Calculus Examples

$y = - 3 \sqrt{x + 1} + 4$

Step 1

Find the first derivative of the function.

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Step 1.1

By the Sum Rule, the derivative of $- 3 \sqrt{x + 1} + 4$ with respect to $x$ is $\frac{d}{d x} [- 3 \sqrt{x + 1}] + \frac{d}{d x} [4]$ .

$\frac{d}{d x} [- 3 \sqrt{x + 1}] + \frac{d}{d x} [4]$

Step 1.2

Evaluate $\frac{d}{d x} [- 3 \sqrt{x + 1}]$ .

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Step 1.2.1

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{x + 1}$ as ${(x + 1)}^{\frac{1}{2}}$ .

$\frac{d}{d x} [- 3 {(x + 1)}^{\frac{1}{2}}] + \frac{d}{d x} [4]$

Step 1.2.2

Since $- 3$ is constant with respect to $x$ , the derivative of $- 3 {(x + 1)}^{\frac{1}{2}}$ with respect to $x$ is $- 3 \frac{d}{d x} [{(x + 1)}^{\frac{1}{2}}]$ .

$- 3 \frac{d}{d x} [{(x + 1)}^{\frac{1}{2}}] + \frac{d}{d x} [4]$

Step 1.2.3

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = x^{\frac{1}{2}}$ and $g (x) = x + 1$ .

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Step 1.2.3.1

To apply the Chain Rule, set $u$ as $x + 1$ .

$- 3 (\frac{d}{d u} [u^{\frac{1}{2}}] \frac{d}{d x} [x + 1]) + \frac{d}{d x} [4]$

Step 1.2.3.2

Differentiate using the Power Rule which states that $\frac{d}{d u} [u^{n}]$ is $n u^{n - 1}$ where $n = \frac{1}{2}$ .

$- 3 (\frac{1}{2} u^{\frac{1}{2} - 1} \frac{d}{d x} [x + 1]) + \frac{d}{d x} [4]$

Step 1.2.3.3

Replace all occurrences of $u$ with $x + 1$ .

$- 3 (\frac{1}{2} {(x + 1)}^{\frac{1}{2} - 1} \frac{d}{d x} [x + 1]) + \frac{d}{d x} [4]$

Step 1.2.4

By the Sum Rule, the derivative of $x + 1$ with respect to $x$ is $\frac{d}{d x} [x] + \frac{d}{d x} [1]$ .

$- 3 (\frac{1}{2} {(x + 1)}^{\frac{1}{2} - 1} (\frac{d}{d x} [x] + \frac{d}{d x} [1])) + \frac{d}{d x} [4]$

Step 1.2.5

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$- 3 (\frac{1}{2} {(x + 1)}^{\frac{1}{2} - 1} (1 + \frac{d}{d x} [1])) + \frac{d}{d x} [4]$

Step 1.2.6

Since $1$ is constant with respect to $x$ , the derivative of $1$ with respect to $x$ is $0$ .

$- 3 (\frac{1}{2} {(x + 1)}^{\frac{1}{2} - 1} (1 + 0)) + \frac{d}{d x} [4]$

Step 1.2.7

To write $- 1$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$- 3 (\frac{1}{2} {(x + 1)}^{\frac{1}{2} - 1 \cdot \frac{2}{2}} (1 + 0)) + \frac{d}{d x} [4]$

Step 1.2.8

Combine $- 1$ and $\frac{2}{2}$ .

$- 3 (\frac{1}{2} {(x + 1)}^{\frac{1}{2} + \frac{- 1 \cdot 2}{2}} (1 + 0)) + \frac{d}{d x} [4]$

Step 1.2.9

Combine the numerators over the common denominator.

$- 3 (\frac{1}{2} {(x + 1)}^{\frac{1 - 1 \cdot 2}{2}} (1 + 0)) + \frac{d}{d x} [4]$

Step 1.2.10

Simplify the numerator.

