Calculus Examples

$\frac{d}{d x} (\arctan (3 x))$

Step 1

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = \arctan (x)$ and $g (x) = 3 x$ .

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Step 1.1

To apply the Chain Rule, set $u$ as $3 x$ .

$\frac{d}{d u} [\arctan (u)] \frac{d}{d x} [3 x]$

Step 1.2

The derivative of $\arctan (u)$ with respect to $u$ is $\frac{1}{1 + u^{2}}$ .

$\frac{1}{1 + u^{2}} \frac{d}{d x} [3 x]$

Step 1.3

Replace all occurrences of $u$ with $3 x$ .

$\frac{1}{1 + {(3 x)}^{2}} \frac{d}{d x} [3 x]$

Step 2

Differentiate.

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Step 2.1

Factor $3$ out of $3 x$ .

$\frac{1}{1 + {(3 (x))}^{2}} \frac{d}{d x} [3 x]$

Step 2.2

Simplify the expression.

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Step 2.2.1

Apply the product rule to $3 (x)$ .

$\frac{1}{1 + 3^{2} x^{2}} \frac{d}{d x} [3 x]$

Step 2.2.2

Raise $3$ to the power of $2$ .

$\frac{1}{1 + 9 x^{2}} \frac{d}{d x} [3 x]$

Step 2.3

Since $3$ is constant with respect to $x$ , the derivative of $3 x$ with respect to $x$ is $3 \frac{d}{d x} [x]$ .

$\frac{1}{1 + 9 x^{2}} (3 \frac{d}{d x} [x])$

Step 2.4

Combine $3$ and $\frac{1}{1 + 9 x^{2}}$ .

$\frac{3}{1 + 9 x^{2}} \frac{d}{d x} [x]$

Step 2.5

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$\frac{3}{1 + 9 x^{2}} \cdot 1$

Step 2.6

Simplify the expression.

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Step 2.6.1

Multiply $\frac{3}{1 + 9 x^{2}}$ by $1$ .

$\frac{3}{1 + 9 x^{2}}$

Step 2.6.2

Reorder terms.

$\frac{3}{9 x^{2} + 1}$