{2^{4}}{4}) - \frac{1^{4}}{4})$

Step 12.2.4.12

To write $- \frac{4 (2^{\frac{7}{2}} - 2)}{5}$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$- \frac{4 (2^{\frac{7}{2}} - 2)}{5} \cdot \frac{3}{3} + \frac{2 (2^{\frac{5}{2}} - 2)}{3} - 4 ((\frac{2^{4}}{4}) - \frac{1^{4}}{4})$

Step 12.2.4.13

To write $\frac{2 (2^{\frac{5}{2}} - 2)}{3}$ as a fraction with a common denominator, multiply by $\frac{5}{5}$ .

$- \frac{4 (2^{\frac{7}{2}} - 2)}{5} \cdot \frac{3}{3} + \frac{2 (2^{\frac{5}{2}} - 2)}{3} \cdot \frac{5}{5} - 4 ((\frac{2^{4}}{4}) - \frac{1^{4}}{4})$

Step 12.2.4.14

Write each expression with a common denominator of $15$ , by multiplying each by an appropriate factor of $1$ .

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Step 12.2.4.14.1

Multiply $\frac{4 (2^{\frac{7}{2}} - 2)}{5}$ by $\frac{3}{3}$ .

$- \frac{4 (2^{\frac{7}{2}} - 2) \cdot 3}{5 \cdot 3} + \frac{2 (2^{\frac{5}{2}} - 2)}{3} \cdot \frac{5}{5} - 4 ((\frac{2^{4}}{4}) - \frac{1^{4}}{4})$

Step 12.2.4.14.2

Multiply $5$ by $3$ .

$- \frac{4 (2^{\frac{7}{2}} - 2) \cdot 3}{15} + \frac{2 (2^{\frac{5}{2}} - 2)}{3} \cdot \frac{5}{5} - 4 ((\frac{2^{4}}{4}) - \frac{1^{4}}{4})$

Step 12.2.4.14.3

Multiply $\frac{2 (2^{\frac{5}{2}} - 2)}{3}$ by $\frac{5}{5}$ .

$- \frac{4 (2^{\frac{7}{2}} - 2) \cdot 3}{15} + \frac{2 (2^{\frac{5}{2}} - 2) \cdot 5}{3 \cdot 5} - 4 ((\frac{2^{4}}{4}) - \frac{1^{4}}{4})$

Step 12.2.4.14.4

Multiply $3$ by $5$ .

$- \frac{4 (2^{\frac{7}{2}} - 2) \cdot 3}{15} + \frac{2 (2^{\frac{5}{2}} - 2) \cdot 5}{15} - 4 ((\frac{2^{4}}{4}) - \frac{1^{4}}{4})$

Step 12.2.4.15

Combine the numerators over the common denominator.

$\frac{- 4 (2^{\frac{7}{2}} - 2) \cdot 3 + 2 (2^{\frac{5}{2}} - 2) \cdot 5}{15} - 4 ((\frac{2^{4}}{4}) - \frac{1^{4}}{4})$

Step 12.2.4.16

Multiply $3$ by $- 4$ .

$\frac{- 12 (2^{\frac{7}{2}} - 2) + 2 (2^{\frac{5}{2}} - 2) \cdot 5}{15} - 4 ((\frac{2^{4}}{4}) - \frac{1^{4}}{4})$

Step 12.2.4.17

Multiply $5$ by $2$ .

$\frac{- 12 (2^{\frac{7}{2}} - 2) + 10 (2^{\frac{5}{2}} - 2)}{15} - 4 ((\frac{2^{4}}{4}) - \frac{1^{4}}{4})$

Step 12.2.4.18

Raise $2$ to the power of $4$ .

$\frac{- 12 (2^{\frac{7}{2}} - 2) + 10 (2^{\frac{5}{2}} - 2)}{15} - 4 (\frac{16}{4} - \frac{1^{4}}{4})$

Step 12.2.4.19

Cancel the common factor of $16$ and $4$ .

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Step 12.2.4.19.1

Factor $4$ out of $16$ .

$\frac{- 12 (2^{\frac{7}{2}} - 2) + 10 (2^{\frac{5}{2}} - 2)}{15} - 4 (\frac{4 \cdot 4}{4} - \frac{1^{4}}{4})$

Step 12.2.4.19.2

Cancel the common factors.

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Step 12.2.4.19.2.1

Factor $4$ out of $4$ .

$\frac{- 12 (2^{\frac{7}{2}} - 2) + 10 (2^{\frac{5}{2}} - 2)}{15} - 4 (\frac{4 \cdot 4}{4 (1)} - \frac{1^{4}}{4})$

Step 12.2.4.19.2.2

Cancel the common factor.