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Step 1.2.10.1

Multiply $- 1$ by $2$ .

$- 3 (\frac{1}{2} {(x + 1)}^{\frac{1 - 2}{2}} (1 + 0)) + \frac{d}{d x} [4]$

Step 1.2.10.2

Subtract $2$ from $1$ .

$- 3 (\frac{1}{2} {(x + 1)}^{\frac{- 1}{2}} (1 + 0)) + \frac{d}{d x} [4]$

Step 1.2.11

Move the negative in front of the fraction.

$- 3 (\frac{1}{2} {(x + 1)}^{- \frac{1}{2}} (1 + 0)) + \frac{d}{d x} [4]$

Step 1.2.12

Add $1$ and $0$ .

$- 3 (\frac{1}{2} {(x + 1)}^{- \frac{1}{2}} \cdot 1) + \frac{d}{d x} [4]$

Step 1.2.13

Combine $\frac{1}{2}$ and ${(x + 1)}^{- \frac{1}{2}}$ .

$- 3 (\frac{{(x + 1)}^{- \frac{1}{2}}}{2} \cdot 1) + \frac{d}{d x} [4]$

Step 1.2.14

Multiply $\frac{{(x + 1)}^{- \frac{1}{2}}}{2}$ by $1$ .

$- 3 \frac{{(x + 1)}^{- \frac{1}{2}}}{2} + \frac{d}{d x} [4]$

Step 1.2.15

Move ${(x + 1)}^{- \frac{1}{2}}$ to the denominator using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$- 3 \frac{1}{2 {(x + 1)}^{\frac{1}{2}}} + \frac{d}{d x} [4]$

Step 1.2.16

Combine $- 3$ and $\frac{1}{2 {(x + 1)}^{\frac{1}{2}}}$ .

$\frac{- 3}{2 {(x + 1)}^{\frac{1}{2}}} + \frac{d}{d x} [4]$

Step 1.2.17

Move the negative in front of the fraction.

$- \frac{3}{2 {(x + 1)}^{\frac{1}{2}}} + \frac{d}{d x} [4]$

Step 1.3

Differentiate using the Constant Rule.

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Step 1.3.1

Since $4$ is constant with respect to $x$ , the derivative of $4$ with respect to $x$ is $0$ .

$- \frac{3}{2 {(x + 1)}^{\frac{1}{2}}} + 0$

Step 1.3.2

Add $- \frac{3}{2 {(x + 1)}^{\frac{1}{2}}}$ and $0$ .

$- \frac{3}{2 {(x + 1)}^{\frac{1}{2}}}$

Step 2

Find the second derivative of the function.

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Step 2.1

Differentiate using the Constant Multiple Rule.

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Step 2.1.1

Since $- \frac{3}{2}$ is constant with respect to $x$ , the derivative of $- \frac{3}{2 {(x + 1)}^{\frac{1}{2}}}$ with respect to $x$ is $- \frac{3}{2} \frac{d}{d x} [\frac{1}{{(x + 1)}^{\frac{1}{2}}}]$ .

$f'' (x) = - \frac{3}{2} \cdot \frac{d}{d x} \frac{1}{{(x + 1)}^{\frac{1}{2}}}$

Step 2.1.2

Apply basic rules of exponents.

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Step 2.1.2.1

Rewrite $\frac{1}{{(x + 1)}^{\frac{1}{2}}}$ as ${({(x + 1)}^{\frac{1}{2}})}^{- 1}$ .

$f'' (x) = - \frac{3}{2} \cdot \frac{d}{d x} {({(x + 1)}^{\frac{1}{2}})}^{- 1}$

Step 2.1.2.2

Multiply the exponents in ${({(x + 1)}^{\frac{1}{2}})}^{- 1}$ .

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Step 2.1.2.2.1

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$f'' (x) = - \frac{3}{2} \cdot \frac{d}{d x} {(x + 1)}^{\frac{1}{2} \cdot - 1}$

Step 2.1.2.2.2

Combine $\frac{1}{2}$ and $- 1$ .

$f'' (x) = - \frac{3}{2} \cdot \frac{d}{d x} {(x + 1)}^{\frac{- 1}{2}}$

Step 2.1.2.2.3

Move the negative in front of the fraction.

$f'' (x) = - \frac{3}{2} \cdot \frac{d}{d x} {(x + 1)}^{- \frac{1}{2}}$

Step 2.2

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = x^{- \frac{1}{2}}$ and $g (x) = x + 1$ .

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Step 2.2.1

To apply the Chain Rule, set $u$ as $x + 1$ .

$f'' (x) = - \frac{3}{2} \cdot (\frac{d}{d u} (u^{- \frac{1}{2}}) \frac{d}{d x} (x + 1))$

Step 2.2.2

Differentiate using the Power Rule which states that $\frac{d}{d u} [u^{n}]$ is $n u^{n - 1}$ where $n = - \frac{1}{2}$ .

$f'' (x) = - \frac{3}{2} \cdot (- \frac{1}{2} u^{- \frac{1}{2} - 1} \frac{d}{d x} (x + 1))$

Step 2.2.3

Replace all occurrences of $u$ with $x + 1$ .

$f'' (x) = - \frac{3}{2} \cdot (- \frac{1}{2} \cdot {(x + 1)}^{- \frac{1}{2} - 1} \frac{d}{d x} (x + 1))$

Step 2.3

To write $- 1$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$f'' (x) = - \frac{3}{2} \cdot (- \frac{1}{2} \cdot {(x + 1)}^{- \frac{1}{2} - 1 \cdot \frac{2}{2}} \frac{d}{d x} (x + 1))$

Step 2.4

Combine $- 1$ and $\frac{2}{2}$ .

$f'' (x) = - \frac{3}{2} \cdot (- \frac{1}{2} \cdot {(x + 1)}^{- \frac{1}{2} + \frac{- 1 \cdot 2}{2}} \frac{d}{d x} (x + 1))$

Step 2.5

Combine the numerators over the common denominator.

$f'' (x) = - \frac{3}{2} \cdot (- \frac{1}{2} \cdot {(x + 1)}^{\frac{- 1 - 1 \cdot 2}{2}} \frac{d}{d x} (x + 1))$

Step 2.6

Simplify the numerator.

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Step 2.6.1

Multiply $- 1$ by $2$ .

$f'' (x) = - \frac{3}{2} \cdot (- \frac{1}{2} \cdot {(x + 1)}^{\frac{- 1 - 2}{2}} \frac{d}{d x} (x + 1))$

Step 2.6.2

Subtract $2$ from $- 1$ .

$f'' (x) = - \frac{3}{2} \cdot (- \frac{1}{2} \cdot {(x + 1)}^{\frac{- 3}{2}} \frac{d}{d x} (x + 1))$

Step 2.7

Combine fractions.

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Step 2.7.1

Move the negative in front of the fraction.

$f'' (x) = - \frac{3}{2} \cdot (- \frac{1}{2} \cdot {(x + 1)}^{- \frac{3}{2}} \frac{d}{d x} (x + 1))$

Step 2.7.2

Combine ${(x + 1)}^{- \frac{3}{2}}$ and $\frac{1}{2}$ .

$f'' (x) = - \frac{3}{2} \cdot (- \frac{{(x + 1)}^{- \frac{3}{2}}}{2} \cdot \frac{d}{d x} (x + 1))$

Step 2.7.3

Simplify the expression.

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Step 2.7.3.1

Move ${(x + 1)}^{- \frac{3}{2}}$ to the denominator using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$f'' (x) = - \frac{3}{2} \cdot (- \frac{1}{2 {(x + 1)}^{\frac{3}{2}}} \cdot \frac{d}{d x} (x + 1))$

Step 2.7.3.2

Multiply $- 1$ by $- 1$ .