$\frac{- 12 (2^{\frac{7}{2}} - 2) + 10 (2^{\frac{5}{2}} - 2)}{15} - 4 (\frac{4 \cdot 4}{4 \cdot 1} - \frac{1^{4}}{4})$

Step 12.2.4.19.2.3

Rewrite the expression.

$\frac{- 12 (2^{\frac{7}{2}} - 2) + 10 (2^{\frac{5}{2}} - 2)}{15} - 4 (\frac{4}{1} - \frac{1^{4}}{4})$

Step 12.2.4.19.2.4

Divide $4$ by $1$ .

$\frac{- 12 (2^{\frac{7}{2}} - 2) + 10 (2^{\frac{5}{2}} - 2)}{15} - 4 (4 - \frac{1^{4}}{4})$

Step 12.2.4.20

One to any power is one.

$\frac{- 12 (2^{\frac{7}{2}} - 2) + 10 (2^{\frac{5}{2}} - 2)}{15} - 4 (4 - \frac{1}{4})$

Step 12.2.4.21

To write $4$ as a fraction with a common denominator, multiply by $\frac{4}{4}$ .

$\frac{- 12 (2^{\frac{7}{2}} - 2) + 10 (2^{\frac{5}{2}} - 2)}{15} - 4 (4 \cdot \frac{4}{4} - \frac{1}{4})$

Step 12.2.4.22

Combine $4$ and $\frac{4}{4}$ .

$\frac{- 12 (2^{\frac{7}{2}} - 2) + 10 (2^{\frac{5}{2}} - 2)}{15} - 4 (\frac{4 \cdot 4}{4} - \frac{1}{4})$

Step 12.2.4.23

Combine the numerators over the common denominator.

$\frac{- 12 (2^{\frac{7}{2}} - 2) + 10 (2^{\frac{5}{2}} - 2)}{15} - 4 \frac{4 \cdot 4 - 1}{4}$

Step 12.2.4.24

Simplify the numerator.

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Step 12.2.4.24.1

Multiply $4$ by $4$ .

$\frac{- 12 (2^{\frac{7}{2}} - 2) + 10 (2^{\frac{5}{2}} - 2)}{15} - 4 \frac{16 - 1}{4}$

Step 12.2.4.24.2

Subtract $1$ from $16$ .

$\frac{- 12 (2^{\frac{7}{2}} - 2) + 10 (2^{\frac{5}{2}} - 2)}{15} - 4 (\frac{15}{4})$

Step 12.2.4.25

Combine $- 4$ and $\frac{15}{4}$ .

$\frac{- 12 (2^{\frac{7}{2}} - 2) + 10 (2^{\frac{5}{2}} - 2)}{15} + \frac{- 4 \cdot 15}{4}$

Step 12.2.4.26

Multiply $- 4$ by $15$ .

$\frac{- 12 (2^{\frac{7}{2}} - 2) + 10 (2^{\frac{5}{2}} - 2)}{15} + \frac{- 60}{4}$

Step 12.2.4.27

Cancel the common factor of $- 60$ and $4$ .

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Step 12.2.4.27.1

Factor $4$ out of $- 60$ .

$\frac{- 12 (2^{\frac{7}{2}} - 2) + 10 (2^{\frac{5}{2}} - 2)}{15} + \frac{4 \cdot - 15}{4}$

Step 12.2.4.27.2

Cancel the common factors.

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Step 12.2.4.27.2.1

Factor $4$ out of $4$ .

$\frac{- 12 (2^{\frac{7}{2}} - 2) + 10 (2^{\frac{5}{2}} - 2)}{15} + \frac{4 \cdot - 15}{4 (1)}$

Step 12.2.4.27.2.2

Cancel the common factor.

$\frac{- 12 (2^{\frac{7}{2}} - 2) + 10 (2^{\frac{5}{2}} - 2)}{15} + \frac{4 \cdot - 15}{4 \cdot 1}$

Step 12.2.4.27.2.3

Rewrite the expression.

$\frac{- 12 (2^{\frac{7}{2}} - 2) + 10 (2^{\frac{5}{2}} - 2)}{15} + \frac{- 15}{1}$

Step 12.2.4.27.2.4

Divide $- 15$ by $1$ .

$\frac{- 12 (2^{\frac{7}{2}} - 2) + 10 (2^{\frac{5}{2}} - 2)}{15} - 15$

Step 12.3

Simplify.

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Step 12.3.1

Simplify the numerator.

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Step 12.3.1.1

Apply the distributive property.

$\frac{- 12 \cdot 2^{\frac{7}{2}} - 12 \cdot - 2 + 10 (2^{\frac{5}{2}} - 2)}{15} - 15$

Step 12.3.1.2

Multiply $- 12$ by $- 2$ .