$f'' (x) = 1 (\frac{3}{2}) \cdot (\frac{1}{2 {(x + 1)}^{\frac{3}{2}}} \cdot \frac{d}{d x} (x + 1))$

Step 2.7.3.3

Multiply $\frac{3}{2}$ by $1$ .

$f'' (x) = \frac{3}{2} \cdot (\frac{1}{2 {(x + 1)}^{\frac{3}{2}}} \cdot \frac{d}{d x} (x + 1))$

Step 2.7.4

Multiply $\frac{1}{2 {(x + 1)}^{\frac{3}{2}}}$ by $\frac{3}{2}$ .

$f'' (x) = \frac{3}{2 {(x + 1)}^{\frac{3}{2}} \cdot 2} \cdot \frac{d}{d x} (x + 1)$

Step 2.7.5

Multiply $2$ by $2$ .

$f'' (x) = \frac{3}{4 {(x + 1)}^{\frac{3}{2}}} \cdot \frac{d}{d x} (x + 1)$

Step 2.8

By the Sum Rule, the derivative of $x + 1$ with respect to $x$ is $\frac{d}{d x} [x] + \frac{d}{d x} [1]$ .

$f'' (x) = \frac{3}{4 {(x + 1)}^{\frac{3}{2}}} \cdot (\frac{d}{d x} (x) + \frac{d}{d x} (1))$

Step 2.9

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$f'' (x) = \frac{3}{4 {(x + 1)}^{\frac{3}{2}}} \cdot (1 + \frac{d}{d x} (1))$

Step 2.10

Since $1$ is constant with respect to $x$ , the derivative of $1$ with respect to $x$ is $0$ .

$f'' (x) = \frac{3}{4 {(x + 1)}^{\frac{3}{2}}} \cdot (1 + 0)$

Step 2.11

Simplify the expression.

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Step 2.11.1

Add $1$ and $0$ .

$f'' (x) = \frac{3}{4 {(x + 1)}^{\frac{3}{2}}} \cdot 1$

Step 2.11.2

Multiply $\frac{3}{4 {(x + 1)}^{\frac{3}{2}}}$ by $1$ .

$f'' (x) = \frac{3}{4 {(x + 1)}^{\frac{3}{2}}}$

Step 3

To find the local maximum and minimum values of the function, set the derivative equal to $0$ and solve.

$- \frac{3}{2 {(x + 1)}^{\frac{1}{2}}} = 0$

Step 4

Find the first derivative.

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Step 4.1

Find the first derivative.

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Step 4.1.1

By the Sum Rule, the derivative of $- 3 \sqrt{x + 1} + 4$ with respect to $x$ is $\frac{d}{d x} [- 3 \sqrt{x + 1}] + \frac{d}{d x} [4]$ .

$\frac{d}{d x} [- 3 \sqrt{x + 1}] + \frac{d}{d x} [4]$

Step 4.1.2

Evaluate $\frac{d}{d x} [- 3 \sqrt{x + 1}]$ .

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Step 4.1.2.1

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{x + 1}$ as ${(x + 1)}^{\frac{1}{2}}$ .

$\frac{d}{d x} [- 3 {(x + 1)}^{\frac{1}{2}}] + \frac{d}{d x} [4]$

Step 4.1.2.2

Since $- 3$ is constant with respect to $x$ , the derivative of $- 3 {(x + 1)}^{\frac{1}{2}}$ with respect to $x$ is $- 3 \frac{d}{d x} [{(x + 1)}^{\frac{1}{2}}]$ .

$- 3 \frac{d}{d x} [{(x + 1)}^{\frac{1}{2}}] + \frac{d}{d x} [4]$

Step 4.1.2.3

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = x^{\frac{1}{2}}$ and $g (x) = x + 1$ .

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Step 4.1.2.3.1

To apply the Chain Rule, set $u$ as $x + 1$ .

$- 3 (\frac{d}{d u} [u^{\frac{1}{2}}] \frac{d}{d x} [x + 1]) + \frac{d}{d x} [4]$

Step 4.1.2.3.2

Differentiate using the Power Rule which states that $\frac{d}{d u} [u^{n}]$ is $n u^{n - 1}$ where $n = \frac{1}{2}$ .

$- 3 (\frac{1}{2} u^{\frac{1}{2} - 1} \frac{d}{d x} [x + 1]) + \frac{d}{d x} [4]$

Step 4.1.2.3.3

Replace all occurrences of $u$ with $x + 1$ .

$- 3 (\frac{1}{2} {(x + 1)}^{\frac{1}{2} - 1} \frac{d}{d x} [x + 1]) + \frac{d}{d x} [4]$

Step 4.1.2.4

By the Sum Rule, the derivative of $x + 1$ with respect to $x$ is $\frac{d}{d x} [x] + \frac{d}{d x} [1]$ .

$- 3 (\frac{1}{2} {(x + 1)}^{\frac{1}{2} - 1} (\frac{d}{d x} [x] + \frac{d}{d x} [1])) + \frac{d}{d x} [4]$

Step 4.1.2.5

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$- 3 (\frac{1}{2} {(x + 1)}^{\frac{1}{2} - 1} (1 + \frac{d}{d x} [1])) + \frac{d}{d x} [4]$

Step 4.1.2.6

Since $1$ is constant with respect to $x$ , the derivative of $1$ with respect to $x$ is $0$ .

$- 3 (\frac{1}{2} {(x + 1)}^{\frac{1}{2} - 1} (1 + 0)) + \frac{d}{d x} [4]$

Step 4.1.2.7

To write $- 1$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$- 3 (\frac{1}{2} {(x + 1)}^{\frac{1}{2} - 1 \cdot \frac{2}{2}} (1 + 0)) + \frac{d}{d x} [4]$

Step 4.1.2.8

Combine $- 1$ and $\frac{2}{2}$ .

$- 3 (\frac{1}{2} {(x + 1)}^{\frac{1}{2} + \frac{- 1 \cdot 2}{2}} (1 + 0)) + \frac{d}{d x} [4]$

Step 4.1.2.9

Combine the numerators over the common denominator.

$- 3 (\frac{1}{2} {(x + 1)}^{\frac{1 - 1 \cdot 2}{2}} (1 + 0)) + \frac{d}{d x} [4]$

Step 4.1.2.10

Simplify the numerator.

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Step 4.1.2.10.1

Multiply $- 1$ by $2$ .

$- 3 (\frac{1}{2} {(x + 1)}^{\frac{1 - 2}{2}} (1 + 0)) + \frac{d}{d x} [4]$

Step 4.1.2.10.2

Subtract $2$ from $1$ .

$- 3 (\frac{1}{2} {(x + 1)}^{\frac{- 1}{2}} (1 + 0)) + \frac{d}{d x} [4]$

Step 4.1.2.11

Move the negative in front of the fraction.

$- 3 (\frac{1}{2} {(x + 1)}^{- \frac{1}{2}} (1 + 0)) + \frac{d}{d x} [4]$

Step 4.1.2.12

Add $1$ and $0$ .

$- 3 (\frac{1}{2} {(x + 1)}^{- \frac{1}{2}} \cdot 1) + \frac{d}{d x} [4]$

Step 4.1.2.13

Combine $\frac{1}{2}$ and ${(x + 1)}^{- \frac{1}{2}}$ .

$- 3 (\frac{{(x + 1)}^{- \frac{1}{2}}}{2} \cdot 1) + \frac{d}{d x} [4]$

Step 4.1.2.14

Multiply $\frac{{(x + 1)}^{- \frac{1}{2}}}{2}$ by $1$ .