$\frac{- 12 \cdot 2^{\frac{7}{2}} + 24 + 10 (2^{\frac{5}{2}} - 2)}{15} - 15$

Step 12.3.1.3

Apply the distributive property.

$\frac{- 12 \cdot 2^{\frac{7}{2}} + 24 + 10 \cdot 2^{\frac{5}{2}} + 10 \cdot - 2}{15} - 15$

Step 12.3.1.4

Multiply $10$ by $- 2$ .

$\frac{- 12 \cdot 2^{\frac{7}{2}} + 24 + 10 \cdot 2^{\frac{5}{2}} - 20}{15} - 15$

Step 12.3.1.5

Subtract $20$ from $24$ .

$\frac{- 12 \cdot 2^{\frac{7}{2}} + 10 \cdot 2^{\frac{5}{2}} + 4}{15} - 15$

Step 12.3.2

To write $- 15$ as a fraction with a common denominator, multiply by $\frac{15}{15}$ .

$\frac{- 12 \cdot 2^{\frac{7}{2}} + 10 \cdot 2^{\frac{5}{2}} + 4}{15} - 15 \cdot \frac{15}{15}$

Step 12.3.3

Combine $- 15$ and $\frac{15}{15}$ .

$\frac{- 12 \cdot 2^{\frac{7}{2}} + 10 \cdot 2^{\frac{5}{2}} + 4}{15} + \frac{- 15 \cdot 15}{15}$

Step 12.3.4

Combine the numerators over the common denominator.

$\frac{- 12 \cdot 2^{\frac{7}{2}} + 10 \cdot 2^{\frac{5}{2}} + 4 - 15 \cdot 15}{15}$

Step 12.3.5

Simplify the numerator.

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Step 12.3.5.1

Multiply $- 15$ by $15$ .

$\frac{- 12 \cdot 2^{\frac{7}{2}} + 10 \cdot 2^{\frac{5}{2}} + 4 - 225}{15}$

Step 12.3.5.2

Subtract $225$ from $4$ .

$\frac{- 12 \cdot 2^{\frac{7}{2}} + 10 \cdot 2^{\frac{5}{2}} - 221}{15}$

Step 12.3.6

Factor $- 1$ out of $- 12 \cdot 2^{\frac{7}{2}}$ .

$\frac{- (12 \cdot 2^{\frac{7}{2}}) + 10 \cdot 2^{\frac{5}{2}} - 221}{15}$

Step 12.3.7

Factor $- 1$ out of $10 \cdot 2^{\frac{5}{2}}$ .

$\frac{- (12 \cdot 2^{\frac{7}{2}}) - (- 10 \cdot 2^{\frac{5}{2}}) - 221}{15}$

Step 12.3.8

Factor $- 1$ out of $- (12 \cdot 2^{\frac{7}{2}}) - (- 10 \cdot 2^{\frac{5}{2}})$ .

$\frac{- (12 \cdot 2^{\frac{7}{2}} - 10 \cdot 2^{\frac{5}{2}}) - 221}{15}$

Step 12.3.9

Rewrite $- 221$ as $- 1 (221)$ .

$\frac{- (12 \cdot 2^{\frac{7}{2}} - 10 \cdot 2^{\frac{5}{2}}) - 1 (221)}{15}$

Step 12.3.10

Factor $- 1$ out of $- (12 \cdot 2^{\frac{7}{2}} - 10 \cdot 2^{\frac{5}{2}}) - 1 (221)$ .

$\frac{- (12 \cdot 2^{\frac{7}{2}} - 10 \cdot 2^{\frac{5}{2}} + 221)}{15}$

Step 12.3.11

Rewrite $- (12 \cdot 2^{\frac{7}{2}} - 10 \cdot 2^{\frac{5}{2}} + 221)$ as $- 1 (12 \cdot 2^{\frac{7}{2}} - 10 \cdot 2^{\frac{5}{2}} + 221)$ .

$\frac{- 1 (12 \cdot 2^{\frac{7}{2}} - 10 \cdot 2^{\frac{5}{2}} + 221)}{15}$

Step 12.3.12

Move the negative in front of the fraction.

$- \frac{12 \cdot 2^{\frac{7}{2}} - 10 \cdot 2^{\frac{5}{2}} + 221}{15}$

Step 13

The result can be shown in multiple forms.

Exact Form:

$- \frac{12 \cdot 2^{\frac{7}{2}} - 10 \cdot 2^{\frac{5}{2}} + 221}{15}$

Decimal Form:

$- 20.01306396 \dots$

Step 14