$- 3 \frac{{(x + 1)}^{- \frac{1}{2}}}{2} + \frac{d}{d x} [4]$

Step 4.1.2.15

Move ${(x + 1)}^{- \frac{1}{2}}$ to the denominator using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$- 3 \frac{1}{2 {(x + 1)}^{\frac{1}{2}}} + \frac{d}{d x} [4]$

Step 4.1.2.16

Combine $- 3$ and $\frac{1}{2 {(x + 1)}^{\frac{1}{2}}}$ .

$\frac{- 3}{2 {(x + 1)}^{\frac{1}{2}}} + \frac{d}{d x} [4]$

Step 4.1.2.17

Move the negative in front of the fraction.

$- \frac{3}{2 {(x + 1)}^{\frac{1}{2}}} + \frac{d}{d x} [4]$

Step 4.1.3

Differentiate using the Constant Rule.

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Step 4.1.3.1

Since $4$ is constant with respect to $x$ , the derivative of $4$ with respect to $x$ is $0$ .

$- \frac{3}{2 {(x + 1)}^{\frac{1}{2}}} + 0$

Step 4.1.3.2

Add $- \frac{3}{2 {(x + 1)}^{\frac{1}{2}}}$ and $0$ .

$f' (x) = - \frac{3}{2 {(x + 1)}^{\frac{1}{2}}}$

Step 4.2

The first derivative of $f (x)$ with respect to $x$ is $- \frac{3}{2 {(x + 1)}^{\frac{1}{2}}}$ .

$- \frac{3}{2 {(x + 1)}^{\frac{1}{2}}}$

Step 5

Set the first derivative equal to $0$ then solve the equation $- \frac{3}{2 {(x + 1)}^{\frac{1}{2}}} = 0$ .

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Step 5.1

Set the first derivative equal to $0$ .

$- \frac{3}{2 {(x + 1)}^{\frac{1}{2}}} = 0$

Step 5.2

Set the numerator equal to zero.

$3 = 0$

Step 5.3

Since $3 \neq 0$ , there are no solutions.

No solution

Step 6

Find the values where the derivative is undefined.

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Step 6.1

Convert expressions with fractional exponents to radicals.

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Step 6.1.1

Apply the rule $x^{\frac{m}{n}} = \sqrt[n]{x^{m}}$ to rewrite the exponentiation as a radical.

$- \frac{3}{2 \sqrt{{(x + 1)}^{1}}}$

Step 6.1.2

Anything raised to $1$ is the base itself.

$- \frac{3}{2 \sqrt{x + 1}}$

Step 6.2

Set the denominator in $\frac{3}{2 \sqrt{x + 1}}$ equal to $0$ to find where the expression is undefined.

$2 \sqrt{x + 1} = 0$

Step 6.3

Solve for $x$ .

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Step 6.3.1

To remove the radical on the left side of the equation, square both sides of the equation.

${(2 \sqrt{x + 1})}^{2} = 0^{2}$

Step 6.3.2

Simplify each side of the equation.

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Step 6.3.2.1

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{x + 1}$ as ${(x + 1)}^{\frac{1}{2}}$ .

${(2 {(x + 1)}^{\frac{1}{2}})}^{2} = 0^{2}$

Step 6.3.2.2

Simplify the left side.

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Step 6.3.2.2.1

Simplify ${(2 {(x + 1)}^{\frac{1}{2}})}^{2}$ .

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Step 6.3.2.2.1.1

Apply the product rule to $2 {(x + 1)}^{\frac{1}{2}}$ .

$2^{2} {({(x + 1)}^{\frac{1}{2}})}^{2} = 0^{2}$

Step 6.3.2.2.1.2

Raise $2$ to the power of $2$ .

$4 {({(x + 1)}^{\frac{1}{2}})}^{2} = 0^{2}$

Step 6.3.2.2.1.3

Multiply the exponents in ${({(x + 1)}^{\frac{1}{2}})}^{2}$ .

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Step 6.3.2.2.1.3.1

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$4 {(x + 1)}^{\frac{1}{2} \cdot 2} = 0^{2}$

Step 6.3.2.2.1.3.2

Cancel the common factor of $2$ .

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Step 6.3.2.2.1.3.2.1

Cancel the common factor.

$4 {(x + 1)}^{\frac{1}{2} \cdot 2} = 0^{2}$

Step 6.3.2.2.1.3.2.2

Rewrite the expression.

$4 {(x + 1)}^{1} = 0^{2}$

Step 6.3.2.2.1.4

Simplify.

$4 (x + 1) = 0^{2}$

Step 6.3.2.2.1.5

Apply the distributive property.

$4 x + 4 \cdot 1 = 0^{2}$

Step 6.3.2.2.1.6

Multiply $4$ by $1$ .

$4 x + 4 = 0^{2}$

Step 6.3.2.3

Simplify the right side.

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Step 6.3.2.3.1

Raising $0$ to any positive power yields $0$ .

$4 x + 4 = 0$

Step 6.3.3

Solve for $x$ .

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Step 6.3.3.1

Subtract $4$ from both sides of the equation.

$4 x = - 4$

Step 6.3.3.2

Divide each term in $4 x = - 4$ by $4$ and simplify.

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Step 6.3.3.2.1

Divide each term in $4 x = - 4$ by $4$ .

$\frac{4 x}{4} = \frac{- 4}{4}$

Step 6.3.3.2.2

Simplify the left side.

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Step 6.3.3.2.2.1

Cancel the common factor of $4$ .

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Step 6.3.3.2.2.1.1

Cancel the common factor.

$\frac{4 x}{4} = \frac{- 4}{4}$

Step 6.3.3.2.2.1.2

Divide $x$ by $1$ .

$x = \frac{- 4}{4}$

Step 6.3.3.2.3

Simplify the right side.

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Step 6.3.3.2.3.1

Divide $- 4$ by $4$ .

$x = - 1$

Step 6.4

Set the radicand in $\sqrt{x + 1}$ less than $0$ to find where the expression is undefined.

$x + 1 < 0$

Step 6.5

Subtract $1$ from both sides of the inequality.

$x < - 1$

Step 6.6

The equation is undefined where the denominator equals $0$ , the argument of a square root is less than $0$ , or the argument of a logarithm is less than or equal to $0$ .

$x \leq - 1$

$(- \infty, - 1]$

$x \leq - 1$

$(- \infty, - 1]$

Step 7

Critical points to evaluate.

$x = - 1$

Step 8

Evaluate the second derivative at $x = - 1$ . If the second derivative is positive, then this is a local minimum. If it is negative, then this is a local maximum.

$\frac{3}{4 {((- 1) + 1)}^{\frac{3}{2}}}$

Step 9

Evaluate the second derivative.

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Step 9.1

Simplify the expression.

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Step 9.1.1

Add $- 1$ and $1$ .

$\frac{3}{4 \cdot 0^{\frac{3}{2}}}$

Step 9.1.2

Rewrite $0$ as $0^{2}$ .

$\frac{3}{4 \cdot {(0^{2})}^{\frac{3}{2}}}$

Step 9.1.3

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$\frac{3}{4 \cdot 0^{2 (\frac{3}{2})}}$

Step 9.2

Cancel the common factor of $2$ .

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Step 9.2.1

Cancel the common factor.

$\frac{3}{4 \cdot 0^{2 (\frac{3}{2})}}$

Step 9.2.2

Rewrite the expression.

$\frac{3}{4 \cdot 0^{3}}$

Step 9.3

Simplify the expression.

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Step 9.3.1

Raising $0$ to any positive power yields $0$ .

$\frac{3}{4 \cdot 0}$

Step 9.3.2

Multiply $4$ by $0$ .

$\frac{3}{0}$

Step 9.3.3

The expression contains a division by $0$ . The expression is undefined.

Undefined

$\frac{3}{0}$

Step 9.4

The expression contains a division by $0$ . The expression is undefined.

Undefined

Step 10

Since the first derivative test failed, there are no local extrema.

No Local Extrema

Step 11